ÌâÄ¿ÄÚÈÝ
(14·Ö) ÓÐA¡¢B¡¢C¡¢D¡¢E ÎåÖÖÔªËصÄÔ×ÓÐòÊýÒÀ´ÎÔö´ó£¬B¡¢C µÄÑôÀë×ÓÓëAµÄÒõÀë×ÓºÍÄÊÔ×ӵĵç×Ó²ã½á¹¹Ïàͬ£»A¡¢B¿ÉÐγÉÀë×Ó»¯ºÏÎïB2A£»CµÄÑõ»¯Îï¼ÈÄÜÓëÇ¿Ëá·´Ó¦£¬ÓÖÄÜÓëÇ¿¼î·´Ó¦£»DµÄÔ×ӽṹʾÒâͼΪ£º £»EµÄ×îÍâ²ãµç×ÓÊýÊǵç×Ó²ãÊýµÄ2±¶¡£ÊԻشðÏÂÁи÷ÎÊÌ⣺
£¨1£©B¡¢DÔªËØ·Ö±ðΪ ¡¢ £»
£¨2£©DÔªËØλÓÚÔªËØÖÜÆÚ±íÖÐµÚ ÖÜÆÚ¡¢µÚ ×壻
£¨3£©»¯ºÏÎïB2AµÄµç×Óʽ____________________£»
£¨4£©EµÄ×î¸ß¼ÛÑõ»¯ÎïµÄË®»¯ÎïµÄ·Ö×ÓʽÊÇ________________________¡£
£¨5£©DÓëNaOHÈÜÒº·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º_______________________________________¡£
£¨6£©CµÄÑõ»¯ÎïÓëEµÄ×î¸ß¼ÛÑõ»¯ÎïµÄË®»¯ÎïÈÜÒº·´Ó¦µÄÀë×Ó·½³Ìʽ£º
_______________________________________________________________________¡£
£¨1£©B¡¢DÔªËØ·Ö±ðΪ ¡¢ £»
£¨2£©DÔªËØλÓÚÔªËØÖÜÆÚ±íÖÐµÚ ÖÜÆÚ¡¢µÚ ×壻
£¨3£©»¯ºÏÎïB2AµÄµç×Óʽ____________________£»
£¨4£©EµÄ×î¸ß¼ÛÑõ»¯ÎïµÄË®»¯ÎïµÄ·Ö×ÓʽÊÇ________________________¡£
£¨5£©DÓëNaOHÈÜÒº·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º_______________________________________¡£
£¨6£©CµÄÑõ»¯ÎïÓëEµÄ×î¸ß¼ÛÑõ»¯ÎïµÄË®»¯ÎïÈÜÒº·´Ó¦µÄÀë×Ó·½³Ìʽ£º
_______________________________________________________________________¡£
£¨1£©B£ºNa £»D£ºSi £¨2·Ö£©
£¨2£©Èý IVA £¨2·Ö£©
£¨3£©£¨2·Ö£©
£¨4£©H2SO4 £¨2·Ö£©
£¨5£©Si + 2NaOH + H2O = Na2SiO3 + 2H2¡ü£¨3·Ö£©
£¨6£©Al2O3 + 6H£«= 2Al3£«+ 3H2O£¨3·Ö£©
£¨2£©Èý IVA £¨2·Ö£©
£¨3£©£¨2·Ö£©
£¨4£©H2SO4 £¨2·Ö£©
£¨5£©Si + 2NaOH + H2O = Na2SiO3 + 2H2¡ü£¨3·Ö£©
£¨6£©Al2O3 + 6H£«= 2Al3£«+ 3H2O£¨3·Ö£©
ÂÔ
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿