ÌâÄ¿ÄÚÈÝ

ij»¯Ñ§ÐËȤС×éÓÃÖ»º¬ÓÐÂÁ¡¢Ìú¡¢Í­µÄ¹¤Òµ·ÏÁÏÖÆÈ¡´¿¾»µÄÂÈ»¯ÂÁÈÜÒº¡¢ÂÌ·¯¾§Ìå(FeSO4¡¤7H2O)ºÍµ¨·¯¾§Ì壬ÒÔ̽Ë÷¹¤Òµ·ÏÁϵÄÔÙÀûÓá£ÆäʵÑé·½°¸ÈçÏ£º

£¨1£©Ð´³öºÏ½ðÓëÉÕ¼îÈÜÒº·´Ó¦µÄÀë×Ó·½³Ìʽ£º                                                 ¡£
£¨2£©ÓÉÂËÒºAÖÆAlCl3ÈÜÒºµÄ;¾¶ÓТٺ͢ÚÁ½ÖÖ£¬Í¾¾¶¢ÚÖÐͨÈëµÄijÆøÌ壨¹Ì̬ʱ¿ÉÓÃÓÚÈ˹¤½µÓ꣩£¬Ð´³ö¸ÃÆøÌåµÄµç×Óʽ     ¡£ÄãÈÏΪ½ÏºÏÀíµÄ;¾¶ÊÇ    £¨Ìî¢Ù»ò¢Ú£©£¬ÀíÓÉÊÇ£º                          ¡£
£¨3£©ÂËÒºEÈô·ÅÖÃÔÚ¿ÕÆøÖÐÒ»¶Îʱ¼äºó£¬ÈÜÒºÖеÄÑôÀë×Ó³ýÁ˺ÍÍ⣬»¹¿ÉÄÜ´æÔÚ           £¨ÓÃÀë×Ó·ûºÅ±íʾ£©£¬¼ì²â¸ÃÀë×ӵķ½·¨ÊÇ                               ¡£
£¨4£©ÓÃÂËÔüFͨ¹ýÁ½ÖÖ;¾¶ÖÆÈ¡µ¨·¯£¬Óë;¾¶¢ÛÏà±È£¬Í¾¾¶¢ÜÃ÷ÏÔ¾ßÓеÄÁ½¸öÓŵãÊÇ£º                          ¡¢                               ¡£
£¨5£©Í¾¾¶¢Ü·¢ÉúµÄ·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º                                                       ¡£
£¨6£©ÊµÑéÊÒ´ÓCuSO4ÈÜÒºÖÆÈ¡µ¨·¯£¬²Ù×÷²½ÖèÓÐÕô·¢Å¨Ëõ¡¢ÀäÈ´½á¾§¡¢          ¡¢×ÔÈ»¸ÉÔï¡£

£¨1£©2Al +2OH¨D + 2H2O = 2AlO2¨D +3H2¡ü (2·Ö)
£¨2£©  (1·Ö) ¢Ú  (1·Ö) Í¾¾¶¢ÙÖÆÈ¡µÄAlCl3ÈÜÒºÖлìÓÐNaClÔÓÖÊ(1·Ö)
£¨3£©Fe3£« (1·Ö) È¡Ñù£¬µÎ¼ÓKSCN£¬Èô±äѪºìÉ«£¬ÔòÓÐFe3£« ¡£(1·Ö)
£¨4£©³É±¾µÍ (1·Ö£¬ºÏÀí¸ø·Ö£¬ºóͬ) £»²»²úÉúÓж¾ÆøÌå (1·Ö)
£¨5£©2Cu +2H2SO4 +O2¡ú 2CuSO4 +2H2O   (2·Ö)
£¨6£©¹ýÂËÏ´µÓ (1·Ö)

ÊÔÌâ·ÖÎö£º
£¨1£©ÂÁ¡¢Ìú¡¢Í­Ö»ÓÐÂÁÓëÉÕ¼îÈÜÒº·´Ó¦¡£
£¨2£©ÓëNaAlO2·´Ó¦Éú³ÉAl(OH)3£¬¹Ì̬ʱ¿ÉÓÃÓÚÈ˹¤½µÓ꣬ÆøÌåÊÇCO2 £»NaAlO2 +4HCl=AlCl3+NaCl+2H2O ËùÒÔAlCl3ÈÜÒºÖлìÓÐNaClÔÓÖÊ¡£
£¨3£©Fe2£«±»¿ÕÆøÑõ»¯³ÉFe3£«£»Fe3£«ÓëKSCN·´Ó¦£¬±äѪºìÉ«¶øFe2£«²»ÄÜ¡£
£¨4£©Í¾¾¶¢ÛCu+2H2SO4= CuSO4+ SO2¡ü+2H2O
;¾¶¢Ü 2Cu +2H2SO4 +O2 = 2CuSO4 +2H2O;¾¶¢ÜÓÃÏ¡H2SO4³É±¾µÍ£¬²»²úÉúÓж¾ÆøÌå
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø