ÌâÄ¿ÄÚÈÝ
(16·Ö)ijÑо¿Ð¡×éÄâÓôÖʳÑÎ(º¬Ca2+¡¢Mg2+¡¢SO
µÈ)¡¢´Ö¹è(º¬C¼°²»ÓëCl2·´Ó¦µÄ¹ÌÌåÔÓÖÊ)ÖÆÈ¡´¿¹è£¬Éè¼ÆÈçÏµĹ¤ÒÕÁ÷³Ì£º

ÊԻشðÏÂÁÐÎÊÌ⣺
£¨1£©¹¤ÒµÉÏÒ»°ãÊÇÀûÓùýÁ¿½¹Ì¿ÔÚ¸ßÎÂÏ»¹ÔʯӢɰÀ´ÖÆÈ¡´Ö¹è£¬Ð´³ö¸Ã¹ý³ÌµÄ»¯Ñ§·½³Ìʽ£º_______________________________________________________________________¡£
£¨2£©¾«ÖÆ´ÖÑÎË®ËùÐèÊÔ¼ÁΪ¢ÙBaC12£»¢ÚNa2CO3£»¢ÛHC1£»¢ÜNaOH£¬ÆäµÎ¼ÓµÄÏȺó˳ÐòÊÇÏÂÁеÄ________(ÌîÏÂÁи÷ÏîµÄÐòºÅ)¡£
a£®¢Ù¢Ú¢Ü¢Û b£®¢Ü¢Ú¢Ù¢Û c£®¢Ü¢Ù¢Û¢Ú d£®¢Ú¢Ü¢Ù¢Û
ÒÑÖª£¬
£¬¼ÙÉè¸Ã´ÖÑÎË®ÖÐ
µÄŨ¶È¾ùΪ0.01 mol¡¤L-1£¬ÈôÏò1 L¸Ã´ÖÑÎË®ÖÐÖð½¥µÎÈëÒ»¶¨Á¿Na2CO3ÈÜÒº£¬Ê×ÏȳöÏֵijÁµíÊÇ__________¡£
£¨3£©ÒÑÖªSiCl4µÄ·ÐµãÊÇ57.6¡æ£¬CC14µÄ·ÐµãÊÇ76.8¡æ¡£ÔÚ·´Ó¦Æ÷IÖеõ½µÄSiCl4´ÖÆ·Öк¬ÓÐCCl4£¬´ÓÖеõ½´¿¾»SiCl4¿É²ÉÓõķ½·¨ÊÇÏÂÁи÷ÏîÖеÄ________(ÌîÐòºÅ)¡£
a£®ÕôÁó b£®¸ÉÁó c£®·ÖÒº d£®¹ýÂË
·´Ó¦Æ÷¢òÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ__________________________________________¡£
£¨4£©ÏÂͼÊÇÓÃÀë×Ó½»»»Ä¤·¨µç½â±¥ºÍʳÑÎË®µÄʾÒâͼ£¬µç½â²ÛÖÐÒõ¼«²úÉúµÄÆøÌåÊÇ_____¡£²úÆ·AµÄ»¯Ñ§Ê½Îª____________¡£

Èô²ÉÓÃÎÞĤµç½â²Ûµç½â±¥ºÍʳÑÎË®¿ÉÖÆÈ¡´ÎÂÈËáÄÆ£¬ÊÔд³ö¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ__ ___¡£


ÊԻشðÏÂÁÐÎÊÌ⣺
£¨1£©¹¤ÒµÉÏÒ»°ãÊÇÀûÓùýÁ¿½¹Ì¿ÔÚ¸ßÎÂÏ»¹ÔʯӢɰÀ´ÖÆÈ¡´Ö¹è£¬Ð´³ö¸Ã¹ý³ÌµÄ»¯Ñ§·½³Ìʽ£º_______________________________________________________________________¡£
£¨2£©¾«ÖÆ´ÖÑÎË®ËùÐèÊÔ¼ÁΪ¢ÙBaC12£»¢ÚNa2CO3£»¢ÛHC1£»¢ÜNaOH£¬ÆäµÎ¼ÓµÄÏȺó˳ÐòÊÇÏÂÁеÄ________(ÌîÏÂÁи÷ÏîµÄÐòºÅ)¡£
a£®¢Ù¢Ú¢Ü¢Û b£®¢Ü¢Ú¢Ù¢Û c£®¢Ü¢Ù¢Û¢Ú d£®¢Ú¢Ü¢Ù¢Û
ÒÑÖª£¬


£¨3£©ÒÑÖªSiCl4µÄ·ÐµãÊÇ57.6¡æ£¬CC14µÄ·ÐµãÊÇ76.8¡æ¡£ÔÚ·´Ó¦Æ÷IÖеõ½µÄSiCl4´ÖÆ·Öк¬ÓÐCCl4£¬´ÓÖеõ½´¿¾»SiCl4¿É²ÉÓõķ½·¨ÊÇÏÂÁи÷ÏîÖеÄ________(ÌîÐòºÅ)¡£
a£®ÕôÁó b£®¸ÉÁó c£®·ÖÒº d£®¹ýÂË
·´Ó¦Æ÷¢òÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ__________________________________________¡£
£¨4£©ÏÂͼÊÇÓÃÀë×Ó½»»»Ä¤·¨µç½â±¥ºÍʳÑÎË®µÄʾÒâͼ£¬µç½â²ÛÖÐÒõ¼«²úÉúµÄÆøÌåÊÇ_____¡£²úÆ·AµÄ»¯Ñ§Ê½Îª____________¡£

Èô²ÉÓÃÎÞĤµç½â²Ûµç½â±¥ºÍʳÑÎË®¿ÉÖÆÈ¡´ÎÂÈËáÄÆ£¬ÊÔд³ö¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ__ ___¡£
£¨16·Ö£©
£¨1£©SiO2+2C
Si+2CO¡ü£¨2·Ö£©
£¨2£©a£¨2·Ö£©£»Ì¼Ëá¸Æ£¨»òCaCO3£©£¨2·Ö£©
£¨3£©a£¨2·Ö£©£»SiCl4+2H2
Si+4HCl£¨2·Ö£©
£¨4£©ÇâÆø£¨»òH2£©£¨2·Ö£©£»NaOH£¨2·Ö£©£»NaCl+H2O
NaClO+H2¡ü£¨2·Ö£©
£¨1£©SiO2+2C

£¨2£©a£¨2·Ö£©£»Ì¼Ëá¸Æ£¨»òCaCO3£©£¨2·Ö£©
£¨3£©a£¨2·Ö£©£»SiCl4+2H2

£¨4£©ÇâÆø£¨»òH2£©£¨2·Ö£©£»NaOH£¨2·Ö£©£»NaCl+H2O

ÊÔÌâ·ÖÎö£º£¨1£©CÔÚ¸ßÎÂÌõ¼þÏ»¹ÔSiO2£¬Éú³ÉSiºÍCO£¬»¯Ñ§·½³ÌʽΪ£ºSiO2+2C

£¨2£©Na2CO3ÈÜÒºµÄ×÷ÓÃΪ³ýÈ¥Ca2+¡¢³ýÈ¥¹ýÁ¿µÄBaCl2ÈÜÒº£¬ËùÒÔNa2CO3µÄ˳ÐòÔÚBaCl2µÄºóÃ棬HClµÄ×÷ÓÃÊdzýÈ¥¹ýÁ¿µÄNa2CO3ºÍNaOH£¬ËùÒÔÔÚ×îºó£¬Òò´ËaÏîÕýÈ·£»ÒòΪKsp(MgCO3) < Ksp(CaCO3)£¬CaCO3¸üÄÑÈÜ£¬ËùÒÔÊ×ÏÈÎö³öµÄ³ÁµíÊÇCaCO3¡£
£¨3£©SiCl4ÓëCCl4ÔÚ³£ÎÂÏÂΪҺÌ壬Ï໥Èܽ⣬µ«·Ðµã²»Í¬£¬ËùÒÔÓÃÕôÁóµÄ·½·¨µÃµ½´¿¾»µÄSiCl4£»·´Ó¦Æ÷IIÖÐH2»¹ÔSiCl4£¬»¯Ñ§·½³ÌʽΪ£ºSiCl4+2H2

£¨4£©¸ù¾Ý·Åµç˳Ðò£¬Òõ¼«ÉÏH2OµçÀë³öµÄH+·Åµç£¬ËùÒÔµç½â²ÛÖÐÒõ¼«²úÉúµÄÆøÌåÊÇÇâÆø£»Ë®µçÀë³öµÄH+·Åµç£¬´Ù½øH2OµÄµçÀëƽºâÏòÓÒÒƶ¯£¬OH?Ũ¶ÈÔö´ó£¬ËùÒÔ²úÆ·AΪNaOH£»ÎÞĤµç½â²Ûµç½â±¥ºÍʳÑÎË®¿ÉÖÆÈ¡´ÎÂÈËáÄÆ£¬µç½â²úÉúµÄCl2ÓëNaOH·´Ó¦Éú³É´ÎÂÈËáÄÆ£¬ËùÒÔ»¯Ñ§·½³ÌʽΪ£ºNaCl+H2O


Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿