ÌâÄ¿ÄÚÈÝ

15£®¿§·ÈËᣨ¼ûͼ£©£¬´æÔÚÓÚÐí¶àÖÐÒ©ÖУ¬ÈçÒ°ºúÂܲ·¡¢¹âҶˮËÕ¡¢ÜñÂó¡¢Ä¾°ëÏĵȣ®¿§·ÈËáÓÐֹѪ×÷Óã¬Ìرð¶ÔÄÚÔàµÄֹѪЧ¹û½ÏºÃ£®
¢Ù¿§·ÈËáÓëNaHCO3ÈÜÒº·´Ó¦µÄ·½³Ìʽ£®
¢Ú·ä½ºµÄÖ÷Òª»îÐԳɷÖΪCPAE£¬·Ö×ÓʽΪC17H16O4£¬¸ÃÎïÖÊÔÚÒ»¶¨Ìõ¼þÏ¿ÉË®½âÉú³É¿§·ÈËáºÍÒ»ÖÖ´¼£¬¸Ã´¼Îª·¼Ïã´¼ÇÒ·Ö×ӽṹÖÐÎÞ¼×»ù£¬´Ë·¼Ïã´¼µÄ½á¹¹¼òʽΪ£¬¿§·ÈËá¸ú¸Ã·¼Ïã´¼ÔÚÒ»¶¨Ìõ¼þÏ·´Ó¦Éú³ÉCPAEµÄ»¯Ñ§·½³ÌʽΪ£®

·ÖÎö ¢Ùº¬ÓÐôÈ»ù£¬¿ÉÓë̼ËáÇâÄÆ·´Ó¦Éú³É¶þÑõ»¯Ì¼ÆøÌ壻
¢Ú·Ö×ÓʽΪC17H16O4£¬¸ÃÎïÖÊÔÚÒ»¶¨Ìõ¼þÏ¿ÉË®½âÉú³É¿§·ÈËáºÍÒ»ÖÖ´¼£¬ËµÃ÷CPAEº¬ÓÐõ¥»ù£¬¸Ã´¼Îª·¼Ïã´¼ÇÒ·Ö×ӽṹÖÐÎÞ¼×»ù£¬ÓÉ·Ö×Óʽ¿ÉÖª¸Ã´¼Îª£¬ÒԴ˽â´ð£®

½â´ð ½â£º¢Ùº¬ÓÐôÈ»ù£¬¿ÉÓë̼ËáÇâÄÆ·´Ó¦Éú³É¶þÑõ»¯Ì¼ÆøÌ壬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£¬
¹Ê´ð°¸Îª£º£»
¢Ú·Ö×ÓʽΪC17H16O4£¬¸ÃÎïÖÊÔÚÒ»¶¨Ìõ¼þÏ¿ÉË®½âÉú³É¿§·ÈËáºÍÒ»ÖÖ´¼£¬ËµÃ÷CPAEº¬ÓÐõ¥»ù£¬¸Ã´¼Îª·¼Ïã´¼ÇÒ·Ö×ӽṹÖÐÎÞ¼×»ù£¬ÓÉ·Ö×Óʽ¿ÉÖª¸Ã´¼Îª£¬¿§·ÈËá¸ú¸Ã·¼Ïã´¼ÔÚÒ»¶¨Ìõ¼þÏ·´Ó¦Éú³ÉCPAEµÄ»¯Ñ§·½³ÌʽΪ£¬
¹Ê´ð°¸Îª£º£»£®

µãÆÀ ±¾Ì⿼²éÓлúÎïµÄ½á¹¹ºÍÐÔÖÊ£¬ÌâÄ¿ÄѶȲ»´ó£¬×¢ÒâÓлúÎïµÄº¬ÓеĹÙÄÜÍŵÄÐÔÖÊ£¬´ËΪ½â´ð¸ÃÌâµÄ¹Ø¼ü£¬ÊìϤ±½·Ó¡¢Ï©Ìþ¡¢ôÈËáµÄÐÔÖʼ´¿É½â´ð£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
4£®2014Äê³õ£¬Îíö²ÌìÆø¶à´ÎËÁÅ°ÎÒ¹úÖж«²¿µØÇø£®ÆäÖУ¬Æû³µÎ²ÆøºÍȼúβÆøÊÇÔì³É¿ÕÆøÎÛȾµÄÔ­ÒòÖ®Ò»£®£¨1£©Æû³µÎ²Æø¾»»¯µÄÖ÷ÒªÔ­ÀíΪ2NO£¨g£©+2CO£¨g£©$\stackrel{´ß»¯¼Á}{?}$2CO2£¨g£©+N2£¨g£©£®ÔÚÃܱÕÈÝÆ÷Öз¢Éú¸Ã·´Ó¦Ê±£¬c£¨CO2£©Ëæζȣ¨T£©¡¢´ß»¯¼ÁµÄ±íÃæ»ý£¨S£©ºÍʱ¼ä£¨t£©µÄ±ä»¯ÇúÏßÈçÏÂͼËùʾ£®¾Ý´ËÅжϣº
¢Ù¸Ã·´Ó¦µÄ¡÷H£¼0£¨Ìî¡°£¾¡±¡°£¼¡±£©£®
¢ÚÔÚT2ζÈÏ£¬0¡«2sÄÚµÄƽ¾ù·´Ó¦ËÙÂÊv£¨N2£©=0.025mol•L-1•s-1£®
¢Ûµ±¹ÌÌå´ß»¯¼ÁµÄÖÊÁ¿Ò»¶¨Ê±£¬Ôö´óÆä±íÃæ»ý¿ÉÌá¸ß»¯Ñ§·´Ó¦ËÙÂÊ£®Èô´ß»¯¼ÁµÄ±íÃæ»ýS1£¾S2£¬ÔÚͼ¼×Öл­³öc£¨CO2£©ÔÚT1¡¢S2Ìõ¼þÏ´ﵽƽºâ¹ý³ÌÖеı仯ÇúÏߣ®

¢ÜÈô¸Ã·´Ó¦ÔÚ¾øÈÈ¡¢ºãÈݵÄÃܱÕÌåϵÖнøÐУ¬Í¼ÒÒʾÒâͼÕýÈ·ÇÒÄÜ˵Ã÷·´Ó¦ÔÚ½øÐе½t1ʱ¿Ì´ïµ½Æ½ºâ״̬µÄÊÇbd£¨Ìî´úºÅ£©£®
£¨2£©ÒÑÖª£ºCO2£¨g£©+3H2£¨g£©¨TCH3OH£¨g£©+H2O£¨g£©¡÷H1
2CO£¨g£©+O2£¨g£©¨T2CO2£¨g£©¡÷H2
2H2£¨g£©+O2£¨g£©¨T2H2O£¨g£©¡÷H3
Ôò·´Ó¦CO£¨g£©+2H2£¨g£©¨TCH3OH£¨g£©µÄ¡÷H=¡÷H1+$\frac{1}{2}$¡÷H2-$\frac{1}{2}$¡÷H3
£¨3£©Ä³ÊµÑéС×éÓÃ50mL 0.50mol•L-1 NaOH ÈÜÒººÍ30mL 0.50mol•L-1ÁòËáÈÜÒº½øÐÐÖкÍÈȵIJⶨ£®ÊµÑéÊýÖµ½á¹û±È57.3kJ•mol-1ƫС£¬²úÉú´ËʵÑéÆ«²îµÄÔ­Òò¿ÉÄÜÊÇ£¨Ìî×Öĸ£©a¡¢d£®
a£®ÊµÑé×°Öñ£Î¡¢¸ôÈÈЧ¹û²î
b£®Á¿È¡NaOHÈÜÒºµÄÌå»ýʱÑöÊÓ¶ÁÊý
c£®Ò»´ÎÐÔ°ÑNaOHÈÜÒºµ¹ÈëÊ¢ÓÐÁòËáµÄСÉÕ±­ÖÐ
d£®ÓÃζȼƲⶨNaOHÈÜÒºÆðʼζȺóÖ±½Ó²â¶¨H2SO4ÈÜÒºµÄζȣ®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø