ÌâÄ¿ÄÚÈÝ

ÒÑÖªA¡¢B¡¢C¡¢DÊǶÌÖÜÆÚÖеÄ4ÖַǽðÊôÔªËØ£¬ËüÃǵÄÔ­×ÓÐòÊýÒÀ´ÎÔö´ó¡£AÔªËØÔ­×ÓÐγɵÄÀë×Ó¾ÍÊÇÒ»¸öÖÊ×Ó¡£ÓÖÖª£¬¢ÙBµ¥ÖÊÔÚ¸ßÎÂÏ¿ɴÓAÓëD×é³ÉµÄijÖÖ»¯ºÏÎïÖÐÖû»³öA£¬Í¬Ê±Éú³É»¯ºÏÎïBD£¬¢ÚA¡¢C¡¢DÈýÖÖÔªËØ×é³ÉµÄijÖÖÑÎË®ÈÜÒºÏÔËáÐÔ£¬¢ÛB¡¢C¾ùÄÜÓëD×é³ÉÔ­×ÓÊý±ÈΪ1¡Ã1ºÍ1¡Ã2µÄ»¯ºÏÎï¡£

£¨1£©Ð´³ö¢ÚÖÐÑεÄË®ÈÜÒºÏÔËáÐÔµÄÔ­Òò£¨Ð´³öÀë×Ó·½³Ìʽ£©_____________________£»

£¨2£©ÒÑÖªA¡¢B¡¢C¡¢D¿É×é³ÉÔ­×Ó¸öÊý±È5¡Ã1¡Ã1¡Ã3µÄ»¯ºÏÎд³ö¸Ã»¯ºÏÎïÓë×ãÁ¿NaOHÈÜÒº·´Ó¦µÄÀë×Ó·½³Ìʽ£º__________________________¡£

£¨3£©¡°³¤Õ÷2ºÅ¡±ÔËÔØ»ð¼ýËùÓÃȼÁϾÍÊÇCµÄÇ⻯Îﱻȡ´úºóµÄ²úÎÏà¶Ô·Ö×ÓÖÊÁ¿60£¬ÆäÖÐBµÄÖÊÁ¿·ÖÊýΪ0.40£¬AµÄÖÊÁ¿·ÖÊýΪ0.1333£¬ÆäÓàΪC£©£¬¶øC¡¢DÐγɵÄÔ­×Ó¸öÊý±È1¡Ã2µÄ»¯ºÏÎÏà¶Ô·Ö×ÓÖÊÁ¿92£©¾ÍÊǸÃȼÁϵÄÑõ»¯¼Á¡£ÇÒÒÑÖªËüÃÇÖ®¼ä·¢ÉúÑõ»¯»¹Ô­·´Ó¦ºóÉú³ÉµÄ²úÎï¶Ô»·¾³ÎÞÎÛȾ¡£Ôò¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ_____________________¡£

£¨4£©CÔªËصÄÆø̬Ç⻯ÎïÄÜ»¹Ô­CuO£¬Éú³ÉCu¡¢Cµ¥Öʼ°AÓëDÐγɵĻ¯ºÏÎ¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ__________________¡£

£¨1£©NH+H2ONH3¡¤H2O+H+

£¨2£©NH+HCO+2OH£­====NH3¡ü+CO+2H2O

£¨3£©C2H8N2+2N2O4====3N2+2CO2+4H2O

£¨4£©2NH3+3CuON2+3Cu+3H2O

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø