ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿È¡3mL 5mol¡¤L-1 H2O2ÈÜÒº£¬¼ÓÈëÉÙÁ¿MnO2·ÛÄ©£¬2minʱc(H2O2)½µÎª1mol¡¤L-1¡£ÏÂÁÐ˵·¨²»ÕýÈ·µÄÊÇ
A.2minÄÚ£¬v(H2O2) =2molL-lmin-1
B.MnO2ÊÇ´ß»¯¼Á£¬ÄܼӿìH2O2µÄ·Ö½âËÙÂÊ
C.Éý¸ßζȻòÔö´óH2O2µÄŨ¶È£¬¾ùÄܼӿìH2O2µÄ·Ö½âËÙÂÊ
D.Èô½«5 molL-l H2O2ÈÜÒºµÄÌå»ýÔöÖÁ6mL£¬ÔòH2O2µÄ·Ö½âËÙÂÊÔöÖÁÔÀ´µÄ2±¶
¡¾´ð°¸¡¿D
¡¾½âÎö¡¿
A. »¯Ñ§·´Ó¦ËÙÂÊv===2molL-lmin-1£¬AÏîÕýÈ·£»
B. ´ß»¯¼Á¸Ä±ä·´Ó¦ËÙÂʲ»¸Ä±ä»¯Ñ§Æ½ºâ£¬¼ÓÈëÉÙÁ¿MnO2·ÛÄ©ÊÇ·´Ó¦µÄ´ß»¯¼Á£¬ÄܼӿìH2O2µÄ·Ö½âËÙÂÊ£¬BÏîÕýÈ·£»
C. Éý¸ßζȻòÔö´óH2O2µÄŨ¶È¾ù¿ÉÒÔ¼Ó¿ì·´Ó¦ËÙÂÊ£¬CÏîÕýÈ·£»
D. Èô½«5 molL-l H2O2ÈÜÒºµÄÌå»ýÔöÖÁ6mL£¬ÈÜҺŨ¶È¼õÉÙ£¬H2O2µÄ·Ö½âËÙÂÊ»á¼õÂý£¬DÏî´íÎó£»
´ð°¸Ñ¡D¡£
¡¾ÌâÄ¿¡¿ÈËÌåµÄ½¡¿µÓÐÀµÓÚÌåÄÚ¸÷ÖÖÔªËصľùºâÉãÈë¡£
£¨1£©Õý³£ÈËÒ»ÌìµÄʳÑÎÉãÈëÁ¿²»³¬¹ý 6g¡£
¢Ù³ýÈ¥ NaClÈÜÒºÖеÄSO42-£¬ÒÀ´Î¼ÓÈëµÄÈÜҺΪ£¨ÌîÈÜÖʵĻ¯Ñ§Ê½£©£º¹ýÁ¿______ÈÜÒº¡¢¹ýÁ¿______ÈÜÒº¡¢ÊÊÁ¿Ï¡ÑÎËá¡£
¢ÚʳÓõâÑÎÊÇʳÑÎÖмÓÈë KIO3¡£Ï±íÊÇijµØÊг¡ÉÏÏúÊÛµÄÒ»ÖÖ¡°¼ÓµâÑΡ±°ü×°ÉϵIJ¿·ÖÎÄ×Ö˵Ã÷¡£»Ø´ðÏÂÁÐÎÊÌ⣺
ÅäÁϱí | ¾«Öƺ£ÑΡ¢µâËá¼Ø£¨KIO3£© |
º¬µâÁ¿ | 20~40 mg/kg |
´¢²Ø·½·¨ | ÃÜ·â±Ü¹â¡¢·À³± |
ʳÓ÷½·¨ | Åëµ÷ʱ´ýʳƷÊìºó¼ÓÈëµâÑÎ |
ʳÓõâÑÎÖС°µâ¡±ÊÇÖ¸______£¨Ìî¡°µâÀë×Ó¡±»ò¡°µâÔªËØ¡±£©¡£ÍƲâ³öµâËá¼Ø£¨KIO3£©»¯Ñ§ÐÔÖÊ£ºµâËá¼Ø£¨KIO3£©ÔÚ¸ßÎÂʱ______£¨Ìî¡°Ò׷ֽ⡱»ò¡°²»Ò׷ֽ⡱£©¡£Ò»Öֲⶨº¬µâÁ¿µÄ»¯Ñ§ÔÀíÊÇ£º
£¨¦©£©KIO3 + KI + H2SO4===K2SO4 + I2 + H2O£¨Î´Åäƽ£©£¬
£¨¢ò£©I2 + 2Na2S2O3 = 2NaI + Na2S4O8¡£½«·´Ó¦ ¦© ¸ÄдΪÀë×Ó·½³Ìʽ_____
£¨2£©³ÉÈËÿÌì´ÓʳÎïÖÐÉãÈ¡ 0.8 g Ca ÔªËØ¡¢0.3 g Mg ÔªËØ¡£
¢ÙCa ÔªËØÓë Mg ÔªËØÎïÖʵÄÁ¿Ö®±ÈΪ______¡£
¢ÚÄ«Óã¹Ç·Û(Ö÷Òª³É·ÖÊÇ CaCO3£©£¬¿ÉÓÃ×÷ÖÎÁÆθËá¹ý¶à£¬ÆäÔÒòÊÇ_________(ÓÃÀë×Ó·½³Ìʽ»Ø´ð)¡£
¢Û´Óº£Ë®ÖпÉÌáȡþ£º³ýÈ¥»ìÔÚ Mg(OH)2 ÖÐµÄ Ca(OH)2 µÄ×î¼Ñ·½·¨ÊÇ£º¼ÓÈë¹ýÁ¿µÄ______£¨Ìî¡°A¡±»ò¡°B¡±£©£¨A. MgSO4 ÈÜÒº¡¡B. MgCl2 ÈÜÒº£©£¬¹ýÂË£¬Ï´µÓ£¬µÍκæ¸É¡£