ÌâÄ¿ÄÚÈÝ

¡¾ÌâÄ¿¡¿ÂÁºÍÇâÑõ»¯¼Ø¶¼ÊÇÖØÒªµÄ¹¤Òµ²úÆ·¡£Çë»Ø´ð£º

(1)¹¤ÒµÒ±Á¶ÂÁµÄ»¯Ñ§·½³ÌʽÊÇ_______________________¡£

(2)ÂÁÓëÇâÑõ»¯¼ØÈÜÒº·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ______________¡£

(3)¹¤Òµ¼¶ÇâÑõ»¯¼ØµÄÈÜÒºÖк¬ÓÐijЩº¬ÑõËá¸ùÔÓÖÊ£¬¿ÉÓÃÀë×Ó½»»»Ä¤·¨µç½âÌá´¿¡£µç½â²ÛÄÚ×°ÓÐÑôÀë×Ó½»»»Ä¤(Ö»ÔÊÐíÑôÀë×Óͨ¹ý)£¬Æ乤×÷Ô­ÀíÈçͼËùʾ¡£

¢Ù¸Ãµç½â²ÛµÄÑô¼«·´Ó¦Ê½ÊÇ______________________¡£

¢Úͨµç¿ªÊ¼ºó£¬Òõ¼«¸½½üÈÜÒºpH»áÔö´ó£¬Çë¼òÊöÔ­Òò______________________¡£

¢Û³ýÈ¥ÔÓÖʺóµÄÇâÑõ»¯¼ØÈÜÒº´ÓÒºÌå³ö¿Ú___________(Ìîд¡°A¡±»ò¡°B¡±)µ¼³ö¡£

¡¾´ð°¸¡¿(1)2Al2O3(ÈÛÈÚ)4Al£«3O2¡ü

(2)2Al£«2OH£­£«2H2O==2AlO2£­£«3H2¡ü

(3)¢Ù4OH£­£­4e£­==2H2O£«O2¡ü

¢ÚH£«·Åµç£¬´Ù½øË®µÄµçÀ룬OH£­Å¨¶ÈÔö´ó¢ÛB

¡¾½âÎö¡¿(3)Öиù¾Ýµç½âÔ­Àí£¬Ñô¼«Ó¦ÊÇOH£­Ê§µç×Ó£¬ËùÒԵ缫·´Ó¦Ê½Îª4OH£­£­4e£­==2H2O£«O2¡ü£¬¶øÒõ¼«ÎªH£«·Åµç£¬´Ù½øË®µÄµçÀ룬ʹOH£­Å¨¶ÈÔö´ó£¬ËùÒÔpHÔö´ó£¬¸ù¾ÝÑôÀë×Ó½»»»Ä¤µÄÌص㣬K£«¿É´ÓÑô¼«Çø½øÈëÒõ¼«ÇøºÍOH£­×é³ÉKOH£¬´Ó¶ø¿ÉÔÚÒõ¼«ÇøµÃµ½´¿µÄKOHÈÜÒº£¬¹ÊÒºÌåÓ¦´ÓB¿Úµ¼³ö¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø