ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿¼îʽ̼ËáǦ[»¯Ñ§Ê½Îª2PbCO3¡¤Pb(OH)2]ÊÇÉú²úǦËáÐîµç³ØÕý¼«µÄÔÁÏ¡£
(1) ijÑо¿Ð¡×éÖƱ¸¼îʽ̼ËáǦµÄÖ÷ҪʵÑéÁ÷³ÌÈçÏ£º
¢Ù¡°·´Ó¦¢Ù¡±µÄÉú³ÉÎïÊÇ(CH3COO)2Pb¡¤Pb(OH)2£¬¸Ã·´Ó¦ÊÇÔÚ90¡æ¡¢½Á°è²¢±£ÎÂ3 hµÄÌõ¼þÏÂÍê³ÉµÄ£¬Ôò¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ_______________________________________¡£
¢Ú¹ýÂËʱËùÐèÒªµÄ²£Á§ÒÇÆ÷ÓЩ¶·¡¢________¡£
¢Û³Áµí¾Ë®Ï´µÓºóÓÖÓþƾ«Ï´µÓµÄÄ¿µÄÊÇ____________________________________¡£
(2) Ϊȷ¶¨2PbCO3¡¤Pb(OH)2µÄÈÈ·Ö½â¹ý³Ì£¬½øÐÐÁËÈçÏÂʵÑ飺
³ÆÈ¡Ò»¶¨Á¿(1)ÖÐÖƵõIJúÆ··ÅÔÚÈÈÖØ·ÖÎöÒÇÖУ¬ÔÚë²ÆøÁ÷ÖмÓÈȷֽ⣬²âµÃ²ÐÁô¹ÌÌåµÄÖÊÁ¿Ëæζȵı仯ÈçÏÂͼËùʾ¡£
¢ÙA¡úB¹ý³ÌÖУ¬ÒݳöµÄ·Ö½â²úÎïµÄ»¯Ñ§Ê½Îª______________£»Eµã²ÐÁô¹ÌÌåµÄ»¯Ñ§Ê½Îª______________¡£¡¡
¢Ú¸ù¾ÝͼÖÐÊý¾Ý£¬¼ÆË㲢ȷ¶¨Dµã²ÐÁô¹ÌÌåµÄ»¯Ñ§Ê½(д³ö¼ÆËã¹ý³Ì)______________¡£
¡¾´ð°¸¡¿ 2PbO£«2CH3COOH (CH3COO)2Pb¡¤Pb(OH)2 ÉÕ±¡¢²£Á§°ô ³ýÈ¥³Áµí±íÃ渽×ŵÄË®²¢´Ù½øÆä¿ìËÙ¸ÉÔï H2O PbO 1 mol 2PbCO3¡¤Pb(OH)2(ÓÃÑõ»¯ÎïÐÎʽ±íʾΪ£º3PbO¡¤2CO2¡¤H2O)µÄÖÊÁ¿Îª775 g£¬155 g 2PbCO3¡¤Pb(OH)2µÄÎïÖʵÄÁ¿Îª0.2 mol£¬¿ÉÒÔ±íʾΪ£ºº¬PbO 0.6 mol¡¢CO2 0.4 mol¡¢H2O 0.2 mol£¬¶ø¼ÓÈȹý³ÌÖÐPbÔªËصÄÖÊÁ¿²»±ä£¬Òò´Ë£¬A¡úBµÄ¹ý³ÌÖУ¬¦¤m1£½3.6 g£¬¼õÉÙµÄÊÇ0.2 mol H2O£¬B¡úDµÄ¹ý³ÌÖУ¬¦¤m2£½8.8 g£¬¼õÉÙµÄÊÇ0.2 mol CO2£¬D¡úEµÄ¹ý³ÌÖУ¬¦¤m3£½8.8 g£¬¼õÉÙµÄÊÇ0.2 mol CO2£¬ËùÒÔ£¬BµãµÄ»¯Ñ§Ê½Îª2PbCO3¡¤PbO£¬¼´3PbO¡¤2CO2£¬DµãµÄ»¯Ñ§Ê½ÎªPbCO3¡¤2PbO£¬¼´3PbO¡¤CO2
¡¾½âÎö¡¿(1)¢Ù¡°·´Ó¦¢Ù¡±µÄÉú³ÉÎïÊÇ(CH3COO)2PbPb(OH)2£¬¸Ã·´Ó¦ÊÇÔÚ90¡æ¡¢½Á°è²¢±£ÎÂ3hµÄÌõ¼þÏÂÍê³ÉµÄ£¬Ôò¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º2PbO+2CH3COOH(CH3COO)2PbPb(OH)2£»¹Ê´ð°¸Îª£º2PbO+2CH3COOH(CH3COO)2PbPb(OH)2£»
¢Ú¹ýÂËʱËùÐèÒªµÄ²£Á§ÒÇÆ÷ÓЩ¶·¡¢ÉÕ±¡¢²£Á§°ô£¬¹Ê´ð°¸Îª£ºÉÕ±¡¢²£Á§°ô£»
¢Û¡°Ï´µÓ¡±Ê±£¬¾Ë®Ï´µÓºóÔÙÓþƾ«Ï´µÓµÄÄ¿µÄÊdzýÈ¥±íÃæµÄË®·Ýͬʱ¿ÉÒÔ¿ìËÙ¸ÉÔµÃ´¿¾»2PbCO3Pb(OH)2µÄ²úÆ·£¬¹Ê´ð°¸Îª£º³ýÈ¥³Áµí±íÃ渽×ŵÄË®²¢´Ù½øÆä¿ìËÙ¸ÉÔ
(2)¢Ù1mol2PbCO3Pb(OH)2(ÓÃÑõ»¯ÎïÐÎʽ±íʾΪ£º3PbO2CO2H2O)µÄÖÊÁ¿Îª775g£¬155g2PbCO3Pb(OH)2µÄÎïÖʵÄÁ¿Îª0.2mol£¬¿ÉÒÔ±íʾΪ£ºº¬PbO0.6mol¡¢CO20.4mol¡¢H2O0.2mol£¬¶ø¼ÓÈȹý³ÌÖÐPbÔªËصÄÖÊÁ¿²»±ä£¬Òò´ËA¡úBµÄ¹ý³ÌÖУ¬¡÷m1=3.6g£¬¼õÉÙµÄÊÇ0.2molH2O£¬B¡úDµÄ¹ý³ÌÖУ¬¡÷m2=8.8g£¬¼õÉÙµÄÊÇ0.2molCO2£¬D¡úEµÄ¹ý³ÌÖУ¬¡÷m3=8.8g£¬¼õÉÙµÄÊÇ0.2molCO2£¬ÔòEµã²ÐÁôµÄ¹ÌÌåΪPbO£»¹Ê´ð°¸Îª£ºH2O£»PbO£»
¢Ú1mol2PbCO3Pb(OH)2(ÓÃÑõ»¯ÎïÐÎʽ±íʾΪ£º3PbO2CO2H2O)µÄÖÊÁ¿Îª775g£¬155g2PbCO3Pb(OH)2µÄÎïÖʵÄÁ¿Îª0.2mol£¬¿ÉÒÔ±íʾΪ£ºº¬PbO0.6mol¡¢CO20.4mol¡¢H2O0.2mol£¬¶ø¼ÓÈȹý³ÌÖÐPbÔªËصÄÖÊÁ¿²»±ä£¬Òò´ËA¡úBµÄ¹ý³ÌÖУ¬¡÷m1=3.6g£¬¼õÉÙµÄÊÇ0.2molH2O£¬B¡úDµÄ¹ý³ÌÖУ¬¡÷m2=8.8g£¬¼õÉÙµÄÊÇ0.2molCO2£¬D¡úEµÄ¹ý³ÌÖУ¬¡÷m3=8.8g£¬¼õÉÙµÄÊÇ0.2molCO2£¬ËùÒÔ£¬BµãµÄ»¯Ñ§Ê½Îª2PbCO3PbO£¬¼´3PbO2CO2£¬DµãµÄ»¯Ñ§Ê½ÎªPbCO32PbO£¬¼´3PbOCO2£¬´ð£ºDµã²ÐÁô¹ÌÌåµÄ»¯Ñ§Ê½ÎªPbCO32PbO»ò3PbOCO2¡£