ÌâÄ¿ÄÚÈÝ
ijÈÜÒºÖпÉÄܺ¬ÓÐÒÔÏÂ6ÖÖÀë×ÓÖеļ¸ÖÖ£ºNH4+¡¢A13+¡¢Mg2+¡¢CO32¨D¡¢ClÒ»¡¢SO42¨D£¬ÎªÈ·ÈÏÈÜÒº×é³É£¬ÏÖÈ¡100 mL·Ö³ÉÈýµÈ·ÝÈÜÒº½øÐÐÈçÏÂʵÑ飺
£¨1£©ÏòµÚÒ»·ÝÈÜÒºÖмÓÈë AgNO3ÈÜÒºÓгÁµí²úÉú£»
£¨2£©ÏòµÚ¶þ·ÝÈÜÒºÖмÓÈë×ãÁ¿NaOHÈÜÒº³ä·Ö·´Ó¦ºó£¬×îÖյõ½³Áµí0.58 g(¾¹ýÂË¡¢Ï´µÓ¡¢¸ÉÔÏÂͬ)£¬Í¬Ê±ÊÕ¼¯µ½ÆøÌå0.03 mol(ÉèÆøÌåÈ«²¿´ÓÈÜÒºÖÐÒݳö)£»
£¨3£©ÏòµÚÈý·ÝÈÜÒºÖмÓÈë×ãÁ¿BaCl2ÈÜÒº(ÑÎËáËữ)³ä·Ö·´Ó¦ºó£¬µÃµ½³Áµí6.99 g¡£
ÓÉ´Ë¿ÉÖª£¬ÏÂÁйØÓÚÔÈÜÒº×é³ÉµÄÕýÈ·½áÂÛÊÇ
£¨1£©ÏòµÚÒ»·ÝÈÜÒºÖмÓÈë AgNO3ÈÜÒºÓгÁµí²úÉú£»
£¨2£©ÏòµÚ¶þ·ÝÈÜÒºÖмÓÈë×ãÁ¿NaOHÈÜÒº³ä·Ö·´Ó¦ºó£¬×îÖյõ½³Áµí0.58 g(¾¹ýÂË¡¢Ï´µÓ¡¢¸ÉÔÏÂͬ)£¬Í¬Ê±ÊÕ¼¯µ½ÆøÌå0.03 mol(ÉèÆøÌåÈ«²¿´ÓÈÜÒºÖÐÒݳö)£»
£¨3£©ÏòµÚÈý·ÝÈÜÒºÖмÓÈë×ãÁ¿BaCl2ÈÜÒº(ÑÎËáËữ)³ä·Ö·´Ó¦ºó£¬µÃµ½³Áµí6.99 g¡£
ÓÉ´Ë¿ÉÖª£¬ÏÂÁйØÓÚÔÈÜÒº×é³ÉµÄÕýÈ·½áÂÛÊÇ
A£®Ò»¶¨´æÔÚClÒ» |
B£®Ò»¶¨´æÔÚA13+ºÍNH4+ |
C£®Ò»¶¨²»´æÔÚMg2+£¬¿ÉÄÜ´æÔÚA13+ |
D£®ÈÜÒºÖÐSO42¨DµÄŨ¶ÈÊÇ0. 3 mol/L |
B
ÊÔÌâ·ÖÎö£º¼ÓÈë AgNO3ÈÜÒºÓгÁµí²úÉú²»ÄÜÈ·¶¨ÈÜÒºÖÐÊÇ·ñÒ»¶¨º¬ÓÐClÒ»ÒòΪ̼ËáÒøÒ²ÊÇ°×É«³Áµí£¬A´íÎó£»ÇâÑõ»¯Ã¾²»ÈÜÓÚÇâÑõ»¯ÄÆ£¬ËùÒÔ¼ÓÈë¹ýÁ¿µÄÇâÑõ»¯ÄƲúÉú³Áµí˵Ã÷ÈÜÒºÖÐÒ»¶¨º¬ÓÐMg2+£¬ÈÜÒºÖмÓÈë×ãÁ¿BaCl2ÈÜÒº(ÑÎËáËữ)³ä·Ö·´Ó¦ºó£¬µÃµ½ÁòËá±µ³Áµí6.99 g£¬ÎïÖʵÄÁ¿£¬¸ù¾ÝÔªËØÊغãÁòËá¸ùÀë×ÓµÄÎïÖʵÄÁ¿Îª£¬D´íÎó£¬ËùÒÔ´ð°¸Ñ¡B¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿