ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿Ï±íΪ³¤Ê½ÖÜÆÚ±íµÄÒ»²¿·Ö£¬ÆäÖеıàºÅ´ú±í¶ÔÓ¦µÄÔªËØ¡£
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
(1)±íÖÐÊôÓÚdÇøÔªËصÄÊÇ________(ÌîÔªËØ·ûºÅ)¡£
(2)±íÖÐÔªËآٵÄ6¸öÔ×ÓÓëÔªËØ¢ÛµÄ6¸öÔ×ÓÐγɵÄijÖÖ»·×´·Ö×ÓÃû³ÆΪ____£»¢ÛºÍ¢ßÐγɵÄÒ»ÖÖ³£¼ûÈܼÁµÄ»¯Ñ§Ê½Îª_____¡£
(3)ÔªËآܵĵÚÒ»µçÀëÄÜ________ÔªËØ¢Ý(Ñ¡Ìî¡°>¡±¡¢¡°£½¡±»ò¡°<¡±)µÄµÚÒ»µçÀëÄÜ£»ÔªËآ޵ĵ縺ÐÔ________ÔªËØ¢ß(Ñ¡Ìî¡°>¡±¡¢¡°£½¡±»ò¡°<¡±)µÄµç¸ºÐÔ¡£
(4)ÔªËآߺ͢àÐγɵĻ¯ºÏÎïµÄµç×ÓʽΪ________________¡£
(5)ijЩ²»Í¬×åÔªËصÄÐÔÖÊÒ²ÓÐÒ»¶¨µÄÏàËÆÐÔ£¬ÈçÉϱíÖÐÔªËØ¢ÚÓëÔªËآݵÄÇâÑõ»¯ÎïÓÐÏàËƵÄÐÔÖÊ¡£Çëд³öÔªËØ¢ÚµÄÇâÑõ»¯ÎïÓëNaOHÈÜÒº·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º________¡£
¡¾´ð°¸¡¿Ti ±½ CCl4 > < Be(OH)2£«2NaOH===Na2BeO2£«2H2O
¡¾½âÎö¡¿
ÓÉÔªËØÔÚÖÜÆÚ±íÖеÄλÖÿÉÖª£¬¢ÙΪH£¬¢ÚΪBe£¬¢ÛΪC£¬¢ÜΪMg£¬¢ÝΪAl£¬¢ÞΪP£¬¢ßΪCl£¬¢àΪCa£¬¢áΪTi£¬¢âΪCu¡£½áºÏÔªËØÖÜÆÚ±íµÄ½á¹¹ºÍÔªËØÖÜÆÚÂÉ·ÖÎö½â´ð¡£
(1)dÇøÔªËØ°«ÔªËØÖÜÆÚ±íÖÐλÓÚ¢óB~¢ø£¬±íÖÐÊôÓÚdÇøÔªËصÄÊÇTi£¬¹Ê´ð°¸Îª£ºTi£»
(2)ÔªËآٵÄ6¸öÔ×ÓÓëÔªËØ¢ÛµÄ6¸öÔ×ÓÐγɵĻ¯ºÏÎïµÄ»¯Ñ§Ê½ÎªC6H6£¬ÆäÖнṹΪ»·×´·Ö×ÓµÄΪ±½£¬¢ÛºÍ¢ßÐγɵÄÒ»ÖÖ³£¼ûÈܼÁΪCCl4£¬¹Ê´ð°¸Îª£º±½£»CCl4£»
(3)¢ÜΪMg£¬¢ÝΪAl£¬Í¬Ò»ÖÜÆÚÖУ¬ÔªËصĵÚÒ»µçÀëÄÜËæ×ÅÔ×ÓÐòÊýµÄÔö´ó¶ø³ÊÔö´óÇ÷ÊÆ£¬µ«µÚ¢òA×åÔªËصÚÒ»µçÀëÄÜ´óÓÚÏàÁÚÔªËØ£¬µÚÒ»µçÀëÄÜ£ºMg£¾Al£»¢ÞΪP£¬¢ßΪCl£¬ÔªËصķǽðÊôÐÔԽǿ£¬µç¸ºÐÔÔ½´ó£¬µç¸ºÐÔ£ºP£¼Cl£¬¹Ê´ð°¸Îª£º>£»<£»
(4) ¢ßΪCl£¬¢àΪCa£¬¢ßºÍ¢àÐγɵĻ¯ºÏÎïΪÂÈ»¯¸Æ£¬ÊôÓÚÀë×Ó»¯ºÏÎµç×ÓʽΪ£¬¹Ê´ð°¸Îª£º
£»
(5)ÔªËØ¢ÚµÄÇâÑõ»¯ÎïÓëNaOHÈÜÒº·´Ó¦Éú³ÉNa2BeO2£¬¸Ã·´Ó¦ÎªBe(OH)2+2NaOH¨TNa2BeO2+2H2O£¬¹Ê´ð°¸Îª£ºBe(OH)2+2NaOH¨TNa2BeO2+2H2O¡£
![](http://thumb2018.1010pic.com/images/loading.gif)