ÌâÄ¿ÄÚÈÝ

2£®ÓÃCH4´ß»¯»¹Ô­NO£¬¿ÉÒÔÏû³ýµªÑõ»¯ÎïµÄÎÛ£¬ÓÐÍû½â¾öÆû³µÎ²ÆøÎÛȾÎÊÌ⣬·´Ó¦ÈçÏ£º
CH4£¨g£©+4NO2£¨g£©=4NO£¨g£©+CO2£¨g£©+2H2O£¨g£©£»¡÷H=-574kJ•mol-1
CH4£¨g£©+4NO£¨g£©=2N2£¨g£©+CO2£¨g£©+2H2O£¨g£©£»¡÷H=-akJ•mol-1
°´ÉÏÊöת»¯£¬±ê×¼×´¿öÏÂ44.8L NO2±»»¹Ô­ÖÁN2£¬Õû¸ö¹ý³ÌÖзųöµÄÈÈÁ¿Îª867kJ£¬ÔòaµÄֵΪ£¨¡¡¡¡£©
A£®1160B£®2308C£®1441D£®2320

·ÖÎö ÏȽ«Á½¸ö·½³ÌʽÏà¼ÓµÃ NO2ת»¯ÎªµªÆøµÄ·½³Ìʽ£¬¸ù¾Ý±ê×¼×´¿öÏÂ44.8L NO2±»»¹Ô­ÖÁN2£¬Õû¸ö¹ý³ÌÖзųöµÄÈÈÁ¿Îª867kJ¼ÆËãaµÄÖµ£®

½â´ð ½â£º½«Á½¸ö·½³ÌʽCH4£¨g£©+4NO2£¨g£©=4NO£¨g£©+CO2£¨g£©+2H2O£¨g£©¡÷H1=-574kJ•mol-1¡¢CH4£¨g£©+4NO£¨g£©=2N2£¨g£©+CO2£¨g£©+2H2O£¨g£©¡÷H2=-akJ•mol-1Ïà¼ÓµÃ£º2CH4£¨g£©+4NO2£¨g£©=2N2£¨g£©+2CO2£¨g£©+4H2O£¨g£©¡÷H=-£¨574+a£©kJ•mol-1
ÓÖ±ê×¼×´¿öÏÂ44.8L NO2±»»¹Ô­ÖÁN2£¬¼´2molNO2±»»¹Ô­ÖÁN2·Å³öµÄÈÈÁ¿Îª867kJ£¬ËùÒÔ867¡Á2=574+a£¬½âµÃa=1160£¬¹ÊÑ¡£ºA£®

µãÆÀ ±¾Ì⿼²éÁË·´Ó¦ÈȵļÆËãµÈ֪ʶµã£¬¸ù¾ÝÎïÖʵÄÁ¿ÓëÈÈÁ¿µÄ¹Øϵʽ¼ÆËã·Å³öµÄÈÈÁ¿¼´¿É£¬ÄѶȲ»´ó£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
19£®ÎªÁ˲ⶨijδ֪NaOHÈÜÒºµÄŨ¶È£¬ÐèÒª0.200mol•L-1µÄÑÎËáÈÜÒº500mL£®Ä³Ñ§ÉúÓÃʵÑéÊÒÖг£ÓõÄ36.5%£¨ÃܶÈΪ1.20g•cm-3£©µÄŨÑÎËáÅäÖÆËùÐèÏ¡ÑÎËᣬ²¢Éè¼ÆÁËÒÔϲ½ÖèÍê³ÉʵÑ飮
£¨1£©ÇëÄã°ïÖú¸ÃͬѧÍê³ÉÒÔϸ÷²½ÖеÄÄÚÈÝ£¬²¢½«ÆäËùÉè¼ÆµÄʵÑé²½ÖèÕýÈ·ÅÅÐò£®
A£®ÓÃb£¨´ÓÒÔϱ¸Ñ¡ÒÇÆ÷ÖÐÑ¡È¡Êʵ±ÒÇÆ÷½«ÆäÐòºÅÌîÈ룩Á¿£¨»ò³Æ£©È¡36.5%£¨ÃܶÈΪ1.19g•cm-3£©µÄŨÑÎËá8.3ml£¨ÌîдËùÐèÌå»ý»òÖÊÁ¿£©£®
a.50mLÁ¿Í²£»  b.10mLÁ¿Í²£»   c£®ÍÐÅÌÌìƽ£®
B£®½«È¡ºÃµÄŨÑÎËáÔÚÉÕ±­ÖмÓÊÊÁ¿ÕôÁóˮϡÊÍ£®
C£®ÇáÇáÕñµ´ºó¼ÌÐø¼ÓÕôÁóË®µ½ÒºÃæ¾àÀëÒÇÆ÷¿ÌÏß1¡«2cm´¦£®
D£®µÈÈÜÒº»Ö¸´ÖÁÊÒΣ®
E£®½«ÈÜÒºÓò£Á§°ôÒýÁ÷תÈë500mlÈÝÁ¿Æ¿£¨ÌîдËùÐèÒÇÆ÷£©ÖУ¬ÔÙÓÃÊÊÁ¿ÕôÁóˮϴµÓÉÕ±­ºÍ²£Á§°ô2¡«3´ÎÒ»²¢×ªÈëÆäÖУ®
F£®ÓýºÍ·µÎ¹Ü¼ÓÕôÁóˮֱµ½ÈÜÒºÒºÃæÇ¡ºÃÓë¿ÌÏßÏàÇУ¬ÈûºÃÆ¿ÈûÒ¡Ôȼ´¿É£®
ÒÔÉϸ÷ʵÑé²½ÖèµÄÕýÈ·ÅÅÁÐ˳ÐòÊÇABDECF£®
ʵÑéÐòºÅµÎ¶¨¹ÜÒºÃæÆðʼ¶ÁÊýµÎ¶¨¹ÜÒºÃæÖÕµã¶ÁÊý
11.32mL23.36mL
22.26mL24.22mL
£¨2£©×¼È·ÒÆÈ¡20.00mL´ý²âNaOHÈÜÒºÓÚÒ»½à¾»×¶ÐÎÆ¿ÖУ¬È»ºóÓÃËùÅä±ê×¼ÑÎËáÈÜÒº½øÐе樣¨ÒÔ·Ó̪Ϊָʾ¼Á£©£®µÎ¶¨½á¹ûÈçÏÂ±í£º
¸ù¾ÝÒÔÉÏÊý¾Ý¼ÆËã³öδ֪NaOHÈÜÒºµÄÎïÖʵÄÁ¿Å¨¶ÈΪ0.22mol•L-1£¨¾«È·µ½0.01£©£®
£¨3£©ÏÂÁвÙ×÷»òÐðÊöÕýÈ·µÄÊÇBC£¨ÌîдÐòºÅ£©£®
A£®µÎ¶¨¹ý³ÌÖУ¬ÑÛ¾¦×¢Êӵζ¨¹ÜÄÚÈÜÒº²¢Ê¹ÊÓÏßÓëÒºÃæµÄ°¼Ãæˮƽ£®
B£®µÎ¶¨¹ý³ÌÖÐÓÉÓÚÒ¡¶¯×¶ÐÎƿʹÉÙÐíÈÜÒº½¦ÆðÕ´ÔÚÆ¿ÄÚ±Ú£¬ÎªÊ¹²â¶¨½á¹ûÕýÈ·£¬¿ÉÓÃÉÙÐíÕôÁóË®½«Æä³åÈë׶ÐÎÆ¿ÄÚµÄÈÜÒºÖУ®
C£®ÈÝÁ¿Æ¿ºÍµÎ¶¨¹ÜÔÚʹÓÃÇ°Ï´¾»ºó¶¼Òª¼ì²éÊÇ·ñ©Һ£®
D£®Ïò׶ÐÎÆ¿ÖÐÒÆÈ¡NaOHÈÜҺǰ£¬ÓÃÉÙÐíNaOHÈÜÒºÈóϴ׶ÐÎÆ¿2¡«3´Î£®
£¨4£©ÏÂÁвÙ×÷»òÏÖÏó»áµ¼Ö²ⶨ½á¹ûÆ«¸ßµÄÊÇACE£¨ÌîдÐòºÅ£©£®
A£®µÎ¶¨¹ý³ÌÖв»Ð¡ÐĽ«Ò»µÎÈÜÒºµÎÔÚ׶ÐÎÆ¿Í⣻
B£®µÎ¶¨½áÊøʱ£¬·¢ÏÖÔڵζ¨¹Ü¼â×ì´¦ÓÐСÆøÅÝ£»   
C£®µÎ¶¨½áÊøºóÑöÊӵζ¨¹ÜÒºÃæ¶ÁÊý£»
D£®ÈÜÒºÍÊÉ«Á¢¼´¶ÁÊý£¬Ò¡¶¯×¶ÐÎÆ¿ºó¿´µ½ÈÜÒººìÉ«¸´³ö£»
E£®ËáʽµÎ¶¨¹ÜÓÃÕôÁóˮϴ¾»ºó£¬Î´Óñê×¼ÑÎËáÈóÏ´£¬Ö±½Ó¼ÓÈë±ê×¼Òº½øÐе樣®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø