ÌâÄ¿ÄÚÈÝ

£¨13·Ö£©(1)ÈçͼËùʾװÖã¬ÎªÊµÏÖÏÂÁÐʵÑéÄ¿µÄ£¬ÆäÖÐy¶ËÊʺÏÓÚ×÷Èë¿ÚµÄÊÇ_____¶àÏ

A Æ¿ÄÚÊ¢ÒºÌå¸ÉÔï¼Á£¬ÓÃÒÔ¸ÉÔïÆøÌå
B Æ¿ÄÚÊ¢ÒºÌåÏ´µÓ¼Á£¬ÓÃÒÔ³ýȥijÆøÌåÖеÄÔÓÖÊ
C Æ¿ÄÚʢˮ£¬ÓÃÒÔ²âÁ¿Ä³ÄÑÈÜÓÚË®µÄÆøÌåµÄÌå»ý
D Æ¿ÄÚÖü´æÆøÌ壬¼ÓˮʱÆøÌå¿É±»Åųö
E ÊÕ¼¯ÃܶȱȿÕÆø´óµÄÆøÌå
F ÊÕ¼¯ÃܶȱȿÕÆøСµÄÆøÌå
(2) ŨH2SO4ºÍľ̿ÔÚ¼ÓÈÈʱ·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ_______________________¡£
ͼÖÐÐéÏß¿òÖеÄ×°ÖÿÉÓÃÀ´¼ìÑéŨÁòËáÓëľ̿·ÛÔÚ¼ÓÈÈÌõ¼þÏ·´Ó¦²úÉúµÄËùÓÐÆøÌå²úÎ

ÌîдÏÂÁпհס£
¢ÙAÖÐÎÞË®ÁòËáÍ­µÄ×÷ÓÃ_____________¡£
¢ÚÖ¤Ã÷SO2Ò»¶¨´æÔÚµÄÏÖÏóÊÇ_____________¡£
¢ÛCÖÐËáÐÔKMnO4ÈÜÒºµÄ×÷ÓÃ_____________¡£
¢ÜÖ¤Ã÷CO2Ò»¶¨´æÔÚµÄÏÖÏóÊÇ_____________¡£
£¨1£©    A B E    (2) C+2H2SO4CO2¡ü+2SO2¡ü+2H2O
¢Ù¼ìÑéË®ÕôÆø   ¢ÚBÖÐÆ·ºìÍÊÉ«   ¢Û³ýÈ¥SO2   ¢ÜDÖÐÆ·ºì²»ÍËÉ«£¬EÖбä»ë×Ç
£¨1£©ÓÉͼ¿ÉÒÔ¿´³öyµ¼¹Ü²åÈëµ½ÊÔ¼ÁÆ¿µÄµ×²¿£¬Òò´Ë¿ÉÓÃÀ´¸ÉÔïijЩÆøÌ壬Ҳ¿ÉÓÃÀ´³ýÈ¥ÆøÌåÖеÄijЩÔÓÖÊ£¬»òÕßÓÃÀ´ÊÕ¼¯ÃܶȴóÓÚ¿ÕÆøµÄijЩÆøÌå¡£ÈôÆ¿ÄÚʢˮ£¬ÓÃÒÔ²âÁ¿Ä³ÄÑÈÜÓÚË®µÄÆøÌåµÄÌå»ý£¬Ôò½øÆø¿ÚÓ¦ÊÇxµ¼¹Ü¡£Í¬ÑùÆ¿ÄÚÖü´æÄÑÈÜÓÚË®µÄÆøÌ壬¼ÓˮʱÆøÌå¿É±»Åųö£¬½øÆø¿ÚͬÑùÓ¦ÊÇxµ¼¹Ü¡£ÊÕ¼¯ÃܶȱȿÕÆøСµÄÆøÌ壬½øÆø¿ÚÓ¦ÊÇxµ¼¹Ü¡£¹ÊÕýÈ·µÄ´ð°¸ÊÇA B E¡£
£¨2£©Å¨ÁòËá¾ßÓÐÇ¿Ñõ»¯ÐÔ£¬ÔÚ¼ÓÈȵÄÌõ¼þÏ¿ÉÑõ»¯µ¥ÖÊ̼£¬·½³ÌʽΪC+2H2SO4CO2¡ü+2SO2¡ü+2H2O¡£²úÎïÓÐÈýÖÖË®ÕôÆø¡¢CO2ºÍSO2£¬Ñé֤ˮÕôÆøÓÃÎÞË®ÁòËáÍ­£¬CO2Óñ¥ºÍʯ»ÒË®£¬SO2ÓÃÆ·ºìÈÜÒº¡£ÓÉÓÚºóÁ½Õ߶¼ÐèҪͨ¹ýÈÜÒº£¬Òò´ËÊ×ÏÈÑé֤ˮÕôÆø¡£ÒòΪSO2Ò²¿ÉÒÔʹʯ»ÒË®±ä»ì×Ç£¬Òò´ËÔÚ¼ìÑéCO2֮ǰ£¬ÐèÒªÏȼìÑéSO2£¬²¢ÇÒ»¹ÒªÍêÈ«³ýÈ¥SO2£¬ÒÔ±ÜÃâ¸ÉÈÅCO2µÄ¼ìÑé¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
£¨15·Ö£©ÖÆÈ¡´¿¾»µÄÂÈ»¯Í­¾§Ì壨CuCl2¡¤2H2O£©µÄÉú²ú¹ý³ÌÈçÏ£º
I£®½«´ÖÑõ»¯Í­£¨º¬ÉÙÁ¿Fe£©ÈܽâÔÚ×ãÁ¿µÄÏ¡ÑÎËáÖУ¬È»ºó¼ÓÈÈ¡¢¹ýÂ˵õ½CuCl2£¨º¬ÉÙÁ¿FeCl2£©ÈÜÒº£¬¾­²â¶¨£¬ÈÜÒºpHΪ2¡£
II£®¶ÔIÖÐËùµÃµ½µÄÈÜÒº°´ÏÂÁв½Öè½øÐÐÌá´¿¡£

ÒÑÖª£º
 
ÇâÑõ»¯Î↑ʼ³ÁµíʱµÄpH
ÇâÑõ»¯Îï³ÁµíÍêȫʱµÄpH
Fe3+
1.9
3.2
Cu2+
4.7
6.7
   ÊԻشðÏÂÁÐÎÊÌ⣺
£¨1£©ÏÂÁÐÎïÖÊÖУ¬×îÊʺÏ×÷ΪÑõ»¯¼ÁXµÄÊÇ          ¡££¨ÌîÐòºÅ£©
A£®KMnO4        B£®K2Cr2O4              C£®H2O2                  D£®NaClO
£¨2£©¢Ù¼Ó½ôÈëµÄÎïÖÊYÊÇ             ¡£
¢Úд³ö³ÁµíZÔÚË®ÖеijÁµíÈܽâƽºâ·½³Ìʽ£º                 ¡£
£¨3£©·ÖÀë³ö³ÁµíZ£¬²¢½«ÂËÒºÕô·¢£¬Óû»ñµÃÂÈ»¯Í­¾§Ì壨CuCl2¡¤2H2O£©£¬Ó¦²ÉÈ¡µÄ´ëÊ©ÊÇ                                                 ¡£  
£¨4£©¢ÙijͬѧÀûÓ÷´Ó¦£ºCu+2H+===Cu2++H2¡üÉè¼ÆʵÑéÀ´ÖÆÈ¡CuCl2ÈÜÒº£¬¸ÃͬѧÉè¼ÆµÄ×°ÖÃÓ¦¸ÃΪ          ¡££¨Ìî¡°Ô­µç³Ø¡±»ò¡°µç½â³Ø¡±£©
¢ÚÇëÄãÔÚÏÂÃæ·½¿òÖл­³ö¸ÃͬѧÉè¼ÆµÄ×°ÖÃͼ£¬²¢Ö¸Ã÷µç¼«²ÄÁϺ͵ç½âÖÊÈÜÒº¡£

£¨5£©ÒÑ֪һЩÄÑÈÜÎïµÄŨ¶È»ý³£ÊýÈçÏÂ±í£º
ÎïÖÊ
FeS
MnS
CuS
PbS
HgS
ZnS
Ksp
6.3¡Á10-18
2.5¡Á-13
1.3¡Á10-36
3.4¡Á10-28
6.4¡Á10-53
1.6¡Á10-24
       Ä³¹¤Òµ·ÏË®Öк¬ÓÐCu2+¡¢Pb2+¡¢Hg2+£¬×îÊÊÒËÏò´Ë¹¤Òµ·ÏË®ÖмÓÈë¹ýÁ¿µÄ      ³ýÈ¥ËüÃÇ¡££¨Ñ¡ÌîÐòºÅ£©
¢ÙNaOH           ¢ÚFeS                      ¢ÛNa2S
£¨12·Ö£©Èý²ÝËáºÏÌúËá¼Ø¾§ÌåK3[Fe(C2O4 )3]¡¤3H2O¿ÉÓÃÓÚÉãÓ°ºÍÀ¶É«Ó¡Ë¢¡£Ä³Ð¡×齫ÎÞË®Èý²ÝËáºÏÌúËá¼ØÔÚÒ»¶¨Ìõ¼þϼÓÈȷֽ⣬¶ÔËùµÃÆøÌå²úÎïºÍ¹ÌÌå²úÎï½øÐÐʵÑéºÍ̽¾¿¡£ÇëÀûÓÃʵÑéÊÒ³£ÓÃÒÇÆ÷¡¢ÓÃÆ·ºÍÒÔÏÂÏÞÑ¡ÊÔ¼ÁÍê³ÉÑéÖ¤ºÍ̽¾¿¹ý³Ì¡£
ÏÞÑ¡ÊÔ¼Á£ºÅ¨ÁòËá¡¢1.0mol¡¤L-1HNO3¡¢1.0mol¡¤L-1ÑÎËá¡¢1.0mol¡¤L-1 NaOH¡¢3%H2O2¡¢0.1mol¡¤L-1KI¡¢0.1mol¡¤L-1CuSO4¡¢20% KSCN¡¢³ÎÇåʯ»ÒË®¡¢Ñõ»¯Í­¡¢ÕôÁóË®¡£
£¨1£©½«ÆøÌå²úÎïÒÀ´Îͨ¹ý³ÎÇåʯ»ÒË®£¨A£©¡¢Å¨ÁòËá¡¢×ÆÈÈÑõ»¯Í­£¨B£©¡¢³ÎÇåʯ»ÒË®£¨C£©£¬¹Û²ìµ½A¡¢CÖгÎÇåʯ»ÒË®¶¼±ä»ë×Ç£¬BÖÐÓкìÉ«¹ÌÌåÉú³É£¬ÔòÆøÌå²úÎïÊÇ       ¡£
£¨2£©¸ÃС×éͬѧ²éÔÄ×ÊÁϺóÍÆÖª£¬¹ÌÌå²úÎïÖУ¬ÌúÔªËز»¿ÉÄÜÒÔÈý¼ÛÐÎʽ´æÔÚ£¬¶øÑÎÖ»ÓÐK2CO3¡£ÑéÖ¤¹ÌÌå²úÎïÖмØÔªËØ´æÔڵķ½·¨ÊÇ        £¬ÏÖÏóÊÇ           
£¨3£©¹ÌÌå²úÎïÖÐÌúÔªËØ´æÔÚÐÎʽµÄ̽¾¿¡£
¢ÙÌá³öºÏÀí¼ÙÉè
¼ÙÉè1£º         £»¼ÙÉè2£º              £»¼ÙÉè3£º         ¡£
¢ÚÉè¼ÆʵÑé·½°¸Ö¤Ã÷ÄãµÄ¼ÙÉ裨²»ÒªÔÚ´ðÌ⿨ÉÏ×÷´ð£©
¢ÛʵÑé¹ý³Ì
¸ù¾Ý¢ÚÖз½°¸½øÐÐʵÑé¡£ÔÚ´ðÌ⿨ÉÏ°´Ï±íµÄ¸ñʽд³öʵÑé²½Öè¡¢Ô¤ÆÚÏÖÏóÓë½áÂÛ¡£
ʵÑé²½Öè
Ô¤ÆÚÏÖÏóÓë½áÂÛ
²½Öè1£º
 
²½Öè2£º
 
²½Öè3£º
 
¡­¡­
 

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø