ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿ÏÖÓÐX£¬Y£¬Z£¬MËÄÖÖÔªËؾùΪ¶ÌÖÜÆÚÔªËØ£®ÓйØÐÅÏ¢ÈçÏÂ±í£º
Ô×Ó»ò·Ö×ӽṹ¡¢µ¥ÖÊ»ò»¯ºÏÎïÏà¹ØÐÅÏ¢ | |
X | º¬XÔªËصÄÎïÖÊÑæÑÕÉ«·´Ó¦Îª»ÆÉ« |
Y | µ¥ÖÊΪ˫Ô×Ó·Ö×Ó£®ÈôµÍÎÂÕô·¢ÒºÌ¬¿ÕÆø£¬ÒòÆä·Ðµã½ÏµÍ¿ÉÏÈ»ñµÃYµÄµ¥ÖÊ |
Z | ZÔªËØÔ×ÓÒ×ʧȥ2¸öµç×ÓÐγÉ8µç×ӽṹµÄÀë×Ó |
M | MÔªËØÔ×ÓµÄ×îÍâ²ãµç×ÓÊýÊÇK²ãµç×ÓÊýµÄ3±¶£¬MÓëX´¦ÓÚͬһÖÜÆÚ |
£¨1£©XÔªËØÔÚÖÜÆÚ±íµÄλÖÃÊÇ£»
£¨2£©1¸öYµ¥ÖÊ·Ö×ÓÖк¬¶Ô¸ö¹²Óõç×Ó¶Ô£»
£¨3£©ZÄÜÔÚCO2ÆøÌåÖÐȼÉÕ£¬Æ仯ѧ·´Ó¦·½³ÌʽΪ £®
£¨4£©»¯ºÏÎïX2MÈÜÒºÔÚ¿ÕÆøÖг¤ÆÚ·ÅÖã¬ÓëÑõÆø·´Ó¦»áÉú³ÉÓë¹ýÑõ»¯ÄƵĽṹºÍ»¯Ñ§ÐÔÖÊÏàËƵÄÎïÖÊX2M2 £¬ ÆäÈÜÒºÏÔ»ÆÉ«£®ÔòX2M2µÄµç×ÓʽΪ £¬ Óû¯Ñ§·½³Ìʽ±íʾX2MÈÜÒºÔÚ¿ÕÆøÖеıäÖʹý³Ì £®
¡¾´ð°¸¡¿
£¨1£©µÚÈýÖÜÆÚµÚIA×å
£¨2£©3
£¨3£©2Mg+CO2 2MgO+C
£¨4£©£»4Na2S+O2+2H2O¨T4NaOH+2Na2S2
¡¾½âÎö¡¿½â£ºX¡¢Y¡¢Z¡¢MËÄÖÖÔªËؾùΪ¶ÌÖÜÆÚÔªËØ£¬º¬XÔªËصÄÎïÖÊÑæÉ«·´Ó¦Îª»ÆÉ«£¬ÔòXΪNa£»Yµ¥ÖÊΪ˫Ô×Ó·Ö×Ó£¬ÈôµÍÎÂÕô·¢ÒºÌ¬¿ÕÆø£¬ÒòÆä·Ðµã½ÏµÍ¿ÉÏÈ»ñµÃYµÄµ¥ÖÊ£¬ÔòYΪNÔªËØ£»ZÔªËØÔ×ÓÒ×ʧȥ2¸öµç×ÓÐγÉ8µç×ӽṹµÄÀë×Ó£¬ÔòZΪMg£»MÔªËØÔ×ÓµÄ×îÍâ²ãµç×ÓÊýÊÇK²ãµç×ÓÊýµÄ3±¶£¬×îÍâ²ãµç×ÓÊýΪ6£¬MÓëX´¦ÓÚͬһÖÜÆÚ£¬ÔòMΪSÔªËØ£¬£¨1£©XΪNaÔªËØ£¬ÔÚÖÜÆÚ±íÖеÚÈýÖÜÆÚµÚ¢ñA×壬ËùÒÔ´ð°¸ÊÇ£ºµÚÈýÖÜÆÚµÚ¢ñA×壻£¨2£©YΪNÔªËØ£¬1¸öµ¥ÖÊ·Ö×ÓÖк¬3¸ö¹²Óõç×Ó¶Ô£¬ËùÒÔ´ð°¸ÊÇ£º3£»£¨3£©MgÔÚCO2ÆøÌåÖÐȼÉÕÉú³ÉMgOÓëC£¬Æ仯ѧ·´Ó¦·½³ÌʽΪ2Mg+CO2 2MgO+C£¬ËùÒÔ´ð°¸ÊÇ£º2Mg+CO2 2MgO+C£»£¨4£©»¯ºÏÎïNa2SÈÜÒºÔÚ¿ÕÆøÖг¤ÆÚ·ÅÖã¬ÓëÑõÆø·´Ó¦»áÉú³ÉÓë¹ýÑõ»¯ÄƵĽṹºÍ»¯Ñ§ÐÔÖÊÏàËƵÄÎïÖÊX2M2 £¬ X2M2ΪNa2S2 £¬ ´ËÈÜÒºÏÔ»ÆÉ«£¬Æäµç×ÓʽΪ£º £¬Óû¯Ñ§·½³Ìʽ±íʾX2MÈÜÒºÔÚ¿ÕÆøÖеıäÖʹý³ÌΪ£º4Na2S+O2+2H2O¨T4NaOH+2Na2S2 £¬ ËùÒÔ´ð°¸ÊÇ£º £»4Na2S+O2+2H2O¨T4NaOH+2Na2S2 £®
¡¾ÌâÄ¿¡¿½ðÊôîÑ£¨Ti£©ÒòÆäÓ²¶È´ó¡¢ÈÛµã¸ß¡¢³£ÎÂʱÄÍËá¼î¸¯Ê´¶ø±»¹ã·ºÓÃ×÷¸ßпƼ¼²ÄÁÏ£¬±»ÓþΪ¡°Î´À´½ðÊô¡±¡£ÒÔîÑÌú¿ó£¨Ö÷Òª³É·ÖîÑËáÑÇÌú£©ÎªÖ÷ÒªÔÁÏÒ±Á¶½ðÊôîÑͬʱ»ñµÃ¸±²úÆ·¼×µÄ¹¤ÒµÉú²úÁ÷³ÌÈçÏ¡£Çë»Ø´ðÏÂÁÐÎÊÌâ¡£
£¨1£©îÑËáÑÇÌú£¨ÓÃR±íʾ£©Óë̼ÔÚ¸ßÎÂÏ·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ2R+C¨T2Fe+2TiO2+CO2¡ü£¬îÑËáÑÇÌúµÄ»¯Ñ§Ê½Îª_______________£»îÑËáÑÇÌúºÍŨH2SO4·´Ó¦µÄ²úÎïÖ®Ò»ÊÇTiOSO4£¬·´Ó¦ÖÐÎÞÆøÌåÉú³É£¬¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ____________________¡£
£¨2£©ÉÏÊöÉú²úÁ÷³ÌÖмÓÈëÌúмµÄÄ¿µÄÊÇ_________________________£¬´ËʱÈÜÒº¢ñÖк¬ÓÐFe2+¡¢TiO2+ºÍÉÙÁ¿Mg2+µÈÑôÀë×Ó¡£³£ÎÂÏ£¬Æä¶ÔÓ¦ÇâÑõ»¯ÎïµÄKspÈçϱíËùʾ¡£
ÇâÑõ»¯Îï | Fe(OH)2 | TiO(OH)2 | Mg(OH)2 |
Ksp | 8.0¡Á10-16 | 1.0¡Á10-29 | 1.8¡Á10-11 |
¢Ù³£ÎÂÏ£¬ÈôËùµÃÈÜÒºÖÐMg2+µÄÎïÖʵÄÁ¿Å¨¶ÈΪ0.0018mol/L£¬µ±ÈÜÒºµÄpHµÈÓÚ_______ʱ£¬Mg(OH)2¿ªÊ¼³Áµí¡£
¢ÚÈô½«º¬ÓÐFe2+¡¢TiO2+ºÍMg2+µÄÈÜÒº¼ÓˮϡÊÍ£¬Á¢¼´Îö³ö´óÁ¿°×É«³Áµí£¬¸Ã·´Ó¦µÄÀë×Ó·½³ÌʽΪ___________________________________________________________¡£
£¨3£©Öмä²úÆ·ÒÒÓ뽹̿¡¢ÂÈÆøÔÚ¸ßÎÂÏ·¢Éú·´Ó¦ÖÆÈ¡TiCl4µÄ·½³ÌʽΪ________¡£Mg»¹ÔTiCl4¹ý³ÌÖбØÐëÔÚ1070KµÄζÈϽøÐУ¬ÄãÈÏΪ»¹Ó¦¸Ã¿ØÖƵķ´Ó¦Ìõ¼þÊÇ_________¡£³ýÈ¥ËùµÃ½ðÊôîÑÖÐÉÙÁ¿µÄ½ðÊôþ¿ÉÓõÄÊÔ¼ÁÊÇ__________________¡£