ÌâÄ¿ÄÚÈÝ

Òø¾µ·´Ó¦ÊǼìÑéÈ©»ùµÄÖØÒª·´Ó¦£¬½Ì²Ä¶Ô¸ÃʵÑéµÄ²Ù×÷Ìõ¼þÖ»ÊÇ´ÖÂÔµÄÃèÊö¡£Ä³Í¬Ñ§½øÐÐÈçÏÂÑо¿£º
£¨1£©Ôڸɾ»ÊÔ¹ÜÖмÓÈë2ml2£¥                            £¬È»ºó£¬                   µÃµ½Òø°±ÈÜÒº£¬·Ö×°Èë5Ö§ÊԹܣ¬±àºÅΪ1#£®2#£®3#£®4#£®5# ¡£
£¨2£©ÒÀ´ÎµÎ¼Ó2%£®5%£®10%£®20%£®40%µÄÒÒÈ©ÈÜÒº4µÎ£¬¿ìËÙÕñµ´ºóÖÃÓÚ60¡æ~70¡æµÄˮԡÖС£3·ÖÖÓºó£¬ÊÔ¹Ü1#δÐγɴóÃæ»ýÒø¾µ£¬ÊÔ¹Ü5# µÄÒø¾µÖÊÁ¿²îÓкڰߣ¬ ÊÔ¹Ü4# ²úÉúµÄÒø¾µÖÊÁ¿Ò»°ã£¬ÊÔ¹Ü2#£®3# ÐγɹâÁÁµÄÒø¾µ¡£
¸ÃÑо¿µÄÄ¿µÄÊÇ£º                                                           ¡£
£¨3£©ÒÒÈ©·¢ÉúÒø¾µ·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º                                           £¬
£¨4£©ÓÐÎÄÏ×¼ÇÔØ:ÔÚÇ¿¼îÐÔÌõ¼þÏ£¬¼ÓÈÈÒø°±ÈÜÒº¿ÉÄÜÎö³öÒø¾µ¡£ÑéÖ¤ºÍ¶Ô±ÈʵÑéÈçÏ¡£
×°ÖÃ
ʵÑéÐòºÅ
ÊÔ¹ÜÖеÄÒ©Æ·
ÏÖÏó

ʵÑé¢ñ
2mLÒø°±ÈÜÒººÍÊýµÎ½ÏŨNaOHÈÜÒº
ÓÐÆøÅݲúÉú:
Ò»¶Îʱ¼äºó£¬ÈÜÒºÖð½¥±äºÚ:ÊԹܱڸ½×ÅÒø¾µ
ʵÑé¢ò
2mLÒø°±ÈÜÒººÍ
ÊýµÎŨ°±Ë®
ÓÐÆøÅݲúÉú:Ò»¶Îʱ¼äºó£¬ÈÜÒºÎÞÃ÷ÏԱ仯
 
¸ÃͬѧÓû·ÖÎöʵÑé¢ñºÍʵÑé¢òµÄ²îÒ죬²éÔÄ×ÊÁϺ󣬵ÃÖª:
a£®Ag(NH3)2++2H2OAg++2NH3¡¤H2O¡¡    b£®AgOH²»Îȶ¨£¬¼«Ò×·Ö½âΪºÚÉ«Ag2O
¾­¼ìÑ飬ʵÑé¢ñµÄÆøÌåÖÐÓÐNH3,ºÚÉ«ÎïÖÊÖÐÓÐAg2O¡£²úÉúAg2OµÄÔ­ÒòÊÇ£º
¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡                                                 ¡£
£¨5£©ÓÃʪÈóµÄºìɫʯÈïÊÔÖ½¼ìÑéNH3²úÉúµÄÏÖÏóÊÇ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡ ¡£ÓÃÏ¡HNO3Çå  Ï´ÊԹܱÚÉϵÄAg£¬¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡ ¡¡    ¡¡¡¡¡¡¡¡ ¡£
£¨6£©¸Ãͬѧ¶Ô²úÉúÒø¾µµÄÔ­ÒòÌá³ö¼ÙÉè:ÔÚNaOH´æÔÚÏ£¬¿ÉÄÜÊÇNH3»¹Ô­Ag2O¡£Èç¹û¸Ã¼ÙÉè³ÉÁ¢£¬Ôò˵Ã÷¼ìÑéÈ©»ùʱ£¬Òø°±ÈÜÒº²»ÄܳÊÇ¿¼îÐÔ£¬ÒòΪ£º
                                                               
£¨1£©AgNO3ÈÜÒº, ÖðµÎ¼ÓÈëÏ¡°±Ë®,Ö±µ½×î³õ²úÉúµÄ°×É«³ÁµíÏûʧΪֹ¡£
£¨2£©Ì½¾¿Òø¾µ·´Ó¦ÊµÑéÖУ¬ÒÒÈ©ÈÜÒºµÄŨ¶ÈÓëÏÖÏóµÄ¹Øϵ
£¨3£©
£¨4£©ÔÚNaOH´æÔÚÏ£¬¼ÓÈÈʹNH3Òݳö£¬´ÙʹƽºâAg(NH3)2 + + 2H2O ¡¡¡¡Ag++ 2NH3¡¤H2OÕýÏòÒƶ¯£¬c£¨Ag+£©Ôö´ó£¬Ag+ÓëOH£­·´Ó¦Á¢¼´×ª»¯ÎªAg2O¡£
£¨5£©ÊÔÖ½±äÀ¶; 4HNO3£¨Ï¡£©+ 3Ag¡ú3AgNO3+ NO¡ü+2H2O  
£¨6£©ÔÚÇ¿¼îÐÔÌõ¼þÏ£¬Òø°±ÈÜÒº±¾ÉíÒ²ÄÜÐγÉÒø¾µ£¬ÎÞÐ뺬ȩ»ù»¯ºÏÎï

ÊÔÌâ·ÖÎö£º£¨2£©¸Ä±äÒÒȩŨ¶È£¬¹Û²ìÏÖÏó¡£ËùÒÔ£¬Ì½¾¿Òø¾µ·´Ó¦ÊµÑéÖУ¬ÒÒÈ©ÈÜÒºµÄŨ¶ÈÓëÏÖÏóµÄ¹Øϵ¡£
£¨4£©Fe2£«±»¿ÕÆøÑõ»¯³ÉFe3£«£»Fe3£«ÓëKSCN·´Ó¦£¬±äѪºìÉ«¶øFe2£«²»ÄÜ¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
¢ñ£®ÏÂÁÐÓйزÙ×÷ÕýÈ·µÄÊÇ        _¡£
¢ÙFeBr3×÷´ß»¯¼Á£¬±½ºÍäåË®·¢Éú·´Ó¦¿ÉÉú³ÉÎÞÉ«¡¢±ÈË®ÖصÄÒºÌåäå±½
¢Ú½«Í­Ë¿Íä³ÉÂÝÐý×´£¬Ôھƾ«µÆÉϼÓÈȱäºÚºó£¬Á¢¼´ÉìÈëÊ¢ÓÐÎÞË®ÒÒ´¼µÄÊÔ¹ÜÖУ¬ÊµÏÖÒÒ´¼±»Ñõ»¯ÎªÒÒÈ©µÄʵÑé
¢ÛÓÃCuºÍAg×÷ΪÁ½¼«£¬H2SO4ÈÜÒº×÷Ϊµç½âÖÊÈÜÒº£¬¿ÉÒÔ¹¹³ÉÔ­µç³Ø
¢ÜΪÁË·ÀÖ¹×ÔÀ´Ë®¹ÜÉúÐ⣬һ°ãÔÚ±íÃæ¶ÆÉÏÒ»²ãZn
¢ÝʹÓÃAgNO3ÈÜÒºÑéÖ¤ÈýÂȼ×ÍéÖÐÊÇ·ñº¬ÓÐÂÈÔªËØ£¬ÏÖÏóÊDzúÉú°×É«³Áµí
A.¢Ú¢Ü        B.¢Ù¢Ú        C.¢Û¢Ý        D.¢Ü¢Þ   
¢ò. ÒÒËáÒÒõ¥ÊÇÖØÒªµÄÓлúºÏ³ÉÖмäÌ壬¹ã·ºÓ¦ÓÃÓÚ»¯Ñ§¹¤Òµ¡£ÊµÑéÊÒÀûÓÃÓÒͼµÄ×°ÖÃÖƱ¸ÒÒËáÒÒõ¥¡£

£¨1£©Óë½Ì²Ä²ÉÓõÄʵÑé×°Öò»Í¬£¬´Ë×°ÖÃÖвÉÓÃÁËÇòÐθÉÔï¹Ü£¬Æä×÷ÓÃ
ÊÇ£º                          ¡£
£¨2£©ÒÑ֪ϱíÊý¾Ý£º
ÎïÖÊ
ÈÛµã/¡æ
·Ðµã/¡æ
ÃܶÈ/£¨g/cm3£©
ÒÒ´¼
-144
78
0.789
ÒÒËá
16.6
117.9
1.05
ÒÒËáÒÒõ¥
-83.6
77.5
0.90
ŨÁòËá
¡ª¡ª
338
1.84
¢Ù°´×°ÖÃͼ°²×°ºÃÒÇÆ÷ºó£¬ÐèÒªÊÔ¼ÁΪ3 ml ÒÒ´¼£¬2 mlÒÒËᣬÊÊÁ¿Å¨ÁòËᣬÇëÑ¡ÔñºÏÊʵļÓÈë˳Ðò           ¡£
A. ÏȼÓŨÁòËᣬÔÙ¼ÓÒÒ´¼£¬×îºó¼ÓÒÒËá 
B. ÏȼÓÒÒ´¼£¬ÔÙ¼ÓŨÁòËᣬ×îºó¼ÓÒÒËá
C. ÏȼÓÒÒËᣬÔÙ¼ÓŨÁòËᣬ×îºó¼ÓÒÒ´¼
D. ÏȼÓŨÁòËᣬÔÙ¼ÓÒÒËᣬ×îºó¼ÓÒÒ´¼
¢Ú¸ù¾ÝÉϱíÊý¾Ý·ÖÎö£¬ÎªÊ²Ã´ÒÒ´¼ÐèÒª¹ýÁ¿Ò»Ð©£¬ÆäÔ­ÒòÊÇ               ¡£
£¨3£©°´ÕýÈ·²Ù×÷ÖØÐÂʵÑ飬¸ÃѧÉúºÜ¿ìÔÚСÊÔ¹ÜÖÐÊÕ¼¯µ½ÁËÒÒËáÒÒõ¥¡¢ÒÒËá¡¢ÒÒ´¼µÄ»ìºÏÎï¡£ÏÖÄâ·ÖÀ뺬ÒÒËá¡¢ÒÒ´¼ºÍË®µÄÒÒËáÒÒõ¥´Ö²úÆ·£¬ÏÂͼÊÇ·ÖÀë²Ù×÷²½ÖèÁ÷³Ìͼ¡£ÔÚͼÖÐÔ²À¨ºÅ±íʾ¼ÓÈëÊʵ±µÄÊÔ¼Á£¬±àºÅ±íʾÊʵ±µÄ·ÖÀë·½·¨¡£

¢Ùд³ö¼ÓÈëµÄÊÔ¼ÁÃû³Æ£º ÊÔ¼Á£¨a£©ÊÇ           £»ÊÔ¼Á£¨b£©ÊÇ          ¡£
¢Úд³öÓйصIJÙ×÷·ÖÀë·½·¨£º¢ÙÊÇ      £¬¢ÚÊÇ         £¬¢ÛÊÇ         ¡£
£¨14·Ö£©ÏÂÃæÊǼס¢ÒÒ¡¢±ûÈýλͬѧÖÆÈ¡ÒÒËáÒÒõ¥µÄ¹ý³Ì£¬ÇëÄã²ÎÓ벢ЭÖúËûÃÇÍê³ÉÏà¹ØʵÑéÈÎÎñ¡£
[ʵÑéÄ¿µÄ]ÖÆÈ¡ÒÒËáÒÒõ¥
[ʵÑéÔ­Àí]¼×¡¢ÒÒ¡¢±ûÈýλͬѧ¾ù²ÉÈ¡ÒÒ´¼(CH3CH218OH)¡¢ÒÒËáÓëŨÁòËá»ìºÏ¹²Èȵķ½·¨ÖÆÈ¡ÒÒËáÒÒõ¥£¬ÆäÖÐŨÁòËá³ýÁË×÷ÎüË®¼ÁµÄ×÷ÓÃÍ⻹ÓР     
[×°ÖÃÉè¼Æ]¼×¡¢ÒÒ¡¢±ûÈýλͬѧ·Ö±ðÉè¼ÆÁËÏÂÁÐÈýÌ×ʵÑé×°Öãº
Çë´Ó¼×¡¢ÒÒÁ½Î»Í¬Ñ§Éè¼ÆµÄ×°ÖÃÖÐÑ¡ÔñÒ»ÖÖ×÷ΪʵÑéÊÒÖÆÈ¡ÒÒËáÒÒõ¥µÄ×°Öã¬ÎÒÑ¡ÔñµÄ×°ÖÃÊÇ       (Ñ¡Ìî ¡°¼×¡±»ò ¡°ÒÒ¡±)¡£±ûͬѧ½«¼××°ÖÃÖеIJ£Á§¹Ü¸Ä³ÉÁËÇòÐθÉÔï¹Ü³ýÆðÀäÄý×÷ÓÃÍ⣬ËüµÄÁíÒ»ÖØÒª×÷ÓÃÊÇ           

[ʵÑé²½Öè](1)°´Ñ¡ÔñµÄ×°ÖÃ×é×°ÒÇÆ÷£¬ÔÚÊÔ¹ÜÖÐÏȼÓÈë3mLCH3CH218OH£¬2mL±ù´×Ëᣬ²¢ÔÚÒ¡¶¯Ï»º»º¼ÓÈë2mLŨÁòËá³ä·ÖÒ¡ÔÈ£¬ (2)½«ÊԹ̶ܹ¨ÔÚÌú¼ÜÉÏ£»(3)ÔÚÊԹܢÚÖмÓÈËÊÊÁ¿µÄ±¥ºÍNa2CO3ÈÜÒº£»(4)Óþƾ«µÆ¶ÔÊԹܢټÓÈÈ£»(5)µ±¹Û²ìµ½ÊԹܢÚÖÐÓÐÃ÷ÏÔÏÖÏóʱֹͣʵÑé¡£
[ÎÊÌâÌÖÂÛ]a£®¸ù¾ÝÊԹܢÚÖй۲쵽µÄÏÖÏ󣬿ÉÖªÒÒËáÒÒõ¥µÄÎïÀíÐÔÖÊÓУº
ÎÞÉ«ÓÍ×´ÒºÌå¡¢                                     £»
b£®ÊÔ¹Ü ¢Ú Öб¥ºÍ Na2CO3µÄ×÷ÓÃÊÇÈܽâÒÒ´¼¡¢½µµÍÒÒËáÒÒõ¥µÄÈܽâ¶È»¹ÓР µÄ×÷ÓÃ
c£® ´ÓÊԹܢÚÖзÖÀë³öÒÒËáÒÒõ¥µÄʵÑé²Ù×÷ÊÇ               
d£® Éú³ÉÒÒËáÒÒõ¥µÄ»¯Ñ§·´Ó¦·½³Ìʽ                               

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø