ÌâÄ¿ÄÚÈÝ

¡¾ÌâÄ¿¡¿ÎÒ¹úÓзḻµÄº£Ë®×ÊÔ´£¬¿ª·¢ºÍÀûÓú£Ë®×ÊÔ´Êǵ±Ç°¿ÆѧÑо¿µÄÒ»ÏîÖØÒªÈÎÎñ¡£

£¨1£©±»³Æ×÷º£ÑóÔªËصÄÊÇ_________________£¨Ð´ÔªËØ·ûºÅ£©¡£

£¨2£©¹¤ÒµÉϳ£ÒÔ±¥ºÍʳÑÎˮΪԭÁÏÖƱ¸ÂÈÆø£¬Çëд³ö·´Ó¦µÄ»¯Ñ§·´Ó¦·½³Ìʽ___________¡£

£¨3£©´Óº£Ë®ÖÐÌáȡʳÑκÍäåµÄ¹ý³ÌÈçÏ£º

¢Ù²½Öè¢ñÖÐÒÑ»ñµÃBr2£¬²½Öè¢òÖÐÓÖ½«Br2»¹Ô­ÎªBr£­£¬ÆäÄ¿µÄΪ¸»¼¯äåÔªËØ£¬Çëд³ö²½Öè¢òµÄ»¯Ñ§·½³Ìʽ___¡£

¢Ú²½Öè¢òÖÐͨÈë¿ÕÆø´µ³öä壬ÊÇÀûÓÃÁËäåµÄ___ÐÔÖÊ£¬²½Öè¢óµÃµ½¹¤ÒµäåµÄ»¯Ñ§·½³ÌʽΪ£º______¡£

¡¾´ð°¸¡¿Br 2NaCl+2H2OCl2¡ü+H2¡ü+2NaOH SO2+Br2+2H2O£½H2SO4+2HCl »Ó·¢ÐÔ 2HBr+Cl2£½Br2+2HCl

¡¾½âÎö¡¿

º£Ë®Í¨¹ýº£Ë®µ­»¯ºóµÃµ½ÂÈ»¯ÄÆ¡¢Ä¸ÒººÍµ­Ë®£¬µç½âÂÈ»¯ÄÆ¿ÉÒԵõ½ÂÈÆø£¬ÂÈÆø°ÑĸҺÖеÄäåÀë×ÓÑõ»¯Îªµ¥ÖÊä壬º¬µÍŨ¶ÈÊÇäåË®ÎüÊÕ¶þÑõ»¯Áòת»¯Îªä廯ÇâºÍÁòËáµÄ»ìºÏÈÜÒº£¬×îºóÔÚͨÈëÊÊÁ¿ÂÈÆøµÃµ½¹¤Òµä壬¾Ý´Ë½â´ð¡£

£¨1£©±»³Æ×÷º£ÑóÔªËصÄÊÇä壬ԪËØ·ûºÅÊÇBr¡£

£¨2£©¹¤ÒµÉϳ£ÒÔ±¥ºÍʳÑÎˮΪԭÁÏÖƱ¸ÂÈÆø£¬·´Ó¦µÄ»¯Ñ§·´Ó¦·½³ÌʽΪ2NaCl+2H2OCl2¡ü+H2¡ü+2NaOH¡£

£¨3£©¢Ù²½Öè¢ñÖÐÒÑ»ñµÃBr2£¬²½Öè¢òÖÐÓÖ½«Br2»¹Ô­ÎªBr£­£¬ÆäÄ¿µÄΪ¸»¼¯äåÔªËØ£¬³ö²½Öè¢òÊÇÀûÓõ¥ÖÊäåÑõ»¯¶þÑõ»¯Áò£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪSO2+Br2+2H2O£½H2SO4+2HBr¡£

¢Ú²½Öè¢òÖÐͨÈë¿ÕÆø´µ³öä壬ÊÇÀûÓÃÁËäåµÄ»Ó·¢ÐÔ£¬²½Öè¢óµÃµ½¹¤ÒµäåµÄ»¯Ñ§·½³ÌʽΪ2HBr+Cl2£½Br2+2HCl¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

¡¾ÌâÄ¿¡¿ÎªÌ½¾¿²»Í¬Ìõ¼þϸÊÓÍ(±ûÈý´¼)ºÍÐÁËáõ¥»¯ºÏ³É¸ÊÓͶþõ¥µÄ×î¼ÑÌõ¼þ£¬¿ÆÑй¤×÷Õß×öÁ˸ÊÓͶþõ¥µÄø·¨ºÏ³É¹¤ÒÕÑо¿¡£

ʵÑé1£ºÑо¿²»Í¬Í¶ÁϱȶԲúÂʵÄÓ°Ïì

(1)ÀíÂÛ·ÖÎöºÏ³É¸ÊÓͶþõ¥ËùÐèÐÁËáÓë¸ÊÓ͵ÄͶÁϱÈ(ÎïÖʵÄÁ¿Ö®±È)Ϊ2¡Ã1¡£ÊµÑéÖ¤Ã÷Ìá¸ßͶÁϱȣ¬¸ÊÓͶþõ¥µÄ²úÂʻήµÍ£¬ÆäÔ­Òò¿ÉÄÜÊÇ_______¡£

ʵÑé2£ºÑо¿ÎüË®¼Á¶Ô·´Ó¦µÄÓ°Ïì

(2)¹è½ºÒ×ÓëôÇ»ù½áºÏ£¬¹ÊÓнÏÇ¿µÄÇ×Ë®ÐÔ£¬Ò×ÓÚÎü¸½Ë®·Ö×Ó¡£µ«ÊÇÔÚ·´Ó¦ÌåϵÀï¼ÓÈë¹è½ººó¸ÊÓͶþõ¥º¬Á¿Ã÷ÏÔ½µµÍ£¬ËµÃ÷ºÏ³É¸ÊÓͶþõ¥µÄƽºâ·¢ÉúÁËÄæÏòÒƶ¯£¬·ÖÎö¿ÉÄܵÄÔ­ÒòÊÇ________¡£

ʵÑé3£ºÑо¿²»Í¬´ß»¯¼ÁµÄ´ß»¯Ð§¹û

ÇúÏß

´ß»¯¼Á

×Ý×ø±ê

¢Ù

Ö¬·¾Ã¸IºÅ

ÐÁËáת»¯ÂÊ

¢Ú

Ö¬·¾Ã¸IIºÅ

ÐÁËáת»¯ÂÊ

¢Û

Ö¬·¾Ã¸IºÅ

¸ÊÓͶþõ¥º¬Á¿

¢Ü

Ö¬·¾Ã¸IIºÅ

¸ÊÓͶþõ¥º¬Á¿

(3)ÆäËûÌõ¼þÏàͬʱ£¬²»Í¬Ö¬·¾Ã¸(IºÅ¡¢IIºÅ)´ß»¯ºÏ³É¸ÊÓͶþõ¥µÄЧ¹ûÈçͼËùʾ£¬Ñ¡Ôñ´ËʵÑéÖд߻¯Ð§¹ûÏà¶Ô×î¼ÑµÄ·´Ó¦Ìõ¼þÊÇ________(Ìî×ÖĸÐòºÅ)¡£

A£®12 h£¬IºÅ B£®24 h£¬IºÅ

C£®12 h£¬IIºÅ D£®24 h£¬IIºÅ

ʵÑé4£ºÑо¿Î¶ȶԷ´Ó¦ËÙÂʺͲúÂʵÄÓ°Ïì

(4)Ñ¡¶¨Ö¬·¾Ã¸×ö´ß»¯¼Á£¬¼ÌÐøʵÑé¡£

¢Ù×ÛºÏÉÏͼ£¬Ñ¡Ôñ6 hʱ±È½ÏÊÊÒ˵ķ´Ó¦Î¶ÈÊÇ________¡£

¢ÚÔÚ6 hÖ®ºó£¬ÐÁËáµÄת»¯ÂÊ×ÜÇ÷ÊÆ»ºÂýÉÏÉý£¬30¡æ¡¢40¡æ¸ÊÓͶþõ¥µÄº¬Á¿ÉÏÉý£¬µ«ÊÇ50¡æµÄÈ´ÓÐËù½µµÍ£¬·ÖÎö¿ÉÄܵÄÔ­ÒòÊÇ________¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø