题目内容
【题目】已知:Fe2O3(s)+C(s)=CO2(g)+2Fe(s)△H=+234.1kJmol﹣1
C(s)+O2(g)=CO2(g)△H=﹣393.5kJmol﹣1
则2Fe(s)+O2(g)=Fe2O3(s)的△H是( )
A. ﹣824.4kJmol﹣ B. ﹣627.6kJmol﹣1 C. +744.7kJmol﹣1 D. ﹣169.4kJmol﹣1
【答案】A
【解析】已知:①Fe2O3(s)+ C(s)= CO2(g)+2Fe(s)△H=+234.1kJmol-1,②C(s)+O2(g)=CO2(g)△H=-393.5kJmol-1,由盖斯定律②×-①,得:2Fe(s)+ O2(g)=Fe2O3(s)△H=(-393.5kJmol-1)×-234.1kJmol-1,即2Fe(s)+ O2(g)=Fe2O3(s)△H=-824.35kJmol-1,故选A。
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