ÌâÄ¿ÄÚÈÝ

ÏÂÁнâÊÍʵÑéÏÖÏóµÄ·´Ó¦·½³ÌʽÕýÈ·µÄÊÇ(¡¡¡¡)
A£®ÔÚCH3COONaÈÜÒºÖÐ,µÎ¼Ó·Ó̪ÈÜÒº±äºì:
CH3COO-+H2OCH3COOH+OH-
B£®ÔÚH2O2ÈÜÒºÖÐ,µÎ¼ÓFeCl3ÈÜÒº²úÉúÆøÅÝ:
2H2O2+2Cl-2H2O+O2¡ü+Cl2¡ü
C£®½«Ï໥½Ó´¥µÄͭƬºÍпƬÖÃÓÚÏ¡ÁòËáÖÐ,ͭƬ±íÃæÓÐÆøÅݲúÉú:
Cu+2H+Cu2++H2¡ü
D£®ÏòCu(OH)2Ðü×ÇÒºÖеμÓNa2SÈÜÒº,À¶É«³Áµí±äºÚÉ«:
Cu(OH)2(s)+S2-CuS(s)+2OH-
D
AÑ¡ÏîΪ¿ÉÄæ·´Ó¦;BÑ¡Ïî²»»áÉú³ÉÂÈÆø;CÑ¡ÏîZnʧµç×Ó,H+ÔÚͭƬÉϵõç×Ó,Ö»ÓÐDÑ¡ÏîÕýÈ·
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
Ðí¶àÁòµÄº¬ÑõËáÑÎÔÚÒ½Ò©¡¢»¯¹¤µÈ·½ÃæÓÐ×ÅÖØÒªµÄÓÃ;¡£
£¨1£©Öؾ§Ê¯(BaSO4)³£×ö賦µÀÔìÓ°¼Á¡£ÒÑÖª£º³£ÎÂÏ£¬Ksp(BaSO4)£½1.1¡Á10£­10¡£ÏòBaSO4Ðü×ÇÒºÖмÓÈëÁòËᣬµ±ÈÜÒºµÄpH£½2ʱ£¬ÈÜÒºÖÐc(Ba2£«)£½                        £»
£¨2£©ÁòËáÑÇÌú茶§Ìå[(NH4)2Fe(SO4)2¡¤6H2O]³£×ö·ÖÎö¼Á¡£µÈÎïÖʵÄÁ¿Å¨¶ÈµÄËÄÖÖÏ¡ÈÜÒº£º
a£®(NH4)2Fe(SO4)2         b£®NH4HSO4      c£®(NH4)2SO4        d£®(NH4)2SO3
ÆäÖÐc(NH4+)ÓÉ´óµ½Ð¡µÄ˳ÐòΪ                         (ÌîÑ¡Ïî×Öĸ)£»
£¨3£©¹ý¶þÁòËá¼Ø(K2S2O8)³£×öÇ¿Ñõ»¯¼Á£¬Na2S2O3³£×ö»¹Ô­¼Á¡£
¢ÙK2S2O8ÈÜÒºÓëËáÐÔMnSO4ÈÜÒº»ìºÏ£¬ÔÚ´ß»¯¼Á×÷ÓÃÏ£¬¿ÉÒԹ۲쵽ÈÜÒº±äΪ×ÏÉ«£¬¸Ã·´Ó¦µÄÀë×Ó·½³ÌʽΪ                                                 £»
¢ÚÑùÆ·ÖÐK2S2O8µÄº¬Á¿¿ÉÓõâÁ¿·¨²â¶¨¡£²Ù×÷²½ÖèΪ³ÆÈ¡0.3000 gÑùÆ·ÓÚµâÁ¿Æ¿ÖУ¬¼Ó50 mLË®Èܽ⣻¼ÓÈë4.000 g KI¹ÌÌå(ÉÔ¹ýÁ¿)£¬Õñµ´Ê¹Æä³ä·Ö·´Ó¦£»¼ÓÈëÊÊÁ¿´×ËáÈÜÒºËữ£¬ÒÔ        ÎªÖ¸Ê¾¼Á£¬ÓÃ0.1000 mol¡¤L£­1 Na2S2O3±ê×¼ÒºµÎ¶¨ÖÁÖÕµã(ÒÑÖª£ºI2£«2S2O32-£½ 2I£­£«S4O62-)¡£Öظ´2´Î£¬²âµÃƽ¾ùÏûºÄ±ê×¼Òº21.00 mL¡£¸ÃÑùÆ·ÖÐK2S2O8µÄÖÊÁ¿·ÖÊýΪ(ÔÓÖʲ»²Î¼Ó·´Ó¦)       _£¨½á¹û±£ÁôÈýλÓÐЧÊý×Ö£©¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø