ÌâÄ¿ÄÚÈÝ
ÔÚa mL´×ËáÈÜÒºÖеμÓ0.01 mol¡¤L£1µÄÇâÑõ»¯ÄÆÈÜÒº£¬µÎ¶¨ÇúÏßÈçͼËùʾ¡£
(1)´×ËáÈÜҺŨ¶È________(Ìî¡°´óÓÚ¡±¡°Ð¡ÓÚ¡±»ò¡°µÈÓÚ¡±)0.01 mol¡¤L£1£¬ÀíÓÉÊÇ________£»
(2)bµã£¬c(Na£«)________c(CH3COO£)(Ìî¡°>¡±¡°<¡±»ò¡°£½¡±)
(3)µ±´×ËáÓëÇâÑõ»¯ÄÆÈÜҺǡºÃÍêÈ«ÖкÍʱ£¬ÇúÏßÉ϶ÔÓ¦µÄµãQÓ¦ÔÚ____£»
A£®2ÓëaÖ®¼ä B£®aÓëbÖ®¼ä
C£®bÓëcÖ®¼ä D£®aÓëcÖ®¼ä
(4)ÏÂÁйØϵʽһ¶¨ÕýÈ·µÄÊÇ________¡£
A£®aµã£¬c(H£«)>c(OH£)>c(CH3COO£)>c(Na£«)
B£®aµã£¬c(Na£«)>c(CH3COO£)>c(H£«)>c(OH£)
C£®cµã£¬c(Na£«)>c(CH3COO£)>c(OH£)>c(H£«)
D£®cµã£¬c(Na£«)£«c(H£«)£½c(CH3COO£)£«c(OH£)
(1)´×ËáÈÜҺŨ¶È________(Ìî¡°´óÓÚ¡±¡°Ð¡ÓÚ¡±»ò¡°µÈÓÚ¡±)0.01 mol¡¤L£1£¬ÀíÓÉÊÇ________£»
(2)bµã£¬c(Na£«)________c(CH3COO£)(Ìî¡°>¡±¡°<¡±»ò¡°£½¡±)
(3)µ±´×ËáÓëÇâÑõ»¯ÄÆÈÜҺǡºÃÍêÈ«ÖкÍʱ£¬ÇúÏßÉ϶ÔÓ¦µÄµãQÓ¦ÔÚ____£»
A£®2ÓëaÖ®¼ä B£®aÓëbÖ®¼ä
C£®bÓëcÖ®¼ä D£®aÓëcÖ®¼ä
(4)ÏÂÁйØϵʽһ¶¨ÕýÈ·µÄÊÇ________¡£
A£®aµã£¬c(H£«)>c(OH£)>c(CH3COO£)>c(Na£«)
B£®aµã£¬c(Na£«)>c(CH3COO£)>c(H£«)>c(OH£)
C£®cµã£¬c(Na£«)>c(CH3COO£)>c(OH£)>c(H£«)
D£®cµã£¬c(Na£«)£«c(H£«)£½c(CH3COO£)£«c(OH£)
(1)´óÓÚ£»CH3COOHÊÇÈõµç½âÖÊ£¬Ö»²¿·ÖµçÀë
(2)£½¡¡(3)C¡¡(4)D
(2)£½¡¡(3)C¡¡(4)D
(1)¿ªÊ¼Ê±£¬´×ËáÈÜÒºµÄpH£½2£¬c(H£«)£½0.01 mol¡¤L£1£¬ÓÉÓÚ´×ËáÊÇÈõµç½âÖÊ£¬´×ËáÈÜÒºÖдæÔÚδµçÀëµÄCH3COOH£¬¹Êc(CH3COOH)>0.01 mol¡¤L£1¡£(2)bµã£¬pH£½7±íʾc(H£«)£½c(OH£)£¬ÓɵçºÉÊغãʽc(Na£«)£«c(H£«)£½c(OH£)£«c(CH3COO£)µÃ³ö£ºc(Na£«)£½c(CH3COO£)¡£(3)CH3COOH£«NaOH=CH3COONa£«H2O£¬µ±´×ËáÓëÇâÑõ»¯ÄÆÇ¡ºÃÍêÈ«ÖкÍʱ£¬ÈÜÒº³Ê¼îÐÔ£¬pH>7£¬ÇúÏßÉ϶ÔÓ¦µÄQµãÓ¦ÔÚbÓëcÖ®¼ä¡£(4)aµã£¬ÈÜÒºµÄÈÜÖÊÊÇ´×ËáºÍ´×ËáÄÆ£¬ÈÜÒºÏÔËáÐÔ£¬´×ËáÊÇÈõËᣬÀë×ÓŨ¶È´óС¹ØϵΪ£ºc(CH3COO£)>c(H£«)>c(OH£)£»ÎÞÂÛÈÜÒº³ÊËáÐÔ¡¢ÖÐÐÔ»ò¼îÐÔ£¬ÆäÖж¼Ö»´æÔÚNa£«¡¢H£«¡¢CH3COO£¡¢OH££¬ËùÒÔÒ»¶¨ÓеçºÉÊغãʽ£¬DÑ¡ÏîÕýÈ·¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿