ÌâÄ¿ÄÚÈÝ
¹¤ÒµÌ¼ËáÄÆ(´¿¶ÈԼΪ98%)Öк¬ÓÐCa2£«¡¢Mg2£«¡¢Fe3£«¡¢Cl£ºÍSO42-µÈÔÓÖÊ£¬Ìá´¿¹¤ÒÕÏß·ÈçÏ£º
¢ñ.̼ËáÄƵı¥ºÍÈÜÒºÔÚ²»Í¬Î¶ÈÏÂÎö³öµÄÈÜÖÊÈçͼËùʾ£º
¢ò.ÓйØÎïÖʵÄÈܶȻýÈçÏ£º
ÎïÖÊ | CaCO3 | MgCO3 | Ca(OH)2 | Mg(OH)2 | Fe(OH)3 |
Ksp | 4.96¡Á10£9 | 6.82¡Á10£6 | 4.68¡Á10£6 | 5.61¡Á10£12 | 2.64¡Á10£39 |
»Ø´ðÏÂÁÐÎÊÌ⣺
(1)¼ÓÈëNaOHÈÜҺʱ·¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽΪ£º_____________________________________¡£
Ïòº¬ÓÐMg2£«¡¢Fe3£«µÄÈÜÒºÖеμÓNaOHÈÜÒº£¬µ±Á½ÖÖ³Áµí¹²´æÇÒÈÜÒºµÄpH£½8ʱ£¬c(Mg2£«)£ºc(Fe3£«)£½________¡£
(2)¡°³ÃÈȹýÂË¡±Ê±µÄζÈÓ¦¿ØÖÆÔÚ________¡£
(3)ÓÐÈË´Ó¡°ÂÌÉ«»¯Ñ§¡±½Ç¶ÈÉèÏ뽫¡°Ä¸Òº¡±ÑØÁ÷³ÌÖÐÐéÏßËùʾ½øÐÐÑ»·Ê¹Óá£ÇëÄã·ÖÎöʵ¼Ê¹¤ÒµÉú²úÖÐÊÇ·ñ¿ÉÐÐ________£¬²¢ËµÃ÷ÀíÓÉ________________________________________¡£
(4)ÒÑÖª£ºNa2CO3¡¤10H2O(s)=Na2CO3(s)£«10H2O(g)¡¡¦¤H£½£«532.36 kJ¡¤mol£1
Na2CO3¡¤10H2O(s)=Na2CO3¡¤H2O(s)£«9H2O(g)¦¤H£½£«473.63 kJ¡¤mol£1
д³öNaCO3¡¤H2OÍÑË®·´Ó¦µÄÈÈ»¯Ñ§·½³Ìʽ________________________________________¡£
(1)Fe3£«£«3OH£=Fe(OH)3¡ý¡¢MgCO3£«2OH£=Mg(OH)2£«CO32-¡¢Mg2£«£«2OH£=Mg(OH)¡ý(Èý¸ö´ð¶ÔÁ½¸ö¼´¿É)¡¡2.125¡Á1021
(2)¸ßÓÚ36 ¡æ
(3)²»¿ÉÐС¡Èô¡°Ä¸Òº¡±Ñ»·Ê¹Óã¬ÔòÈÜÒºÖÐc(Cl£)ºÍc(SO42-)Ôö´ó£¬×îºóËùµÃ²úÎïNa2CO3ÖлìÓÐÔÓÖÊ
(4)Na2CO3¡¤H2O(s)=Na2CO3(s)£«H2O(g)¦¤H£½£«58.73 kJ¡¤mol£1
¡¾½âÎö¡¿(1)¸ù¾Ý±íÖÐÊý¾Ý£¬½áºÏÌâÒâ¿ÉÖª¼ÓÈëNaOHÈÜҺʱMg2£«¡¢Fe3£«·Ö±ðÓëOH£½áºÏÉú³É³ÁµíMg(OH)2ºÍFe(OH)3¡£(2)ζÈÔ½¸ß̼ËáÄƾ§ÌåµÄÈܽâ¶ÈÔ½´ó£¬ÎªÁ˼õÉÙ̼ËáÄƵÄËðʧ£¬¹ÊÓ¦³ÃÈȹýÂË£¬¸ù¾ÝÌâÖÐËù¸øÊý¾Ý£¬ÔÚζȸßÓÚ36 ¡æÎö³ö¾§Ìå×îÉÙ¡£(3)¡°Ä¸Òº¡±ÑØÁ÷³ÌÖÐÐéÏßËùʾ½øÐÐÑ»·Ê¹ÓÃʱ£¬»áÔì³ÉCl£ºÍSO42-µÈÀë×ӵĸ»¼¯£¬Ê¹ËùµÃ²úÆ·Öк¬ÓÐÔÓÖÊ¡£
(4)½«Á½¸öÒÑÖªµÄÈÈ»¯Ñ§·½³Ìʽ°´Ë³Ðò±àºÅΪ¢Ù¢Ú£¬¸ù¾Ý¸Ç˹¶¨ÂÉ¢Ù£¢ÚµÃNa2CO3¡¤H2O(s)=Na2CO3(s)£«H2O(g)¡¡¦¤H£½£«58.73 kJ¡¤mol£1¡£
¿Æѧ¼ÒÔÚÀûÓÃÎÞÍÁÔÔÅàÅàÑøһЩÃû¹ó»¨»Üʱ£¬ÅàÑøÒºÖÐÌí¼ÓÁ˶àÖÖ±ØÐèÔªËØ£¬ÆäÅä·½ÈçÏ£¬ÆäÖÐÖ²Îï¸ùÎüÊÕ×îÉÙµÄÀë×ÓÊÇ(¡¡¡¡)¡£
Àë×Ó | K£« | Mg2£« | Ca2£« | NO3- | H2PO4- | SO42- | Zn2£« |
1 | 0.25 | 1 | 2 | 1 | 0.25 | 1 |
A.Zn2£« B£®SO42- C£®Ca2£« D£®H2PO4-