ÌâÄ¿ÄÚÈÝ

ÄƼ°Æ仯ºÏÎï¾ßÓй㷺µÄÓÃ;¡£

£¨1£©¹¤ÒµÉÏÖƱ¸½ðÊôÄƵij£Ó÷½·¨ÊÇ_______¡£ÊÔд³öÖƱ¸½ðÊôÄƵĻ¯Ñ§·½³Ìʽ_____________¡£½ðÊôÄÆ¿ÉÓÃÓÚ________________£¨Ð´³öNaÔÚÈÛµãµÍ·½ÃæµÄÒ»ÖÖÓÃ;£©¡£

£¨2£©ÓÃNa2CO3ÈÛÈÚÑÎ×÷µç½âÖÊ£¬CO¡¢O2¡¢CO2ΪԭÁÏ¿É×é³ÉÐÂÐ͵ç³Ø¡£¸Ãµç³ØµÄ½á¹¹ÈçͼËùʾ£º

¢ÙÕý¼«µÄµç¼«·´Ó¦Ê½Îª_______£¬µç³Ø¹¤×÷ʱÎïÖÊA¿ÉÑ­»·Ê¹Óã¬AÎïÖʵĻ¯Ñ§Ê½Îª_______¡£

¢ÚÇëд³ö¼ìÑéNa2CO3ÖÐÄÆÔªËصķ½·¨_________________________¡£

£¨3£©³£ÎÂÏ£¬Å¨¶È¾ùΪ0.1 mol¡¤L£­1µÄÏÂÁÐÎåÖÖÄÆÑÎÈÜÒºµÄpHÈçÏÂ±í£º

ÈÜÖÊ

CH3COONa

Na2CO3

NaClO

NaCN

pH

8.8

11.6

10.3

11.1

ÉÏÊöÑÎÈÜÒºµÄÒõÀë×ÓÖУ¬½áºÏH£«ÄÜÁ¦×îÇ¿µÄÊÇ_________£¬¸ù¾Ý±íÖÐÊý¾Ý£¬Å¨¶È¾ùΪ0.01 mol¡¤L£­1µÄÏÂÁÐËÄÖÖËáµÄÈÜÒº·Ö±ðÏ¡ÊÍ100±¶£¬pH±ä»¯×î´óµÄÊÇ_______£¨ÌîÐòºÅ£©¡£

a£®HCN b£®HClO c£®CH3COOH d£®H2CO3

£¨4£©ÊµÑéÊÒÖг£ÓÃNaOHÀ´½øÐÐβÆø´¦Àí¡¢Ï´ÆøºÍÌá´¿¡£

¢Ù³£ÎÂÏ£¬µ±300 mL 1 mol¡¤L£­1µÄNaOHÈÜÒºÎüÊÕ4.48 L£¨ÕÛËã³É±ê×¼×´¿ö£©SO2ʱ£¬ËùµÃÈÜÒºpH>7£¬ÔòÈÜÒºÖи÷Àë×ÓŨ¶ÈÓÉ´óµ½Ð¡µÄ˳ÐòΪ_______¡£

¢ÚÒÑÖª¼¸ÖÖÀë×Ó¿ªÊ¼³ÁµíʱµÄpHÈçÏÂ±í£º

Àë×Ó

Fe2£«

Cu2£«

Mg2£«

pH

7.6

5.2

10.4

µ±Ïòº¬ÏàͬŨ¶ÈCu2£«¡¢Mg2£«¡¢Fe2£«µÄÈÜÒºÖеμÓijŨ¶ÈµÄNaOHÈÜҺʱ£¬_______£¨ÌîÀë×Ó·ûºÅ£©ÏȳÁµí£¬Ksp_______Ksp£¨Ìî¡°£¾¡±¡¢¡°£½¡±»ò¡°£¼¡±£©¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

̼Ëá¶þ¼×õ¥£¨CH3OCOOCH3£¬¼ò³ÆDMC£©£¬ÊÇÒ»ÖÖÓ¦ÓÃÇ°¾°¹ã·ºµÄвÄÁÏ£¬ÊµÑéÊÒÖпÉÓü״¼¡¢CO¡¢CO2µÈ½øÐкϳɡ£»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©¶þÑõ»¯Ì¼µÄµç×ÓʽΪ _________________

£¨2£©Óü״¼¡¢CO¡¢O2ÔÚ³£Ñ¹¡¢70¡«120¡æºÍ´ß»¯¼ÁµÄÌõ¼þϺϳÉDMC¡£

ÒÑÖª£º¢ÙCOµÄ±ê׼ȼÉÕÈÈΪ£º?283.0kJ•mol?1£¬

¢Ú1mol H2O£¨l£©ÍêÈ«Õô·¢±ä³ÉH2O£¨g£©ÐèÎüÊÕ44kJµÄÈÈÁ¿

¢Û2CH3OH£¨g£©£«CO2£¨g£©?CH3OCOOCH3£¨g£©£«H2O£¨g£©¡÷H£½?15.5kJ•mol?1

Ôò2CH3OH£¨g£©£«CO£¨g£©£«1/2O2£¨g£©?CH3OCOOCH3 £¨g£©£«H2O£¨l£©¡÷H£½_____¡£

¸Ã·´Ó¦ÔÚ³£Ñ¹ºÍ70¡«120¡æÌõ¼þϾÍÄÜ×Ô·¢·´Ó¦µÄÔ­ÒòÊÇ_______________¡£

£¨3£©ÓÉÉÏÊö·´Ó¦¿ÉÖª¼×´¼ºÍCO2¿ÉÖ±½ÓºÏ³ÉDMCµ«¼×´¼×ª»¯ÂÊͨ³£²»»á³¬¹ý1%£¬ÖÆÔ¼¸Ã·´Ó¦×ßÏò¹¤Òµ»¯Éú²ú£®

¢Ùд³ö¸Ã·´Ó¦Æ½ºâ³£Êý±í´ïʽ£º______________ £»

¢ÚÔÚºãÈÝÃܱÕÈÝÆ÷Öз¢ÉúÉÏÊö·´Ó¦£¬ÄÜ˵Ã÷ÒѴﵽƽºâ״̬µÄÊÇ____£¨Ñ¡Ìî±àºÅ£©£®

A£®vÕý£¨CH3OH£©£½2vÄ棨CO2£©

B£®CH3OCOOCH3ÓëH2OµÄÎïÖʵÄÁ¿Ö®±È±£³Ö²»±ä

C£®ÈÝÆ÷ÄÚÆøÌåµÄÃܶȲ»±äD£®ÈÝÆ÷ÄÚѹǿ²»±ä

¢ÛijÑо¿Ð¡×éÔÚijζÈÏ£¬ÔÚ100mLºãÈÝÃܱÕÈÝÆ÷ÖÐͶÈë2.5mol CH3OH£¨g£©¡¢ÊÊÁ¿CO2ºÍ6¡Á10?5 mol´ß»¯¼Á£¬Ñо¿·´Ó¦Ê±¼ä¶Ô¼×´¼×ª»¯Êý£¨TON£©µÄÓ°Ï죬Æä±ä»¯ÇúÏßÈçͼ1Ëùʾ£®£¨¼ÆË㹫ʽΪ£ºTON£½×ª»¯µÄ¼×´¼µÄÎïÖʵÄÁ¿/´ß»¯¼ÁµÄÎïÖʵÄÁ¿£©¡£

ÔÚ¸ÃζÈÏ£¬×î¼Ñ·´Ó¦Ê±¼äÊÇ_________h£»4¡«10hÄÚDMCµÄƽ¾ù·´Ó¦ËÙÂÊÊÇ_______ £®

£¨4£©ÒÔ¶à¿×²¬Îªµç¼«£¬ÔÚÈçÏÂͼװÖÃÖÐA¡¢B¿Ú·Ö±ðͨÈëCH3OCOOCH3ºÍO2¹¹³ÉȼÁϵç³Ø£¬Çëд³ö¸Ãµç³Ø¸º¼«µÄµç¼«·´Ó¦Ê½____________________________

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø