ÌâÄ¿ÄÚÈÝ
ij¿ÎÍâ»î¶¯Ð¡×éÔÚʵÑéÊÒÓÃÏÂͼµÄһЩװÖÃ×éºÏºó£¬¿ìËÙÖÆÈ¡°±²¢ÑéÖ¤°±µÄijЩÐÔÖÊ£¬Í¬Ê±ÊÕ¼¯ÉÙÁ¿´¿¾»µªÆø£¬Çë»Ø´ð£º

£¨1£©Ð´³öÓÃÊìʯ»ÒºÍÂÈ»¯ï§·´Ó¦ÖÆ°±ÆøµÄ»¯Ñ§·½³Ìʽ
(2) ±¾ÊµÑé½øÐÐÒ»¶Ïʱ¼äºó£¬¹Û²ìµ½¼ÓÈȵÄÓ²Öʲ£Á§ÊÔ¹ÜÄÚºÚÉ«Ñõ»¯Í·ÛĩתΪºìÉ«£¬Ê¢ÎÞË®ÁòËá͵ĸÉÔï¹ÜÄÚ³öÏÖÀ¶É«£¬²¢ÇÒÔÚ×îºóµÄ³öÆøµ¼¹Ü´¦ÊÕ¼¯µ½´¿¾»¡¢¸ÉÔïµÄµªÆø¡£¸ù¾ÝÕâЩÏÖÏó£¬Ð´³öÔÚÓ²Öʲ£Á§ÊÔ¹ÜÄÚ·¢Éú·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º ,Õâ¸ö·´Ó¦ËµÃ÷°±Æø¾ßÓÐ____(Ìî±àºÅ£ºA¡¢¼îÐÔ£»B¡¢»¹ÔÐÔ£»C¡¢Ñõ»¯ÐÔ£» D¡¢²»Îȶ¨ÐÔ)
(3) Ï´ÆøÆ¿ÖÐʢŨÁòËáµÄÖ÷Òª×÷ÓÃÊÇ__________________
(4) ÔÚ×îºóµÄ³öÆøµÄµ¼¹Ü¿ÚÊÕ¼¯¸ÉÔï¡¢´¿¾»µÄµªÆø£¬ÊÕ¼¯·½·¨ÊÇ£º___________
(Ìî±àºÅ£ºA¡¢ÅÅÆø·¨ B¡¢ÅÅË®·¨ C¡¢ÓÃÆøÄÒÊÕ¼¯)
£¨5£©×°ÖÃEµÄ×÷ÓÃÊÇ_______________¡£×°ÖÃFÑéÖ¤µÄÆøÌåÊÇ___________¡£

£¨1£©Ð´³öÓÃÊìʯ»ÒºÍÂÈ»¯ï§·´Ó¦ÖÆ°±ÆøµÄ»¯Ñ§·½³Ìʽ
(2) ±¾ÊµÑé½øÐÐÒ»¶Ïʱ¼äºó£¬¹Û²ìµ½¼ÓÈȵÄÓ²Öʲ£Á§ÊÔ¹ÜÄÚºÚÉ«Ñõ»¯Í·ÛĩתΪºìÉ«£¬Ê¢ÎÞË®ÁòËá͵ĸÉÔï¹ÜÄÚ³öÏÖÀ¶É«£¬²¢ÇÒÔÚ×îºóµÄ³öÆøµ¼¹Ü´¦ÊÕ¼¯µ½´¿¾»¡¢¸ÉÔïµÄµªÆø¡£¸ù¾ÝÕâЩÏÖÏó£¬Ð´³öÔÚÓ²Öʲ£Á§ÊÔ¹ÜÄÚ·¢Éú·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º ,Õâ¸ö·´Ó¦ËµÃ÷°±Æø¾ßÓÐ____(Ìî±àºÅ£ºA¡¢¼îÐÔ£»B¡¢»¹ÔÐÔ£»C¡¢Ñõ»¯ÐÔ£» D¡¢²»Îȶ¨ÐÔ)
(3) Ï´ÆøÆ¿ÖÐʢŨÁòËáµÄÖ÷Òª×÷ÓÃÊÇ__________________
(4) ÔÚ×îºóµÄ³öÆøµÄµ¼¹Ü¿ÚÊÕ¼¯¸ÉÔï¡¢´¿¾»µÄµªÆø£¬ÊÕ¼¯·½·¨ÊÇ£º___________
(Ìî±àºÅ£ºA¡¢ÅÅÆø·¨ B¡¢ÅÅË®·¨ C¡¢ÓÃÆøÄÒÊÕ¼¯)
£¨5£©×°ÖÃEµÄ×÷ÓÃÊÇ_______________¡£×°ÖÃFÑéÖ¤µÄÆøÌåÊÇ___________¡£
£¨1£©2NH4Cl+Ca(OH)2
CaCl2+2NH3¡ü+2H2O
£¨2£©2 NH3+3CuO
N2+3Cu+3H2O B
(3) ¸ÉÔïN2 ³ýÈ¥ÉÙÁ¿NH3 £¨4£©C £¨5£©¸ÉÔïNH3 H2O

£¨2£©2 NH3+3CuO

(3) ¸ÉÔïN2 ³ýÈ¥ÉÙÁ¿NH3 £¨4£©C £¨5£©¸ÉÔïNH3 H2O
ÊÔÌâ·ÖÎö£º£¨2£©Å¨°±Ë®µÎÈëÉúʯ»ÒÖУ¬Éúʯ»ÒÈÜÓÚË®·ÅÈÈ£¬Ê¹°±Ë®·Ö½âͬʱÉúʯ»ÒÓëË®·´Ó¦Éú³ÉÇâÑõ»¯¸Æ£¬ÇâÑõ¸ùÀë×ÓŨ¶ÈÔö´ó£¬Ê¹NH3+H2O



£¨3£©Ï´ÆøÆ¿ÖÐŨÁòËáµÄ×÷ÓÃÊǸÉÔïN2¡¢ÎüÊÕ¶àÓàµÄ°±Æø£¬·ÀÖ¹°±ÆøÒݳöÎÛȾ»·¾³¡£
£¨4£©ÊÕ¼¯´¿¾»¡¢¸ÉÔïµÄ°±ÆøÓÃÆøÄÒÊÕ¼¯¡£
£¨5£©EµÄ×÷ÓÃÊǸÉÔï°±Æø£¬FÑéÖ¤µÄÆøÌåÊÇË®ÕôÆø¡£
µãÆÀ£ºÕÆÎÕʵÑéÊÒ¿ìËÙÖÆ°±ÆøµÄ·½·¨£ºÏòÉúʯ»Ò»ò¹ÌÌåÇâÑõ»¯ÄÆ»ò¼îʯ»ÒÖеμÓŨ°±Ë®¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿