ÌâÄ¿ÄÚÈÝ

¡¾ÌâÄ¿¡¿(1)ÓÐÏÂÁм¸×éÎïÖÊ£ºA. B. ±ûÍéºÍ¼ºÍé C. Õý¶¡ÍéºÍÒ춡Íé D. CH3CH3ºÍCH3(CH2)8CH3

E.ºÍ F.ºÍ

ÆäÖУ¬¢ÙÊôÓÚͬ·ÖÒì¹¹ÌåµÄÊÇ________£»¢ÚÊôÓÚͬλËصÄÊÇ________£»¢ÛÊôÓÚͬһÖÖÎïÖʵÄÊÇ________£»

¢ÜÊôÓÚͬϵÎïµÄÊÇ________________£»

(2)ÒÑ֪ijÍéÌþ·Ö×ÓÏà¶Ô·Ö×ÓÖÊÁ¿Îª72¡£

¢Ù¸ÃÍéÌþµÄ·Ö×ÓʽΪ______________£»

¢Úд³ö¸ÃÍéÌþ·Ö×ÓËùÓеÄͬ·ÖÒì¹¹ÌåµÄ½á¹¹¼òʽ____________________________£»

¢ÛÉÏÊöͬ·ÖÒì¹¹ÌåÖУ¬ÔÚÏàͬÌõ¼þÏ·еã×îµÍµÄÊÇ_____________________________(д½á¹¹¼òʽ)£»

(3) ÒÑÖª µÄ±½»·ÉϵĶþÂÈÈ¡´úÎïÓÐ6ÖÖ£¬Ôò¼×±½±½»·ÉϵÄÈýÂÈÈ¡´úÎïÓÐ______ÖÖ£»

(4)ÏÂÁи÷ÖÖ´¼²»ÄÜ·¢Éú´ß»¯Ñõ»¯µÄÊÇ_______ ¡£

A. CH3OH B. CH3CH2OH C. CH3CH(CH3)OH D. CH3CH2C(CH3)2OH

¡¾´ð°¸¡¿CF A E BD C5H12 CH3CH2CH2CH2CH3¡¢¡¢ 6 D

¡¾½âÎö¡¿

£¨1£©·Ö×ÓʽÏàͬ½á¹¹²»Í¬µÄ»¯ºÏÎﻥΪͬ·ÖÒì¹¹Ì壬Õý¶¡ÍéºÍÒ춡Íé¡¢ºÍ·Ö±ðÂú×ã·Ö×ÓʽÏàͬ£¬½á¹¹²»Í¬£¬»¥ÎªÍ¬·ÖÒì¹¹Ì壬´ð°¸Ñ¡CF£»ÖÊ×ÓÊýÏàͬÖÐ×ÓÊý²»Í¬µÄͬһÖÖÔªËصIJ»Í¬ºËËØ»¥ÎªÍ¬·ÖÒì¹¹Ì壬Ôò»¥ÎªÍ¬Î»ËصÄÊÇ£¬´ð°¸Ñ¡A£»ÐÔÖʺͽṹ¶¼ÍêÈ«ÏàͬµÄÊÇͬһÖÖÎïÖÊ£¬ÔòºÍÊôÓÚͬһÖÖÎïÖÊ£¬´ð°¸Ñ¡E£»½á¹¹ÏàËÆ£¬·Ö×Ó×é³ÉÏà²îÈô¸É¸öCH2Ô­×ÓÍŵÄͬһÀàÓлúÎ»¥³ÆΪͬϵÎÔò±ûÍéºÍ¼ºÍé¡¢CH3CH3ºÍCH3(CH2)8CH3·Ö±ð»¥ÎªÍ¬ÏµÎ´ð°¸Ñ¡BD£»

£¨2£©¢ÙÒÑ֪ijÍéÌþ·Ö×ÓÏà¶Ô·Ö×ÓÖÊÁ¿Îª72£¬¸ù¾ÝÍéÌþͨʽCnH2n+2¿ÉÖª14n+2£½72£¬½âµÃn£½5£¬ËùÒÔ¸ÃÍéÌþµÄ·Ö×ÓʽΪC5H12£»

¢Ú¸ÃÍéÌþÊÇÎìÍ飬ÓÐ3ÖÖͬ·ÖÒì¹¹Ì壬¼´ÕýÎìÍé¡¢ÒìÎìÍéºÍÐÂÎìÍ飬ÔòËùÓеÄͬ·ÖÒì¹¹ÌåµÄ½á¹¹¼òʽΪCH3CH2CH2CH2CH3¡¢¡¢£»

¢ÛÉÏÊöͬ·ÖÒì¹¹ÌåÖУ¬ÔÚÏàͬÌõ¼þÏ·еã×îµÍµÄÊǺ¬ÓÐÖ§Á´×î¶àµÄ£¬¼´ÎªÐÂÎìÍ飬½á¹¹¼òʽΪ£»

£¨3£©ÒÑÖªµÄ±½»·ÉϵĶþÂÈÈ¡´úÎïÓÐ6ÖÖ£¬ÓÉÓÚ±½»·ÉÏÒ»¹²ÊÇ5¸öÇâÔ­×Ó£¬Ôò¼×±½±½»·ÉϵÄÈýÂÈÈ¡´úÎïÒ²ÓÐ6ÖÖ£»

£¨4£©´¼·¢ÉúÑõ»¯·´Ó¦µÄ½á¹¹ÌصãÊÇ£ºÖ»ÓÐôÇ»ùÏàÁ¬Ì¼µÄ̼ÉÏÓÐÇâÔ­×ӵIJÅÄÜ·¢ÉúÑõ»¯·´Ó¦£¬Òò´ËCH3OH¡¢CH3CH2OH¡¢CH3CH(CH3)OH¾ùÄÜ·¢Éú´ß»¯Ñõ»¯£¬CH3CH2C(CH3)2OH²»ÄÜ·¢Éú´ß»¯Ñõ»¯¡£´ð°¸Ñ¡D¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

¡¾ÌâÄ¿¡¿¸õÊÇÈËÌå±ØÐèÔªËØ£¬È纬Á¿²»×ã»áÓ°ÏìÌÇÀàºÍÖ¬ÀàµÄ´úл£¬¹ý¸ßÔò»áÒýÆð¼±ÐÔÖж¾¡£¹¤ÒµÉÏÍùÍù²ÉÈ¡ÏÂÁÐÑ­»·¹¤ÒÕ·ÀÖ¹¸õµÄÎÛȾ£º

Íê³ÉÏÂÁÐÌî¿Õ£º

£¨1£©¢Ù²½Öк¬Cr2OÀë×ӵķÏË®ÔÚËáÐÔÌõ¼þÏÂÄÜÓÃFe3O4´¦Àí£¬·´Ó¦µÄÀë×Ó·½³ÌʽΪ_____________£»

£¨2£©·´Ó¦¢ÝÊÇ¿ÉÄæ·´Ó¦£¬ÔÚNa2CrO4ÈÜÒºÖмÓÈëÏ¡ÁòËᣬÈÜÒºÓÉ»ÆÉ«Öð½¥±ä³É³ÈÉ«£¬Ð´³ö¸Ã·´Ó¦µÄÀë×Ó·½³Ìʽ£º___________________________________£»

£¨3£©ÏòÉÏÊö·´Ó¦ºóµÄÈÜÒºÖмÓÈë¼îÈÜÒº£¬È÷ÏË®µÄpHÉýÖÁ8¡«10£¬¿ØÖÆÊʵ±µÄζȣ¬Ê¹²úÎïÖеĽðÊôÑôÀë×ÓÈ«²¿×ª±äΪ³Áµí¡£»ØÊÕËùµÃµÄCr(OH)3£¬¾­´¦ÀíºóÓÖ¿Éת±ä³ÉK2Cr2O7¡£´¿¾»µÄK2Cr2O7³£ÓÃÓÚ׼ȷ²â¶¨Na2S2O3ÈÜÒºµÄÎïÖʵÄÁ¿Å¨¶È£¬·½·¨ÈçÏ£º

¢ÙCr2O72-+6I-+14H+ =3I2+2Cr3++7H2O

¢Ú2S2O32-+ I2 =S4O62-+2I-£¬×¼È·³ÆÈ¡´¿¾»µÄK2Cr2O7 0.294gÅä³ÉÈÜÒº£¬¼Ó×ãÁ¿KI£¬ÓÃNa2S2O3ÈÜÒºµÎ¶¨£¬ÏûºÄNa2S2O3ÈÜÒº25.00mL¡£

¢Ù»ØÊÕËùµÃµÄCr(OH)3ÔÚ´¦Àí֮ǰÐèÒªÏȽøÐÐÏ´µÓ£¬Ï´µÓ³ÁµíµÄ·½·¨Îª________________________£»

¢ÚµÎ¶¨Ê±¼ÓÈëµÄָʾ¼Áͨ³£Îª_________£¬µÎ¶¨ÖÁÖÕµãµÄÏÖÏóÊÇ_______________________________£»

¢ÛNa2S2O3ÈÜÒºµÄÎïÖʵÄÁ¿Å¨¶ÈΪ__________¡£

¡¾ÌâÄ¿¡¿(1)ÈçͼËùʾ£¬UÐιܵÄ×ó¶Ë±»Ë®ºÍ½ºÈû·â±ÕÓм×ÍéºÍÂÈÆø(Ìå»ý±ÈΪ1¡Ã4)µÄ»ìºÏÆøÌ壬¼Ù¶¨ÂÈÆøÔÚË®ÖеÄÈܽâ¶È¿ÉÒÔºöÂÔ¡£½«·â±ÕÓм×ÍéºÍÂÈÆø»ìºÏÆøÌåµÄ×°Ö÷ÅÖÃÔÚÓйâÁÁµÄµØ·½£¬ÈûìºÏÆøÌ建ÂýµØ·´Ó¦Ò»¶Îʱ¼ä¡£

¢Ù¼ÙÉè¼×ÍéÓëÂÈÆø·´Ó¦³ä·Ö£¬ÇÒÖ»²úÉúÒ»ÖÖÓлúÎÇëд³ö»¯Ñ§·½³Ìʽ£º_________________£»

¢ÚÈôÌâÄ¿Öм×ÍéÓëÂÈÆøµÄÌå»ýÖ®±ÈΪ1¡Ã1£¬ÔòµÃµ½µÄ²úÎïΪ____(Ìî×Öĸ±àºÅ)£»

A£®CH3Cl¡¡HCl B£®CCl4¡¡HCl C£®CH3Cl¡¡CH2Cl2 D£®CH3Cl¡¡CH2Cl2¡¡CHCl3¡¡CCl4¡¡HCl

¢Û¾­¹ý¼¸¸öСʱµÄ·´Ó¦ºó£¬UÐιÜÓҶ˵ÄË®Öù±ä»¯ÊÇ________ (Ìî×Öĸ±àºÅ)£»

A£®Éý¸ßB£®½µµÍ C£®²»±äD£®ÎÞ·¨È·¶¨

¢ÜÈôË®Öк¬ÓÐNa2SiO3£¬ÔòÔÚUÐιÜ×ó¶Ë»á¹Û²ìµ½__________________________________________£»

¢ÝÓҶ˲£Á§¹ÜµÄ×÷ÓÃÊÇ_______________________¡£

(2)ijʵÑéС×éÓÃÏÂÁÐ×°ÖýøÐÐÒÒ´¼´ß»¯Ñõ»¯µÄʵÑé¡£

¢ÙʵÑé¹ý³ÌÖÐÍ­Íø³öÏÖºìÉ«ºÍºÚÉ«½»Ìæ³öÏÖµÄÏÖÏó£¬Çëд³öÏàÓ¦µÄ»¯Ñ§·½³Ìʽ___________________¡¢______________________ £»

¢Ú¼×ºÍÒÒÁ½¸ö×°ÖõÄ×÷Óò»Ïàͬ£¬¼×µÄ×÷ÓÃÊÇ_____________£»ÒÒµÄ×÷ÓÃÊÇ _____________£»

¢Û·´Ó¦½øÐÐÒ»¶Îʱ¼äºó£¬¸ÉÔïÊÔ¹ÜaÖÐÄÜÊÕ¼¯µ½²»Í¬µÄÎïÖÊ£¬ËüÃÇÊÇ______________________£»¼¯ÆøÆ¿ÊÕ¼¯µ½µÄÆøÌåµÄÖ÷Òª³É·ÖÊÇ___________¡£

¡¾ÌâÄ¿¡¿ÀûÓÃÏÂͼװÖòⶨÖкÍÈȵÄʵÑé²½ÖèÈçÏ£º

¢ÙÓÃÁ¿Í²Á¿È¡50 mL 0.25 mol¡¤L£­1ÁòËáµ¹ÈëСÉÕ±­ÖУ¬²â³öÁòËáζȣ»

¢ÚÓÃÁíÒ»Á¿Í²Á¿È¡50 mL 0.55 mol¡¤L£­1NaOHÈÜÒº£¬²¢ÓÃÁíһζȼƲâ³öÆäζȣ»

¢Û½«NaOHÈÜÒºµ¹ÈëСÉÕ±­ÖУ¬É跨ʹ֮»ìºÏ¾ùÔÈ£¬²â³ö»ìºÏÒº×î¸ßζȡ£

»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©µ¹ÈëNaOHÈÜÒºµÄÕýÈ·²Ù×÷ÊÇ__________¡£

A£®Ñز£Á§°ô»ºÂýµ¹Èë B£®·ÖÈý´ÎÉÙÁ¿µ¹Èë C£®Ò»´ÎѸËÙµ¹Èë

£¨2£©Ê¹ÁòËáÓëNaOHÈÜÒº»ìºÏ¾ùÔȵÄÕýÈ·²Ù×÷ÊÇ________¡£

A£®ÓÃζȼÆСÐĽÁ°è B£®½Ò¿ªÓ²Ö½Æ¬Óò£Á§°ô½Á°è

C£®ÇáÇáµØÕñµ´ÉÕ±­ D£®ÓÃÌ×ÔÚζȼÆÉϵĻ·Ðβ£Á§½Á°è°ôÇáÇáµØ½Á¶¯

£¨3£©½Á°è°ôΪºÎ²»ÓÃÍ­ÖʵÄ_____________.

£¨4£©ÊµÑéÊý¾ÝÈçÏÂ±í£º

¢ÙÇëÌîдϱíÖеĿհףº________¡£

ζÈ

ʵÑé´ÎÊý

Æðʼζȡæ

ÖÕֹζÈ

/¡æ

ζȲîƽ¾ùÖµ/¡æ

H2SO4

NaOH

ƽ¾ùÖµ

1

26.2

26.0

26.1

29.5

2

27.0

27.4

27.2

32.3

3

25.9

25.9

25.9

29.2

4

26.4

26.2

26.3

29.8

¢Ú½üËÆÈÏΪ0.55 mol¡¤L£­1NaOHÈÜÒººÍ0.25 mol¡¤L£­1ÁòËáÈÜÒºµÄÃܶȶ¼ÊÇ1 g¡¤cm£­3£¬ÖкͺóÉú³ÉÈÜÒºµÄ±ÈÈÈÈÝc£½4.18 J¡¤g£­1¡¤¡æ£­1¡£ÒÀ¾ÝÉϱíÊý¾Ý¼ÆËãÖкÍÈȦ¤H£½________(ȡСÊýµãºóһλ)¡£

¢ÛÖкÍÈȲⶨʵÑéÖУ¬ÏÂÁвÙ×÷Ò»¶¨»á½µµÍʵÑé׼ȷÐÔµÄÊÇ______¡£

A£®µÎ¶¨¹Ü£¨¾«Á¿ÒÇÆ÷£¬¶ÁÊý±£Áôµ½0.01£©È¡ËùÓÃËá¼îÈÜÒºµÄÌå»ý

B£®NaOHÈÜÒºÔÚµ¹ÈëСÉÕ±­Ê±£¬ÓÐÉÙÁ¿½¦³ö

C£®´ó¡¢Ð¡ÉÕ±­Ìå»ýÏà²î½Ï´ó£¬¼Ð²ã¼ä·ÅµÄËéÅÝÄ­ËÜÁϽ϶à

D£®²âÁ¿ÁòËáÈÜÒºµÄζȼÆÓÃˮϴ¾»ºó²ÅÓÃÀ´²âNaOHÈÜÒºµÄζÈ

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø