ÌâÄ¿ÄÚÈÝ

(12·Ö) Ã÷·¯Ê¯µÄÖ÷Òª³É·ÖÊÇK2SO4¡¤Al2(SO4)3¡¤2Al 2O3¡¤6H2O£¬´ËÍ⻹º¬ÓÐÉÙÁ¿Fe2O3ÔÓÖÊ¡£ÀûÓÃÃ÷·¯Ê¯ÖƱ¸ÇâÑõ»¯ÂÁµÄÁ÷³ÌÈçÏ£º

»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©¡°±ºÉÕ¡±¹ý³ÌÖз¢ÉúµÄ·´Ó¦Îª2Al2(SO4)3£«3S  2Al 2O3£«9SO2£¬ÆäÖÐÑõ»¯¼ÁΪ           ¡£
£¨2£©¡°Èܽ⡱ʱ·´Ó¦µÄÀë×Ó·½³ÌʽΪ           ¡£
£¨3£©¡°µ÷½ÚpH¡±ºó¹ýÂË¡¢Ï´µÓAl(OH)3³Áµí£¬Ö¤Ã÷ÒÑÏ´µÓ¸É¾»µÄʵÑé²Ù×÷ºÍÏÖÏóÊÇ
           ¡£
£¨4£©µ÷½ÚpHʱʹÓõÄÊÇÖÊÁ¿Å¨¶È£¨µ¥Î»Ìå»ýÈÜÒºËùº¬ÈÜÖʵÄÖÊÁ¿£©Îª882 g/L µÄH2SO4 £¬ÅäÖÆ1L¸ÃÈÜÒº£¬ÐèÓÃÁ¿Í²Á¿È¡ÖÊÁ¿·ÖÊýΪ98©‡µÄÁòËᣨÃܶÈÊÇ1.8g/cm3£©
           mL
£¨5£©¡°·ÏÔü¡±¡¢¡°Ä¸Òº¡±ÖпɻØÊÕµÄÎïÖÊ·Ö±ðÊÇ           ¡£
£¨12·Ö£©£¨1£©Al2(SO4)3£¨2·Ö£© £¨2£©Al2O3£«2OH£­£½2AlO2£­£«H2O £¨2·Ö£©
£¨3£©È¡×îºóÒ»´ÎÏ´µÓµÄÁ÷³öÒºÓÚÊÔ¹ÜÖУ¬µÎ¼ÓBaCl2ÈÜÒº£¬ÈôÎÞ°×É«³ÁµíÉú³ÉÔòÒÑÏ´µÓ¸É¾»¡££¨2·Ö£© £¨4£©500.0 mL£¨3·Ö£©
£¨5£©Fe2O3¡¢K2SO4¡¢Na2SO4£¨3·Ö£©
´ËÌâΪ¹¤ÒÕÁ÷³ÌÌ⣬Éæ¼°¹¤ÒÕÁ÷³Ì¡¢ÊµÑé²Ù×÷¡¢·´Ó¦ÀíÂ۵ȡ££¨1£©±ºÉÕ¹ý³ÌÖз¢ÉúµÄÊÇÒ»¸ö¹éÖз´Ó¦S´Ó+6ºÍ0µ½+4¼Û£¬µÃµ½ÊìÁÏÖÐÓÐK2SO4ºÍAl2O3£¬ÓÃNaOHÈܽ⣬½«Al2O3ת»¯ÎªNaAlO2£¬È»ºóµ÷½ÚpH£¬AlO+H++H2O=Al(OH)3¡£882g/LµÄÁòËᣬÎïÖʵÄÁ¿Å¨¶ÈΪ9mol/L£¬98%µÄÁòËáΪ18mol/L£¬´Ó¶ø¼ÆËãÐèÒªÌå»ýΪ500ml¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø