ÌâÄ¿ÄÚÈÝ

£¨15·Ö£©ÏÂͼÉæ¼°µÄÎïÖÊËùº¬ÔªËØÖУ¬³ýÒ»ÖÖÔªËØÍ⣬ÆäÓà¾ùΪ¶ÌÖÜÆÚÔªËØ¡£ÒÑÖª£ºA¡¢FΪÎÞÉ«ÆøÌåµ¥ÖÊ£¬BΪ¾ßÓд̼¤ÐÔÆøζµÄÆøÌ壬CΪºÚÉ«Ñõ»¯ÎEΪºìÉ«½ðÊôµ¥ÖÊ£¨²¿·Ö·´Ó¦µÄ²úÎïδÁгö£©¡£Çë»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©BµÄµç×ÓʽΪ­­­­­        £»

£¨2£©Ð´³öBºÍC·´Ó¦µÄ»¯Ñ§·½³Ìʽ                                            £»

£¨3£©Ð´³öEÓëGµÄÏ¡ÈÜÒºµÄÀë×Ó·½³Ìʽ£¬²¢±ê³öµç×ÓתÒÆÊýÄ¿£º

                                                      £»

£¨4£©J¡¢K¾ùÊÇͬÖÖ½ðÊôµÄÂÈ»¯ÎÇÒKΪ°×É«³Áµí¡£Ð´³öSO2»¹Ô­JÉú³ÉKµÄÀë×Ó·½³Ìʽ                                        £»

£¨5£©Æû³µÎ²ÆøÖг£º¬ÓÐDºÍCO £¬¶þÕßÔÚ´ß»¯¼Á×÷ÓÃÏ¿ÉÒԴ󲿷Öת»¯ÎªÁ½ÖÖ¶Ô¿ÕÆøÎÞÎÛȾµÄÎïÖÊ£¬ÒÑÖª£ºF(g)  +  A(g) = 2D (g) ¡÷H = +180.5KJ/mol

2C (s)+ O2 (g)= 2CO(g) ¡÷H = -221.0 KJ/mol

C (s)+ O2(g)= CO2(g) ¡÷H = -393.5 KJ/mol

ÔòÉÏÊöβÆøת»¯µÄÈÈ»¯Ñ§·½³ÌʽΪ£º                                   ¡£

 

£¨1£©NH3

£¨2£©3CuO +2NH3 ===3Cu + N2 +3H2O£¨¼ÓÈÈ£©

£¨3£©3Cu+8H+ + 2NO3- = 3Cu2+ + 2NO + 4H2O

£¨4£©2Cu2++2Cl-+ SO2 +2H2O = 2CuCl¡ý+ 4H+ + SO42-

£¨5£©2NO(g)+2CO(g)   N2(g)+2CO2(g)¡÷H= ¡ª746.5KJ/mol

½âÎö:

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

ÏÂͼÉæ¼°µÄÎïÖÊËùº¬ÔªËØÖУ¬³ýÒ»ÖÖÔªËØÍ⣬ÆäÓà¾ùΪ¶ÌÖÜÆÚÔªËØ¡£ÒÑÖª£ºA¡¢FΪÎÞÉ«ÆøÌåµ¥ÖÊ£¬BΪ¾ßÓд̼¤ÐÔÆøζµÄÆøÌ壬CΪºÚÉ«Ñõ»¯ÎEΪºìÉ«½ðÊôµ¥ÖÊ£¨²¿·Ö·´Ó¦µÄ²úÎïδÁгö£©¡£Çë»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©BµÄµç×ÓʽΪ        £»
£¨2£©Ð´³öBºÍC·´Ó¦µÄ»¯Ñ§·½³Ìʽ                                            £»
£¨3£©Ð´³öEÓëGµÄÏ¡ÈÜÒº·´Ó¦µÄÀë×Ó·½³Ìʽ£¬²¢Óõ¥ÏßÇűê³öµç×ÓתÒƵķ½ÏòºÍÊýÄ¿£º
                                                      £»
£¨4£©J¡¢K¾ùÊÇͬÖÖ½ðÊôµÄÂÈ»¯ÎÇÒKΪ°×É«³Áµí¡£Ð´³öSO2»¹Ô­JÉú³ÉKµÄÀë×Ó·½³Ìʽ                                        £»
£¨5£©Æû³µÎ²ÆøÖг£º¬ÓÐDºÍCO £¬¶þÕßÔÚ´ß»¯¼Á×÷ÓÃÏ¿ÉÒԴ󲿷Öת»¯ÎªÁ½ÖÖ¶Ô¿ÕÆøÎÞÎÛȾµÄÎïÖÊ£¬ÒÑÖª£º    F(g) + A(g) =" 2D" (g)  ¡÷H =" +180.5KJ/mol"
2C (s)+ O2 (g)= 2CO(g) ¡÷H =" -221.0" KJ/mol
C (s)+ O2(g) = CO2(g)  ¡÷H =" -393.5" KJ/mol
ÔòÉÏÊöβÆøת»¯µÄÈÈ»¯Ñ§·½³ÌʽΪ£º                                   ¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø