ÌâÄ¿ÄÚÈÝ

£¨5·Ö£©ËÉÓÍ´¼ÊÇÒ»ÖÖÌìÈ»Óлú»¯ºÏÎ´æÔÚÓÚ·¼ÕÁÓÍ¡¢ÓñÊ÷Óͼ°³È»¨Ó͵ÈÌìȻֲÎᆱÓÍÖУ¬¾ßÓÐ×϶¡ÏãÏãÆø£¬ÔÚÏãÁϹ¤ÒµÖÐÓÃ;¹ã·º£¬Ö÷ÒªÓÃÓÚÏãÔí¼°»¯×±Æ·ÏãÁϺ͵÷ºÏÏ㾫¡£

8-1Çëд³öËÉÓÍ´¼·Ö±ðÓëÏÂÁÐÊÔ¼Á·´Ó¦ËùµÃÖ÷ÒªÓлú²úÎïµÄ½á¹¹Ê½£¨²»¿¼ÂÇÁ¢ÌåÒì¹¹Ì壩£º

£¨1£©Br2/CC14£»£¨2£©KMnO4£¨Ï¡¡¢ÀäÈÜÒº£©£»£¨3£©(a) KMnO4/NaOH£¬(b) H3O+£»£¨4£©PBr3£»£¨5£©(a) Na£¬(b) CH3I£»£¨6£©CH3COC1/¼î¡£

8-2ËÉÓÍ´¼ÊÇ·ñ´æÔÚÐý¹âÒì¹¹Ì壨¶ÔÓ³Òì¹¹Ì壩£¿ÈçÓУ¬ÇëÖ¸³ö¸Ã·Ö×ÓËùº¬ÊÖÐÔ̼ԭ×ÓµÄÊýÄ¿¼°¿ÉÄÜ´æÔÚµÄÐý¹âÒì¹¹ÌåµÄÊýÄ¿¡£

8-1 ±¾Ð¡Ìâ3·Ö£¬Ã¿¸ö0.5·Ö

 

8-2±¾Ð¡Ìâ2·Ö

´æÔÚÐý¹âÒì¹¹Ì壨»ò´ð£º´æÔÚ¶ÔÓ³Òì¹¹Ì壬»ò´ð£ºÊÇ£©£±·Ö

º¬£±¸öÊÖÐÔ̼ԭ×Ó¡¡0.5·Ö£»¡¡¿ÉÄÜ´æÔÚ£²¸öÐý¹âÒì¹¹Ìå¡¡0.5·Ö

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø