ÌâÄ¿ÄÚÈÝ

¡¾ÌâÄ¿¡¿»¯Ñ§ÊÔ¼ÁÓ¦¸ù¾ÝÆäÐÔÖʺÍÐÎ̬½øÐÐÓÐЧÍ×ÉƱ£´æ£º

(1)¹ÌÌåÊÔ¼ÁÓ¦±£´æÔÚ____________ÖУ¬ÒºÌåÊÔ¼Á±£´æÔÚ____________ÖУ¬¼û¹âÒ×·Ö½âµÄÊÔ¼Á(È磺ŨHNO3¡¢AgNO3µÈ)Ó¦ÓÃ____________É«ÊÔ¼ÁÆ¿±£´æ¡£Çâ·úËá(HF)ÒòºÍ²£Á§ÖеÄSiO2Ç¿ÁÒ·´Ó¦¶ø¸¯Ê´²£Á§£¬Ó¦ÓÃ____________´æ·Å£»½ðÊôÄÆ¡¢¼ØÓ¦±£´æÔÚ____________ÖУ»ÉÙÁ¿°×Á×Ó¦¸Ã±£´æÔÚ____________ÖС£

(2)ÐÂÖÆÂÈË®Ðè±£´æÔÚ×ØÉ«ÊÔ¼ÁÆ¿ÖУ¬Ô­ÒòÊÇ__________________¡£

(3)ʵÑéÊÒÐÂÅäÖƵÄÁòËáÑÇÌúÈÜÒº£¬Ò»°ãÒª¼ÓÈëÉÙÁ¿___________£¬·ÀÖ¹ÔÚ¿ÕÆøÖбäÖÊ¡£

(4)ÔÚÊ¢·ÅŨÁòËáµÄÊÔ¼ÁÆ¿±êÇ©ÉÏÓ¡ÈçÏÂÁо¯Ê¾±ê¼Ç£¬ËµÃ÷ŨÁòËá¾ßÓÐ_______ÐÔ¡£

¡¾´ð°¸¡¿¹ã¿ÚÆ¿ ϸ¿ÚÆ¿ ×Ø ËÜÁÏÆ¿ úÓÍ ÀäË® ÐÂÖÆÂÈË®Öк¬ÓдÎÂÈËᣬ¼û¹â·Ö½â¶ø±äÖÊ Ìú·Û(»òÌúм) ¸¯Ê´

¡¾½âÎö¡¿

(1)¹ÌÌå´æ·ÅÔÚ¹ã¿ÚÆ¿ÖУ¬ÒºÌåÊÔ¼Á±£´æÔÚϸ¿ÚÆ¿ÖУ¬¼û¹âÒ×·Ö½âµÄÎïÖÊÐè±Ü¹â±£´æ£¬Ó¦ÓÃ×ØÉ«ÊÔ¼ÁÆ¿±£´æ£»Çâ·úËᣨHF£©ÒòºÍ²£Á§ÖеÄSiO2Ç¿ÁÒ·´Ó¦£¬²»Ò×Óò£Á§Æ¿´æ·Å¡£¿ÉÓÃËÜÁÏÆ¿´æ·Å£»½ðÊôÄÆ¡¢¼ØÄÜÓëË®ºÍÑõÆøµÈ·´Ó¦£¬Ó¦±£´æÔÚúÓÍÖУ»°×Á×ÔÚ¿ÕÆøÖÐÒ××Ôȼ£¬ÉÙÁ¿°×Á×Ó¦¸Ã±£´æÔÚÀäË®ÖУ»

´ð°¸ÊÇ£º¹ã¿ÚÆ¿£»Ï¸¿ÚÆ¿£»×Ø£»ËÜÁÏÆ¿£»ÃºÓÍ£»ÀäË®£»

(2) ÐÂÖÆÂÈË®Öк¬ÓдÎÂÈËᣬ´ÎÂÈËá²»Îȶ¨£¬¼û¹â·Ö½â£¬¹ÊÐè±£´æÔÚ×ØÉ«ÊÔ¼ÁÆ¿ÖУ»

´ð°¸ÊÇ£ºÐÂÖÆÂÈË®Öк¬ÓдÎÂÈËᣬ¼û¹â·Ö½â¶ø±äÖÊ£»

(3)ÑÇÌúÀë×Ó¾ßÓÐÇ¿µÄ»¹Ô­ÐÔ£¬ÔÚ¿ÕÆøÖÐÒ×±»ÑõÆøÑõ»¯ÎªÌúÀë×Ó£¬Òò´Ë¿ÉÒÔÔÚÐÂÅäÖƵÄÁòËáÑÇÌúÈÜÒºÖмÓÈëÉÙÁ¿µÄÌú·Û£¬·ÀÖ¹ÑÇÌúÀë×Ó±»Ñõ»¯ÎªÌúÀë×Ó£¬ÔÚ¿ÕÆøÖбäÖÊ£»

´ð°¸ÊÇ£ºÌú·Û(»òÌúм)£»

(4) ¾¯Ê¾±ê¼ÇΪ¸¯Ê´ÐÔÒºÌåµÄ±êÖ¾£¬ËµÃ÷ŨÁòËá¾ßÓи¯Ê´ÐÔ£»

¹Ê´ð°¸ÊÇ£º¸¯Ê´¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

¡¾ÌâÄ¿¡¿°±ÆøÓëÊÊÁ¿ÂÈÆø»ìºÏ·´Ó¦¿ÉÉú³ÉNH4Cl(Ë׳ÆÄÔÉ°)ºÍÒ»ÖÖÎÞÎÛȾµÄÆøÌ塣ijѧϰС×éÀûÓÃÏÂÁÐ×°ÖÃÄ£Äâ¸Ã·´Ó¦,Çë»Ø´ðÏà¹ØÎÊÌâ¡£

(1)¸ÃʵÑéÖÐËùÐèµÄÂÈÆøÊÇÓÃŨÑÎËáÓëMnO2·´Ó¦ÖÆÈ¡¡£×°ÖÃAÖÐÒÇÆ÷XµÄÃû³ÆΪ____;XÖз¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽΪ_______¡£

(2)ÒªµÃµ½¸ÉÔï´¿¾»µÄÂÈÆø,ÉÏÊöA¡¢B¡¢C×°ÖõÄÁ¬½Ó˳ÐòÒÀ´ÎΪa¡ú_____(ÓÃСд×Öĸ±íʾ)¡£

(3)ÀûÓÃE×°ÖÃ,½«ÊÊÁ¿°±ÆøÓëÂÈÆø³ä·Ö»ìºÏ·´Ó¦°±ÆøÓ¦´Ó_______(ÓÃСд×Öĸ±íʾ)ͨÈë,·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ_______________;¿ÉÄܹ۲쵽µÄÏÖÏóÊÇ___________¡£

(4)¡¶ÌƱ¾²Ý¡·¼ÇÔØÄÔÉ°ÈëÒ©¿ÉÒÔÉ¢ðöÏûÖ×,ÌìÈ»ÄÔÉ°º¬ÉÙÁ¿NH4Cl£¬ÏÖÈ¡ÌìÈ»ÄÔÉ°½øÐÐNH4Clº¬Á¿²â¶¨¡£×¼È·³ÆÈ¡Ò»¶¨ÖÊÁ¿ÄÔÉ°,Óë×ãÁ¿µÄÑõ»¯Í­»ìºÏ,ÈçÏÂͼËùʾ½øÐÐʵÑé¡£ÒÑÖª:2NH4Cl+3CuO=3Cu+N2+2HCl+3H2O ¡£

¢ÙΪ˳ÀûÍê³ÉÓйØÎïÀíÁ¿µÄ²â¶¨,ÇëÍêÉÆÏÂÁбí¸ñ:

²âÁ¿Ê±¼äµã

¼ÓÈÈÇ°

µ±¹Û²ìµ½_____ÏÖÏóʱ

²âÁ¿ÄÚÈÝ

_______________

Í£Ö¹¼ÓÈÈ,ÀäÈ´,³ÆÁ¿H×°ÖõÄ×ÜÖÊÁ¿

¢ÚÈç¹û²»ÓÃJ×°ÖÃ,²â³öNH4ClµÄº¬Á¿½«_____(Ìî¡°Æ«¸ß¡±¡°Æ«µÍ¡±»ò¡°ÎÞÓ°Ï족)¡£

¡¾ÌâÄ¿¡¿¶þÂÈ»¯¶þÁò(S2Cl2)ÔÚ¹¤ÒµÉÏÓÃÓÚÏ𽺵ÄÁò»¯¡£ÎªÔÚʵÑéÊҺϳÉS2Cl2£¬Ä³»¯Ñ§Ñо¿ÐÔѧϰС×é²éÔÄÁËÓйØ×ÊÁÏ£¬µÃµ½ÈçÏÂÐÅÏ¢£º

¢Ù½«¸ÉÔïµÄÂÈÆøÔÚ110¡æ¡«140¡æÓëÁò·´Ó¦£¬¼´¿ÉµÃS2Cl2´ÖÆ·¡£

¢ÚÓйØÎïÖʵIJ¿·ÖÐÔÖÊÈçÏÂ±í£º

ÎïÖÊ

ÈÛµã/¡æ

·Ðµã/¡æ

»¯Ñ§ÐÔÖÊ

S

112.8

444.6

ÂÔ

S2Cl2

£­77

137

ÓöË®Éú³ÉHCl¡¢SO2¡¢S£»Óë¹ýÁ¿ÂÈÆø·¢ÉúS2Cl2£«Cl22SCl2£»

ζȳ¬300¡æÒÔÉÏÍêÈ«·Ö½âΪÁòºÍÂÈÆø

Éè¼ÆʵÑé×°ÖÃͼÈçÏ£º

(1)ÉÏͼÖÐÆøÌå·¢ÉúºÍβÆø´¦Àí×°Öò»¹»ÍêÉÆ£¬ÇëÄãÌá³ö¸Ä½øÒâ¼û_______________________¡£

ÀûÓøĽøºóµÄÕýÈ·×°ÖýøÐÐʵÑ飬Çë»Ø´ðÏÂÁÐÎÊÌ⣺

(2)BÖз´Ó¦µÄÀë×Ó·½³ÌʽΪ_________________________________________________________¡£

(3)C¡¢DÖеÄÊÔ¼Á·Ö±ðÊÇ_________________¡¢_____________________¡£

(4)ÒÇÆ÷A¡¢BµÄÃû³Æ·Ö±ðÊÇ___________¡¢___________£¬FµÄ×÷ÓÃÊÇ_______________________¡£

(5)Èç¹ûÔÚ¼ÓÈÈEʱζȹý¸ß£¬¶ÔʵÑé½á¹ûµÄÓ°Ïì_________________________________£»ÔÚFÖпÉÄܳöÏÖµÄÏÖÏóÊÇ________________________________________________¡£

(6)S2Cl2´ÖÆ·ÖпÉÄÜ»ìÓеÄÔÓÖÊÊÇ(ÌîдÁ½ÖÖÎïÖʵĻ¯Ñ§Ê½)______________¡¢_____________£¬ÎªÁËÌá¸ßS2Cl2µÄ´¿¶È£¬¹Ø¼üµÄ²Ù×÷ÊÇ¿ØÖƺÃζȺÍ_____________________________________¡£

¡¾ÌâÄ¿¡¿½ðÊôÊ´¿Ì¼Ó¹¤¹ý³ÌÖУ¬³£ÓÃÑÎËá¶ÔÆä±íÃæÑõ»¯Îï½øÐÐÇåÏ´£¬»á²úÉúËáÏ´·ÏË®¡£ pHÔÚ1.5×óÓÒµÄijËáÏ´·ÏË®Öк¬ÌúÔªËØÖÊÁ¿·ÖÊýÔ¼3%£¬ÆäËû½ðÊôÔªËØÈçÍ­¡¢Äø¡¢Ð¿¡¢ ¸õŨ¶È½ÏµÍ£¬¹¤ÒµÉÏ×ÛºÏÀûÓÃËáÏ´·ÏË®¿ÉÖƱ¸ÈýÂÈ»¯Ìú¡£ÖƱ¸¹ý³ÌÈçÏ£º

Ïà¹Ø½ðÊôÀë×ÓÉú³ÉÇâÑõ»¯Îï³ÁµíµÄpHÈçϱíËùʾ£º

»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©¡°Öк͡±Ê±·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ__________________£¬µ÷½ÚpHÖÁ________·¶Î§£¬ÓÐÀûÓÚºóÐøÖƱ¸µÃ´¿¶È½Ï¸ßµÄ²úÆ·¡£

£¨2£©ËáÈÜ´¦ÀíÖкͺóµÄÂËÔü£¬Ê¹ÌúÔªËؽþ³ö¡£ÂËÔüºÍ¹¤ÒµÑÎËᷴӦʱ£¬²»Í¬·´Ó¦Î¶ÈÏ Ìú½þ³öÂÊËæʱ¼ä±ä»¯Èçͼ(a)Ëùʾ£¬¿ÉÖªËáÈܵÄ×î¼ÑζÈΪ_______________¡£°´ÕÕ²»Í¬µÄ¹ÌÒº±È£¨ÂËÔüºÍ¹¤ÒµÑÎËáµÄͶÈëÌå»ý±È£©½øÐз´Ó¦Ê±£¬Ìú½þ³öÂÊËæʱ¼ä±ä»¯Èç ͼ(b)Ëùʾ£¬Êµ¼ÊÉú²úÖйÌÒº±ÈÑ¡Ôñ1.5:1µÄÔ­ÒòÊÇ___________¡£

£¨3£©Ñõ»¯Ê±£¬¿ÉÑ¡ÂÈËáÄÆ»ò¹ýÑõ»¯ÇâΪÑõ»¯¼Á£¬Èô100L¡°ËáÈÜ¡±ËùµÃÈÜÒºÖÐFe 2£«º¬Á¿Îª1.2molL1£¬ÔòÐèͶÈëµÄÑõ»¯¼Á¹ýÑõ»¯ÇâµÄÖÊÁ¿Îª_____________¡£

£¨4£©Ñõ»¯Ê±£¬³ý¿ÉÍâ¼ÓÑõ»¯¼ÁÍ⣬Ҳ¿É²ÉÓöèÐԵ缫µç½âµÄ·½·¨£¬´ËʱÒõ¼«µÄµç¼«·´Ó¦Ê½Îª____£¬µç½â×Ü·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ ___¡£

£¨5£©½«µÃµ½µÄFeCl3ÈÜÒºÔÚHClÆø·ÕÖÐ_________¡¢¹ýÂË¡¢Ï´µÓ¡¢¸ÉÔïµÃFeCl36H2O¾§Ìå¡£

¡¾ÌâÄ¿¡¿ºÏ³É°±ËùÐèH2È¡×ÔCH4£¬CH4ºÍO2×÷ÓóÉCO2¡¢H2£¨·´Ó¦¢Ù£©£¬È»¶øCH4ºÍO2·´Ó¦»¹ÄÜÉú³ÉCO2¡¢H2O£¨·´Ó¦¢Ú£©£¬µ±ÓÐË®Éú³Éʱ£¬H2OºÍCH4·´Ó¦£¨·´Ó¦¢Û£©¡£Ï±í ΪÈý¸ö·´Ó¦ÔÚ²»Í¬Î¶ÈϵÄƽºâ³£ÊýK¡£

£¨1£©·´Ó¦¢ÙµÄƽºâ³£ÊýK¢ÙµÄ±í´ïʽΪ_______________¡£

£¨2£©·´Ó¦¢Ù¢Ú¢ÛµÄƽºâ³£ÊýK¢Ù¡¢K¢Ú¡¢K¢ÛÖ®¼äµÄ¹ØϵΪK¢Ú=_____________£¨Óú¬K¢Ù¡¢ K¢ÛµÄʽ×Ó±íʾ£©¡£·´Ó¦¢Ù¢Ú¢ÛµÄ·´Ó¦ìʱ䣺¦¤H¢Ù¡¢¦¤H¢Ú¡¢¦¤H¢ÛÖ®¼äµÄ¹ØϵΪ¦¤H¢Ù= _____________£¨Óú¬¦¤H¢Ú¡¢¦¤H¢ÛµÄʽ×Ó±íʾ£©¡£

£¨3£©ºãÎÂÌõ¼þÏ£¬·´Ó¦¢ÛµÄÄÜÁ¿Óë·´Ó¦½ø³Ì¹ØϵӦ¶ÔÓ¦ÏÂͼÖеÄ_____________£¬·´Ó¦¢Ú µÄÄÜÁ¿Óë·´Ó¦½ø³Ì¹ØϵӦ¶ÔÓ¦ÏÂͼÖеÄ_____________¡£

£¨4£©ÎªÊ¹·´Ó¦¾¡¿ÉÄÜ°´Éú³ÉH2µÄ·½Ïò½øÐУ¬ÈôÖ»¿¼ÂÇ·´Ó¦¢Û£¬ÇÒ²»½µµÍ·´Ó¦ËÙÂÊ£¬¿É²É È¡__________´ëÊ©£»ÈôÖ»¿¼ÂÇ·´Ó¦¢Ù¢Ú£¬³ý²ÉÈ¡¿ØδëÊ©Í⣬»¹¿É²ÉÈ¡_____________£¨Ð´³öÁ½Ìõ´ëÊ©¼´¿É£©¡£

£¨5£©250¡æʱ£¬ÒÔÄøºÏ½ðΪ´ß»¯¼Á£¬·¢ÉúCO2(g)+CH4(g) 2CO(g)+2H2(g)£¬Ïò40L µÄÃܱÕÈÝÆ÷ÖÐͨÈë6molCO2(g)ºÍ6molCH4(g)£¬Æ½ºâʱ²âµÃÌåϵÖÐCH4µÄÌå»ý·ÖÊý Ϊ10%£¬Ôò»ìºÏÆøÌåµÄÃܶÈΪ______g/L£¬CO2µÄת»¯ÂÊΪ__________£¨±£ÁôÈýλÓÐЧÊý×Ö£©¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø