ÌâÄ¿ÄÚÈÝ

ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£¨¡¡¡¡£©
A£®Ïò°±Ë®ÖмÓˮϡÊͺó£¬ÈÜÒºÖгýÁËH2OÒÔÍâËùÓÐ΢Á£Å¨¶È¶¼Ï½µ
B£®25¡æʱ£¬½«10mL pH=aµÄÑÎËáÓë100mLpH=bµÄBa£¨OH£©2ÈÜÒº»ìºÏºóÇ¡ºÃÖкͣ¬Ôòa+b=13
C£®µÈÎïÖʵÄÁ¿Å¨¶ÈµÄNaClÈÜÒººÍCH3COONaÈÜÒºµÈÌå»ý»ìºÏ£¬Ôò»ìºÏÈÜÒºÖÐÀë×ÓŨ¶È´óС¹ØϵΪ£ºc£¨C1-£©£¾c£¨Na+£©£¾c£¨CH3COO-£©£¾c£¨OH-£©£¾c£¨H+£©
D£®µÈÌå»ýµÈÎïÖʵÄÁ¿Å¨¶ÈµÄNaXºÍÈõËáHX»ìºÏºóµÄÈÜÒºÏÔ¼îÐÔ£¬Ôò»ìºÏÈÜÒºÖÐ΢Á£Å¨¶È´óС¹ØϵΪ£ºc£¨X-£©£¾c£¨Na+£©£¾c£¨HX£©£¾c£¨OH-£©£¾c£¨H+£©
A£®Ï¡ÊÍ°±Ë®Ê±£¬ÈÜÒºÖÐÇâÑõ¸ùÀë×ÓŨ¶È¼õС£¬Î¶Ȳ»±ä£¬Ë®µÄÀë×Ó»ý³£Êý²»±ä£¬ÔòÈÜÒºÖÐÇâÀë×ÓŨ¶ÈÔö´ó£¬¹ÊA´íÎó£»
B£®¶þÕßÇ¡ºÃÖкͣ¬ËµÃ÷ËáÖÐn£¨H+£©µÈÓÚ¼îÖÐn£¨HO-£©£¬Ôò10-a mol/L¡Á0.01L=10 b-14mol/L¡Á0.1L£¬Ôòa+b=13£¬¹ÊBÕýÈ·£»
C£®´×ËáÄÆΪǿ¼îÈõËáÑΣ¬ÆäÈÜÒº³Ê¼îÐÔ£¬¸ù¾ÝÎïÁÏÊغãµÃc£¨Na+£©£¾c£¨C1-£©£¬¹ÊC´íÎó£»
D£®µÈÌå»ýµÈÎïÖʵÄÁ¿Å¨¶ÈµÄNaXºÍÈõËáHX»ìºÏºóµÄÈÜÒºÏÔ¼îÐÔ£¬ËµÃ÷X-µÄË®½â³Ì¶È´óÓÚHXµÄµçÀë³Ì¶È£¬Ôòc£¨X-£©£¼c£¨HX£©£¬¹ÊD´íÎó£»
¹ÊÑ¡B£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
¸ù¾ÝÒªÇó»Ø´ðÏÂÁи÷Ìâ
£¨¢ñ£©ÏÖÓÐ ¢ÙÂÁ ¢ÚNH3¢ÛÇâÑõ»¯ÄÆÈÜÒº ¢ÜҺ̬ÂÈ»¯Çâ ¢ÝAgCl¹ÌÌå¢Þ±ù´×Ëá ¢ßÕáÌÇ£¬Ìî¿Õ»Ø´ð£¨ÌîÐòºÅ£©£º
ÒÔÉÏÎïÖÊÖУ¨1£©ÊôÓÚµç½âÖʵÄÊÇ      £»£¨2£©ÊôÓڷǵç½âÖʵÄÊÇ     £»
£¨3£©ÊôÓÚÇ¿µç½âÖʵÄÊÇ    £»£¨4£©Äܵ¼µçµÄÊÇ         ¡£
£¨¢ò£©Ð´³öÏÂÁз´Ó¦µÄ»¯Ñ§·½³Ìʽ£º
¢ÙÓÐNaHCO3Éú³ÉµÄ»¯ºÏ·´Ó¦                      
¢Ú ÓÐMgCl2²Î¼ÓµÄ·Ö½â·´Ó¦                     
¢Û ÓÐFe2O3²Î¼ÓµÄÖû»·´Ó¦                      
¢Ü ÓÐHNO3Éú³ÉµÄ¸´·Ö½â·´Ó¦                   
(¢ó).ͬÎÂͬѹÌõ¼þÏ£¬Í¬Ìå»ýµÄCH4ºÍSO2µÄÖÊÁ¿Ö®±ÈÊÇ     £»Í¬ÖÊÁ¿µÄCH4ºÍSO2µÄÌå»ýÖ®±ÈÊÇ     £»ÈôÁ½ÕßËùº¬Ô­×Ó¸öÊý×ÜÊýÏàµÈ£¬ÔòCH4ºÍSO2µÄÖÊÁ¿Ö®±ÈÊÇ    ¡£
£¨¢ô£©°ÑÌúƬºÍʯī°ôÓÃÏÂÁÐa¡¢bÁ½ÖÖ·½Ê½·ÅÔÚÊ¢ÓÐÏ¡ÁòËáÄÆÈÜÒººÍ·Ó̪ÊÔÒº»ìºÏÈÜÒºµÄ²£Á§Æ÷ÃóÖУ¬¾­¹ýÒ»¶Îʱ¼äºó£¬Ê×Ïȹ۲쵽ÈÜÒº±äºìµÄÇøÓòÊÇ   £¨ÌîÐòºÅ£©¡£
A£®¢ñºÍ¢ó¸½½üB£®¢ñºÍ¢ô¸½½üC£®¢òºÍ¢ó¸½½üD£®¢òºÍ¢ô¸½½ü

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø