ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿£¨1£©Ä³Î¶ÈÏ£¬ÔÚÌå»ýΪ5 LµÄÈÝÆ÷ÖУ¬A¡¢B¡¢CÈýÖÖÎïÖÊÎïÖʵÄÁ¿Ëæ×Åʱ¼ä±ä»¯µÄ¹ØϵÈçͼËùʾ£¬Ôò¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ__________£¬2 sÄÚÓÃAµÄŨ¶È±ä»¯ºÍÓÃBµÄŨ¶È±ä»¯±íʾµÄƽ¾ù·´Ó¦ËÙÂÊ·Ö±ðΪ________¡¢________¡£
£¨2£©°Ñ0.6 mol XÆøÌåÓë0.6 mol YÆøÌå»ìºÏÓÚ2 LÈÝÆ÷Öз¢Éú·´Ó¦£º2X(g)£«Y(g)=nZ(g)£«2W(g)£¬2 minÄ©ÒÑÉú³É0.2 mol W£¬Èô²âµÃÒÔv(Z)Ũ¶È±ä»¯±íʾµÄv(Z)£½0.1 mol/(L¡¤min)¡£Çó£º
(1)n£½_____£¿
(2)Ç°2 minÄÚ£¬v(X)£½_____£¿
(3)2 minĩʱYµÄŨ¶È_____£¿
¡¾´ð°¸¡¿2A=2B+C(¿ÉÄæ·´Ó¦) 0.08mol/(L.s) 0.12mol/(L.s) 4 0.05mol/(L.min) 0.25mol/L
¡¾½âÎö¡¿
£¨1£©¸ù¾ÝͼÏñ½øÐзÖÎö£¬ÔÙ¸ù¾Ý»¯Ñ§·´Ó¦Öи÷ÎïÖʵÄÎïÖʵÄÁ¿±ä»¯Á¿Ö®±ÈµÈÓÚ»¯Ñ§¼ÆÁ¿ÊýÖ®±ÈµÃ³ö·½³Ìʽ£»
£¨2£©¢ÙÏȼÆËã³ö2minÄÚZµÄÎïÖʵÄÁ¿±ä»¯£¬¸ù¾ÝÎïÖʵÄÁ¿Ó뻯ѧ¼ÆÁ¿Êý³ÉÕý±È¼ÆËã³ön£»
¢Ú¸ù¾Ý»¯Ñ§·´Ó¦ËÙÂÊÓ뻯ѧ¼ÆÁ¿Êý³ÉÕý±È¼ÆËã³öÇ°2minÄÚÓÃX±íʾµÄ·´Ó¦ËÙÂÊ£»
¢Û¸ù¾ÝZµÄÎïÖʵÄÁ¿±ä»¯¼°ZÓëYµÄ¼ÆÁ¿Êý¹Øϵ¼ÆËã³ö2minÄÚÏûºÄYµÄÎïÖʵÄÁ¿£¬È»ºó¼ÆËã³ö2minʱYµÄÎïÖʵÄÁ¿£¬×îºó¸ù¾Ýc=n/V¼ÆËã³ö2minÄ©YµÄŨ¶È¡£
£¨1£©ÓÉͼÏó¿ÉÒÔ¿´³öAµÄÎïÖʵÄÁ¿¼õС£¬B¡¢CµÄÎïÖʵÄÁ¿Ôö¶à£¬ÔòAΪ·´Ó¦ÎB¡¢CΪÉú³ÉÎ»¯Ñ§·´Ó¦Öи÷ÎïÖʵÄÎïÖʵÄÁ¿±ä»¯Á¿Ö®±ÈµÈÓÚ»¯Ñ§¼ÆÁ¿ÊýÖ®±È£¬ÔòÓС÷n£¨A£©£º¡÷n£¨B£©£º¡÷n£¨C£©=£¨1.6mol-0.8mol£©£º1.2mol£º0.4mol=2£º3£º1£¬Ôò·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ2A3B+C£»·´Ó¦¿ªÊ¼ÖÁ2s£¬ÓÃA±íʾµÄƽ¾ù·´Ó¦ËÙÂÊΪv=¡÷c/¡÷t=
=0.08mol¡¤L-1¡¤s-1£¬ÓÃB±íʾµÄƽ¾ù·´Ó¦ËÙÂÊΪv=¡÷c/¡÷t=
=0.12 mol¡¤L-1¡¤s-1£¬¹Ê´ð°¸Îª£º2A
3B+C£¬0.08mol¡¤L-1¡¤s-1£¬0.12mol¡¤L-1¡¤s-1¡£
£¨2£©¢ÙZŨ¶È±ä»¯À´±íʾµÄƽ¾ùËÙÂÊΪ0.1mol/(L¡¤min)£¬ÔòZµÄÎïÖʵÄÁ¿±ä»¯Îª£º0.1mol/(L¡¤min)¡Á2L¡Á2min=0.4mol£¬¸ù¾ÝÎïÖʵÄÁ¿Ö®±ÈµÈÓÚ¼ÆÁ¿ÊýÖ®±È¿ÉÒÔÖªµÀ£¬n£º2=0.4mol£º0.2mol=2£º1£¬¿ÉµÃ³ö£ºn=4£¬¹Ê´ð°¸Îª£º4¡£
¢ÚZÓëXµÄ»¯Ñ§¼ÆÁ¿Êý·Ö±ðΪ4¡¢2£¬ÔòÇ°2minÄÚÓÃX±íʾµÄ·´Ó¦ËÙÂÊÓëZ±íʾµÄ·´Ó¦ËÙÂÊÓ뻯ѧ¼ÆÁ¿Êý³ÉÕý±È£¬¼´v(X)=v(Z)=
¡Á0.1mol/(L¡¤min)=0.05mol/(L¡¤min)£¬¹Ê´ð°¸Îª£º0.05mol/(L¡¤min)¡£
¢Û2minÄÚZµÄÎïÖʵÄÁ¿±ä»¯Îª£º0.1mol/(L¡¤min)¡Á2L¡Á2min=0.4mol£¬¸ù¾Ý·´Ó¦2X(g)£«Y(g)=4Z(g)£«2W(g)¿ÉÒÔÖªµÀ2minÄ©×ܹ²ÏûºÄYµÄÎïÖʵÄÁ¿Îª0.4mol¡Á=0.1mol£¬Ôò2minÄ©Ê£ÓàYµÄÎïÖʵÄÁ¿Îª£º0.6mol-0.1mol=0.5mol£¬ËùÒÔ2minÄ©YµÄÎïÖʵÄÁ¿Å¨¶ÈΪ£º
=0.25mol/L£¬¹Ê´ð°¸Îª£º0.25mol/L¡£
![](http://thumb2018.1010pic.com/images/loading.gif)