ÌâÄ¿ÄÚÈÝ

¡¾ÌâÄ¿¡¿ÒÑ֪ͭµÄÅäºÏÎïA½á¹¹Èçͼ¡£Çë»Ø´ðÏÂÁÐÎÊÌ⣺

(1)д³ö»ù̬CuµÄÍâΧµç×ÓÅŲ¼Ê½_____________________________________¡£

(2)ÅäÌå°±»ùÒÒËá¸ù(H2NCH2COO¡¥)ÊÜÈÈ·Ö½â¿É²úÉúCO2ºÍN2£¬N2ÖЦҼüºÍ¦Ð¼üÊýÄ¿Ö®±ÈÊÇ__________£»N2OÓëCO2»¥ÎªµÈµç×ÓÌ壬ÔòN2OµÄµç×ÓʽΪ____________¡£

(3)ÔÚCu´ß»¯Ï£¬¼×´¼¿É±»Ñõ»¯Îª¼×È©£¬¼×È©·Ö×ÓÖÐHCOµÄ¼ü½Ç_____(Ñ¡Ìî¡°´óÓÚ¡±¡¢¡°µÈÓÚ¡±»ò¡°Ð¡ÓÚ¡±)120¡ã£»¼×È©ÄÜÓëË®ÐγÉÇâ¼ü£¬ÇëÔÚÈçͼÖбíʾ³öÀ´_____¡£

(4)Á¢·½µª»¯ÅðÈçͼÓë½ð¸Õʯ½á¹¹ÏàËÆ£¬Êdz¬Ó²²ÄÁÏ¡£Á¢·½µª»¯Åð¾§ÌåÄÚB-N¼üÊýÓëÅðÔ­×ÓÊýÖ®±ÈΪ___________£»

(5)Cu¾§ÌåµÄ¶Ñ»ý·½Ê½ÈçͼËùʾ£¬ÉèCuÔ­×Ӱ뾶Ϊa£¬¾§ÌåÖÐCuÔ­×ÓµÄÅäλÊýΪ________£¬¾§ÌåµÄ¿Õ¼äÀûÓÃÂÊΪ______¡£(ÒÑÖª:£¬ÁÐʽ²¢¼ÆËã³ö½á¹û)

¡¾´ð°¸¡¿3d104s1 1¡Ã2 ´óÓÚ 4¡Ã1 12 74.76%

¡¾½âÎö¡¿

(1)CuÔ­×ÓºËÍâÓÐ29¸öµç×Ó£¬¸ù¾Ý¹¹ÔìÔ­ÀíÊéдÆä»ù̬ԭ×ÓºËÍâµç×ÓÅŲ¼Ê½£»

(2)¸ù¾ÝN2µÄ½á¹¹Ê½ÎªN¡ÔNÅжϦҼüºÍ¦Ð¼üÊýÄ¿Ö®±È£»µÈµç×ÓÌåµÄ½á¹¹ÏàËÆ£¬¸ù¾Ý¶þÑõ»¯Ì¼µç×ÓʽÊéдN2OµÄµç×Óʽ£»

(3)¼×È©ÖÐCÊÇsp2ÔÓ»¯£¬ÊÇƽÃæÈý½ÇÐΣ¬½áºÏ¹Â¶Ôµç×ÓÓë³É¼üµç×Ó¶ÔµÄ×÷Ó÷ÖÎöÅжϼü½ÇµÄ´óС£»¼×È©·Ö×ÓÖеÄOÔ­×ÓºÍË®·Ö×ÓÖеÄHÔ­×ÓÄÜÐγÉÇâ¼ü£»

(4)¸Ã¾§°ûÖÐNÔ­×ÓÔÚ¾§°ûÄÚ²¿£¬Ã¿¸öNÔ­×ÓÐγÉ4¸öB-N¼ü£¬¼ÆËãÅжÏB-N¼ü¸öÊýÓëBÔ­×Ó¸öÊýÖ®±È£»

(5)Cu¾§ÌåµÄ¶Ñ»ý·½Ê½ÊÇÃæÐÄÁ¢·½×îÃܶѻý£¬¾Ý´ËÅжÏÅäλÊý£»Á¢·½ÌåµÄÃæµÄ¶Ô½ÇÏß³¤ÊÇ4r£¬¼ÆËã³öÁ¢·½ÌåµÄÀⳤºÍ¾§°ûµÄÌå»ý£¬¸ù¾Ý¾§°ûµÄ½á¹¹¼ÆËã³öCuÔ­×ӵĸöÊý£¬×îºó¸ù¾Ý¾§ÌåµÄ¿Õ¼äÀûÓÃÂÊ=¡Á100%¼ÆËã¡£

(1)CuÔ­×ÓºËÍâÓÐ29¸öµç×Ó£¬¸ù¾Ý¹¹ÔìÔ­ÀíÊéдÆä»ù̬ԭ×ÓºËÍâµç×ÓÅŲ¼Ê½Îª[Ar]3d104s1£¬ËùÒÔ»ù̬CuµÄÍâΧµç×ÓÅŲ¼Ê½Îª£º3d104s1£¬¹Ê´ð°¸Îª£º3d104s1£»

(2)N2µÄ½á¹¹Ê½ÎªN¡ÔN£¬¦Ò¼üºÍ¦Ð¼üÊýÄ¿Ö®±ÈΪ1¡Ã2£»µÈµç×ÓÌåµÄ½á¹¹ÏàËÆ£¬¸ù¾Ý¶þÑõ»¯Ì¼µç×Óʽ¿ÉÒÔÊéдN2OµÄµç×ÓʽΪ£¬¹Ê´ð°¸Îª£º1¡Ã2£»£»

(3)¼×È©ÖÐCÊÇsp2ÔÓ»¯£¬ÊÇƽÃæÈý½ÇÐΣ¬CÔ­×ÓÔÚÈý½ÇÐÎÄÚ²¿£¬C-HÓëC-H¼ü¼Ð½ÇÀíÂÛÉÏÊÇ120¡ã£¬µ«ÓÉÓÚÓÐôÊ»ùÑõµÄ¹Â¶Ôµç×ÓµÄÅų⣬ʵ¼Ê¼ü½ÇÓ¦¸ÃÂÔСÓÚ120¡ã£¬ËùÒÔ¼×È©·Ö×ÓÖÐHCOµÄ¼ü½Ç´óÓÚ120¡ã£»¼×È©·Ö×ÓÖеÄOÔ­×ÓºÍË®·Ö×ÓÖеÄHÔ­×ÓÄÜÐγÉÇâ¼ü£¬ÆäÇâ¼ü±íʾΪ£¬¹Ê´ð°¸Îª£º´óÓÚ£»£»

(4)¸Ã¾§°ûÖÐNÔ­×ÓÔÚ¾§°ûÄÚ²¿£¬¸öÊýÊÇ4£¬Ã¿¸öNÔ­×ÓÐγÉ4¸öB-N¼ü£¬B-N¼ü¸öÊýΪ16£»BÔ­×ÓλÓÚ¾§°û¶¥µãºÍÃæÐÄ£¬¸öÊý=8¡Á+6¡Á=4£¬ÔòB-N¼üÓëBÔ­×Ó¸öÊýÖ®±ÈΪ16¡Ã4=4¡Ã1£¬¹Ê´ð°¸Îª£º4¡Ã1£»

(5)Cu¾§ÌåµÄ¶Ñ»ý·½Ê½ÊÇÃæÐÄÁ¢·½×îÃܶѻý£¬ËùÒÔÅäλÊýÊÇ12£»ÓÉͼ¿ÉÖª£¬Á¢·½ÌåµÄÃæµÄ¶Ô½ÇÏß³¤ÊÇ4a£¬ËùÒÔÁ¢·½ÌåµÄÀⳤ=2a£¬1¸öCuµÄÌå»ýÊǦÐa3£¬¾§°ûÖÐCuÔ­×ӵĸöÊý=8¡Á+6¡Á=4¸ö£¬ËùÒÔ¾§ÌåµÄ¿Õ¼äÀûÓÃÂÊΪ¡Á100%=74.76%£¬¹Ê´ð°¸Îª£º12£»74.76%¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

¡¾ÌâÄ¿¡¿Ñо¿»¯Ñ§·´Ó¦Ê±£¬¼ÈÒª¿¼ÂÇÎïÖʱ仯ÓëÄÜÁ¿±ä»¯£¬ÓÖÒª¹Ø×¢·´Ó¦µÄ¿ìÂýÓëÏ޶ȡ£»Ø´ðÏÂÁÐÎÊÌâ:

(1)NH3»¹Ô­NOÊÇÖØÒªµÄÑÌÆøÍÑÏõ¼¼Êõ£¬Æä·´Ó¦¹ý³ÌÓëÄÜÁ¿¹ØϵÈçͼËùʾ

¢ÙÉÏͼÖÐÒòΪ¸Ä±äÁË·´Ó¦Ìõ¼þ£¬·´Ó¦µÄ»î»¯ÄÜ£ºb_______(Ìî¡°£¾¡±¡°£¼£¢»ò¡°£½¡±)a¡£

¢ÚÍÑÏõ·´Ó¦µÄÈÈ»¯Ñ§·½³Ìʽ¿É±íʾΪ·´Ó¦Îï¡úÉú³ÉÎï¡÷H£½______(ÓÃE1¡¢E2µÄ´úÊýʽ±íʾ)¡£

¢ÛÑо¿·¢ÏÖ£¬Ò»¶¨Ìõ¼þϵÄÍÑÏõ·´Ó¦¹ý³Ì¿ÉÄÜÈçͼËùʾ£¬¸ù¾ÝÑõ»¯»¹Ô­·´Ó¦ÖÐÎïÖʵÄ×÷Óã¬NOΪ_______¼Á£¬ÍÑÏõ×Ü·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ_______________¡£

(2)Ò»¶¨Î¶ÈÏ£¬½«²»Í¬ÎïÖʵÄÁ¿µÄH2O(g)ºÍCO·Ö±ðͨÈëÈÝ»ýΪ1LµÄºãÈÝÃÜÈÝÆ÷ÖУ¬½øÐз´Ó¦H2O(g)£«CO(g)CO2(g)£«H2(g)£¬µÃµ½Èç±íËùʾµÄÈý×éÊý¾Ý

ÊÔÑé±àºÅ

ζÈ/¡æ

ÆðʼÁ¿/mol

ƽºâÁ¿/mol

´ïµ½Æ½ºâʱ¼ä/min

H2O(g)

CO(g)

CO(g)

H2(g)

1

650

2.0

4.0

3.0

1.0

5

2

900

1.0

2.0

1.8

0.2

4

3

900

a

b

c

d

t

¢Ù4mimÄÚ£¬ÊµÑé2ÖÐv(CO2)£½______£» 900¡æʱ£¬·´Ó¦µÄƽºâ³£ÊýΪ______£»½µµÍζÈʱ£¬Æ½ºâ³£Êý»á________(Ìî¡°Ôö´ó¡±¡°¼õС¡±»ò¡°²»±ä¡±)¡£

¢Ú650¡æʱ£¬ÈôÔÚ´ËÈÝÆ÷ÖгäÈë2.0 mol H2O(g)¡¢1.0molCO(g)¡¢1.0 mol CO2(g)ºÍ xmol H2(g)£¬ÒªÊ¹·´Ó¦ÔÚ¿ªÊ¼Ê±ÏòÕý·´Ó¦·½Ïò½øÐУ¬ÔòxÓ¦Âú×ãµÄÌõ¼þÊÇ__________¡£

Èôa£½2.0£®b£½1.0£¬ÔòƽºâʱʵÑé2ÖÐH2O(g)ºÍʵÑé3ÖÐCO(g)µÄת»¯ÂÊ(a)µÄ¹ØϵΪa(H2O) _______ (Ìî¡°£¾¡±£¼¡±³É£½¡±)a(CO)¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø