ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿ÔªËØÖÜÆÚ±íÊÇѧϰ»¯Ñ§µÄÖØÒª¹¤¾ß,ËüÒþº¬Ðí¶àÐÅÏ¢ºÍ¹æÂÉ¡£Ï±íËùÁÐÊÇÁùÖÖ¶ÌÖÜÆÚÔªËصÄÔ×Ӱ뾶¼°Ö÷Òª»¯ºÏ¼Û(ÒÑÖªîëÔªËصÄÔ×Ӱ뾶Ϊ0.089 nm)¡£
ÔªËØ´úºÅ | A | B | C | D | X | Y |
Ô×Ӱ뾶/nm | 0.037 | 0.143 | 0.102 | 0.099 | 0.074 | 0.075 |
Ö÷Òª»¯ºÏ¼Û | +1 | +3 | +6,-2 | -1 | -2 | +5,-3 |
£¨1£©CÔªËØÔÚÖÜÆÚ±íÖеÄλÖÃΪ________£¬ÆäÀë×ӽṹʾÒâͼΪ£º_______¡£
£¨2£©BµÄ×î¸ß¼ÛÑõ»¯Îï¶ÔÓ¦µÄË®»¯ÎïÓëYµÄ×î¸ß¼ÛÑõ»¯Îï¶ÔÓ¦µÄË®»¯Îï·´Ó¦µÄÀë×Ó·½³ÌʽΪ___¡£
£¨3£©¹ØÓÚC¡¢D Á½ÖÖÔªËØ˵·¨ÕýÈ·µÄÊÇ__________£¨ÌîÐòºÅ£©¡£
a.¼òµ¥Àë×ӵİ뾶D>C b.Æø̬Ç⻯ÎïµÄÎȶ¨ÐÔD±ÈCÇ¿ c.×î¸ß¼ÛÑõ»¯Îï¶ÔÓ¦µÄË®»¯ÎïµÄËáÐÔC±ÈDÇ¿
£¨4£©ÔÚ100mL18mol/LµÄCµÄ×î¸ß¼ÛÑõ»¯Îï¶ÔÓ¦µÄË®»¯ÎïµÄŨÈÜÒºÖмÓÈë¹ýÁ¿µÄÍƬ£¬¼ÓÈÈʹÆä³ä·Ö·´Ó¦£¬²úÉúÆøÌåµÄÌå»ýΪ6.72L(±ê¿öÏ£©£¬Ôò¸Ã·´Ó¦¹ý³ÌÖÐתÒƵĵç×ÓÊýΪ______¡£
£¨5£©Ð´³öÓÉA¡¢D¡¢XÈýÖÖÔªËØ×é³ÉµÄijÖÖ¿ÉÒÔÏû¶¾É±¾úÎïÖʵĵç×Óʽ_____________¡£
£¨6£©±È½ÏYÔªËØÓëÆäͬ×å¶ÌÖÜÆÚÔªËصÄÇ⻯ÎïµÄÈ۷еã¸ßµÍ__ £¾___ (ÌîÇ⻯Îﻯѧʽ£©£¬ÀíÓÉ___________¡£
¡¾´ð°¸¡¿µÚÈýÖÜÆÚVIA×å Al(OH)3+3H+==Al3++3H2O b 0.6NA NH3 PH3 Á½Õ߶¼Îª·Ö×Ó¾§Ì壬NH3´æÔÚ·Ö×Ó¼äÇâ¼ü£¬ÔöÇ¿·Ö×Ó¼ä×÷ÓÃÁ¦£¬µ¼ÖÂÈ۷еã±ÈPH3¸ß
¡¾½âÎö¡¿
¸ù¾ÝÔªËصÄÔ×Ӱ뾶Ïà¶Ô´óСºÍÖ÷Òª»¯ºÏ¼ÛÊ×ÏÈÅжϳöÔªËØÖÖÀ࣬Ȼºó½áºÏÔªËØÖÜÆÚÂɺÍÏà¹ØÎïÖʵÄÐÔÖÊ·ÖÎö½â´ð¡£
AµÄÖ÷Òª»¯ºÏ¼ÛÊÇ+1¼Û£¬Ô×Ӱ뾶×îС£¬AÊÇH£»CµÄÖ÷Òª»¯ºÏ¼ÛÊÇ+6ºÍ£2¼Û£¬Òò´ËCÊÇS£»BµÄÖ÷Òª»¯ºÏ¼ÛÊÇ+3¼Û£¬Ô×Ӱ뾶×î´ó£¬ËùÒÔBÊÇAl£»DºÍXµÄÖ÷Òª»¯ºÏ¼Û·Ö±ðÊÇ£1ºÍ£2¼Û£¬Ôò¸ù¾ÝÔ×Ӱ뾶¿ÉÅжÏDÊÇCl£¬XÊÇO¡£YµÄÖ÷Òª»¯ºÏ¼ÛÊÇ+5ºÍ£3¼Û£¬Ô×Ӱ뾶´óÓÚÑõÔ×Ó¶øСÓÚÂÈÔ×Ó£¬ÔòYÊÇN¡£
£¨1£©CÔªËØÊÇS£¬ÔÚÖÜÆÚ±íÖеÄλÖÃΪµÚÈýÖÜÆÚVIA×壬ÆäÀë×ӽṹʾÒâͼΪ¡£
£¨2£©BµÄ×î¸ß¼ÛÑõ»¯Îï¶ÔÓ¦µÄË®»¯ÎïÊÇÇâÑõ»¯ÂÁ£¬ÓëYµÄ×î¸ß¼ÛÑõ»¯Îï¶ÔÓ¦µÄË®»¯ÎïÏõËá·´Ó¦µÄÀë×Ó·½³ÌʽΪAl(OH)3+3H+£½Al3++3H2O¡£
£¨3£©a.ÁòÀë×ÓºÍÂÈÀë×Ó¾ùÊÇ18µç×Ó£¬ºËµçºÉÊýÔ½´óÀë×Ӱ뾶ԽС£¬Ôò¼òµ¥Àë×ӵİ뾶D£¼C£¬a´íÎó£»
b.·Ç½ðÊôÐÔCl£¾S£¬·Ç½ðÊôÐÔԽǿ£¬Ç⻯ÎïÔ½Îȶ¨£¬ÔòÆø̬Ç⻯ÎïµÄÎȶ¨ÐÔD±ÈCÇ¿£¬bÕýÈ·£»
c.·Ç½ðÊôÐÔԽǿ£¬×î¸ß¼Ûº¬ÑõËáµÄËáÐÔԽǿ£¬Ôò×î¸ß¼ÛÑõ»¯Îï¶ÔÓ¦µÄË®»¯ÎïµÄËáÐÔD±ÈCÇ¿£¬c´íÎó£»
´ð°¸Ñ¡b£»
£¨4£©Å¨ÁòËáºÍÍ·´Ó¦Éú³ÉÁòËáÍ¡¢¶þÑõ»¯ÁòºÍË®£¬ÁòÔªËØ»¯ºÏ¼Û´Ó+6¼Û½µµÍµ½+4¼Û£¬µÃµ½2¸öµç×Ó¡£·´Ó¦ÖÐÉú³É¶þÑõ»¯ÁòµÄÎïÖʵÄÁ¿ÊÇ6.72L¡Â22.4L/mol£½0.3mol£¬ÔòתÒƵç×ÓµÄÎïÖʵÄÁ¿ÊÇ0.6mol£¬¸öÊýÊÇ0.6NA£»
£¨5£©ÓÉH¡¢O¡¢ClÈýÖÖÔªËØ×é³ÉµÄijÖÖ¿ÉÒÔÏû¶¾É±¾úÎïÖÊÊÇ´ÎÂÈËᣬÆäµç×ÓʽΪ¡£
£¨6£©ÓÉÓÚ°±ÆøºÍÁ×»¯ÇⶼΪ·Ö×Ó¾§Ì壬NH3´æÔÚ·Ö×Ó¼äÇâ¼ü£¬ÔöÇ¿·Ö×Ó¼ä×÷ÓÃÁ¦£¬´Ó¶øµ¼ÖÂÈ۷еã±ÈPH3¸ß
¡¾ÌâÄ¿¡¿º£ÑóÖÐÔ̺¬×ŷḻµÄ×ÊÔ´¡£ÀûÓú£Ë®ÌáÈ¡µË®¡¢äåºÍþµÄ²¿·Ö¹ý³ÌÈçͼËùʾ¡£
£¨1£©º£Ë®µ»¯µÄ·½·¨ÓÐ_________________¡¢Àë×Ó½»»»·¨ºÍµçÉøÎö·¨µÈ¡£
£¨2£©Óô¿¼îÎüÊÕŨËõº£Ë®´µ³öµÄBr2:
3Br2+ 6Na2CO3+3H2O£½ 5NaBr+ NaBrO3+6NaHCO3¡£µ±ÎüÊÕ3 mol Br2ʱ£¬·´Ó¦ÖÐתÒƵĵç×ÓÊýÊÇ_____________¡£
£¨3£©º£Ë®Öв¿·ÖÀë×ӵĺ¬Á¿ÈçÏ£º
³É·Ö | º¬Á¿£¨ mg/L£© | ³É·Ö | º¬Á¿£¨ mg/L£© |
Na+ | 10560 | Cl- | 18980 |
Mg2+ | 1272 | Br- | 64 |
Ca2+ | 400 | SO42- | 2560 |
ÆäÖУ¬Mg2+µÄÎïÖʵÄÁ¿Å¨¶ÈÊÇ____________¡£ÈôÒª´Ó100 LµÄº£Ë®ÖÐÌáȡþ£¬ÀíÂÛÉÏÐèÒª¼ÓÈë³Áµí¼ÁCa£¨OH£©2µÄÖÊÁ¿ÊÇ_______________¡£
£¨4£©ÓÉMg£¨OH£©2ÖƵ¥ÖÊMg£¬ÒÔÏ·½·¨×îºÏÊʵÄÊÇ________________£¨ÌîÐòºÅ£©¡£
A£®Mg£¨OH£©2 MgOMg
B£®Mg£¨OH£©2MgOMg
C£®Mg£¨OH£©2ÎÞË®MgCl2Mg
D£®Mg£¨OH£©2 MgCl2ÈÜÒºMg
¡¾ÌâÄ¿¡¿Ò»¶¨Î¶ÈÏ£¬ÔÚÈÝ»ýΪ2LµÄÃܱÕÈÝÆ÷Öз¢Éú·´Ó¦CO(g)+H2O(g) CO2(g)+H2(g)£¬²¿·ÖÊý¾Ý¼ûÏÂ±í£¨±íÖÐt2>t1£©
·´Ó¦Ê±¼ä£¯min | n(CO)£¯mol | n(H2O)£¯mol | n(CO2)£¯mol | n(H2)£¯mol |
0 | 1.20 | 0.60 | 0 | 0 |
t1 | 0.80 | |||
t2 | 0.20 |
ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ
A. ·´Ó¦ÔÚt1minÄ©µÄËÙÂÊΪv(H2)=0.40£¯t1 mol¡¤L-1¡¤min-1
B. ƽºâʱCOµÄת»¯ÂÊΪ66£®67£¥
C. ¸ÃζÈÏ·´Ó¦µÄƽºâ³£ÊýΪ1
D. ÆäËûÌõ¼þ²»±ä£¬ÈôÆðʼʱ£¬n(CO)=0.60 mol£¬n(H2O)=1.20 mol£¬Ôòƽºâʱn(CO2)=0.20mol