题目内容

已知1g火箭燃料肼（N2H4）气体燃烧生成N2和H2O（g）时，放出16.7kJ的热量，则该反应的热化学方程式正确的是

A．N2H4+O2=N2+2H2O                 △H =－534.4kJ/mol

B．N2H4（g）+O2(g)=N2(g)+2H2O(g)           △H =－534.4kJ/mol

C． N2H4（g）+O2(g)=N2(g)+2H2O(g)         △H = +534.4kJ/mol

D．N2H4（g）+O2(g)= N2(g)+H2O(g)△H =－16.7kJ/mol

 

【答案】

B

【解析】

 

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已知1g火箭燃料肼（N2H4）气体燃烧生成N2和H2O（g）时，放出16.7kJ的热量，则该反应的热化学方程式正确的是（　　）

已知1g火箭燃料肼（N2H4）气体燃烧生成N2和H2O（g）时，放出16.7kJ的热量，则该反应的热化学方程式正确的是(   )

A．N2H4+O2=N2+2H2O                               △H = —534.4kJ/mol

B．N2H4(g)+ O2(g)= N2(g)+2H2O(g)         △H = —16.7kJ/mol

C．N2H4(g)+O2(g)=N2(g)+2H2O(l)           △H = —534.4kJ/mol

D．N2H4(g)+O2(g)=N2(g)+2H2O(g)           △H = —534.4kJ/mol

 

已知1g火箭燃料肼（N2H4）气体燃烧生成N2和H2O（g）时，放出16.7kJ的热量，则该反应的热化学方程式正确的是

A．N2H4+O2=N2+2H2O                           △H = —534.4kJ/mol

B．N2H4(g)+ O2(g)= N2(g)+2H2O(g)         △H = —16.7kJ/mol

C．N2H4(g)+O2(g)=N2(g)+2H2O(l)          △H = —534.4kJ/mol

D．N2H4(g)+O2(g)=N2(g)+2H2O(g)         △H = —534.4kJ/mol

 

已知1g火箭燃料肼（N2H4）气体燃烧生成N2和H2O（g）时，放出16.7kJ的热量，则该反应的热化学方程式正确的是

A．N2H4+O2=N2+2H2O                           △H = —534.4kJ/mol

B．N2H4(g)+ O2(g)= N2(g)+2H2O(g)         △H = —16.7kJ/mol

C．N2H4(g)+O2(g)=N2(g)+2H2O(l)          △H = —534.4kJ/mol

D．N2H4(g)+O2(g)=N2(g)+2H2O(g)         △H = —534.4kJ/mol

 

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