ÌâÄ¿ÄÚÈÝ

£¨12·Ö£¬Ã¿¿Õ2·Ö£©ÏÖÓк¬NaCl¡¢Na2SO4ºÍNaNO3µÄ»ìºÏÎѡÔñÊʵ±µÄÊÔ¼Á½«Æäת»¯ÎªÏàÓ¦µÄ³Áµí»ò¹ÌÌ壬´Ó¶øʵÏÖCl-¡¢SO42-¡¢ºÍNO3-µÄÏ໥·ÖÀë¡£ÏàÓ¦µÄʵÑé¹ý³Ì¿ÉÓÃÏÂͼ±íʾ£º
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
[1]д³öʵÑéÁ÷³ÌÖÐÏÂÁÐÎïÖʵĻ¯Ñ§Ê½
ÊÔ¼ÁX £º            ³ÁµíA£º              ³ÁµíB£º                    
[2]ÉÏÊöʵÑéÁ÷³ÌÖмÓÈë¹ýÁ¿µÄNa2CO3µÄÄ¿µÄÊÇ                _____  ¡£
[3]д³ö¢ÛµÄ»¯Ñ§·½³Ìʽ£º¢Ú________________________________________
[4]°´´ËʵÑé·½°¸µÃµ½µÄÈÜÒº3Öп϶¨º¬ÓР        £¨Ìѧʽ£©ÔÓÖÊ¡£

£¨Ã¿¿Õ¸÷2·Ö£¬¹²12·Ö£©¢ÅBaCl2 [»òBa(NO3)2]    BaSO4    AgCl 
¢Æ³ýÈ¥¹ýÁ¿µÄBa2+¡¢Ag+
[3]NaCl+AgNO3=AgCl+NaNO3  £¨ºÏÀí¼´¿É£©           [4]Na2CO3   

½âÎö

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

£¨12·Ö£¬Ã¿¿Õ2·Ö£©

µ±½ñÊÀ½ç£¬ÄÜÔ´µÄ·¢Õ¹ÈÕÒæ³ÉΪȫÊÀ½ç¡¢È«ÈËÀ๲ͬ¹ØÐĵÄÎÊÌâ¡£

(1)AºÍBµÄµ¥Öʵ¥Î»ÖÊÁ¿µÄȼÉÕÈȴ󣬿ÉÓÃ×÷ȼÁÏ¡£ÒÑÖªAºÍBΪ¶ÌÖÜÆÚÔªËØ£¬ÆäÔ­×ӵĵÚÒ»ÖÁµÚËĵçÀëÄÜÈçϱíËùʾ£º

µçÀëÄÜ(kJ/mol)

I1

I2

I3

I4

A

899

1 757

14 840

21 000

B

738

1 451

7 733

10 540

 

¢ÙÇë¸ù¾ÝÉÏÊöÐÅÏ¢£¬Ð´³öA»ù̬ԭ×ӵĺËÍâµç×ÓÅŲ¼Ê½£º__________________¡£

¢Úijͬѧ¸ù¾ÝÉÏÊöÐÅÏ¢£¬ÍƶÏBµÄºËÍâµç×ÓÅŲ¼Èçͼ1Ëùʾ£¬¸ÃͬѧËù»­µÄµç×ÓÅŲ¼Í¼Î¥±³ÁË______________________¡£

(2)ÇâÆø×÷ΪһÖÖÇå½àÄÜÔ´£¬±ØÐë½â¾öËüµÄ´¢´æÎÊÌ⣬C60¿ÉÓÃ×÷´¢Çâ²ÄÁÏ¡£

¢ÙÒÑÖª½ð¸ÕʯÖÐC¡ªC¼üµÄ¼ü³¤Îª154.45 pm£¬C60ÖÐC¡ªC¼üµÄ¼ü³¤Îª145 pmºÍ140 pm£¬ÓÐͬѧ¾Ý´ËÈÏΪC60µÄÈÛµã¸ßÓÚ½ð¸Õʯ£¬ÄãÈÏΪÊÇ·ñÕýÈ·²¢²ûÊöÀíÓÉ____________________________                          ________________¡£

¢Ú¿Æѧ¼Ò°ÑC60ºÍK²ôÔÓÔÚÒ»ÆðÖÆÔìÁËÒ»ÖÖ¸»ÀÕÏ©»¯ºÏÎÆ侧°ûÈçͼ2Ëùʾ£¬¸ÃÎïÖÊÔÚµÍÎÂʱÊÇÒ»ÖÖ³¬µ¼Ìå¡£¸ÃÎïÖÊÖÐKÔ­×ÓºÍC60·Ö×ӵĸöÊý±ÈΪ______________________¡£

¢Û¼ÌC60ºó£¬¿Æѧ¼ÒÓֺϳÉSi60¡¢N60£¬C¡¢Si¡¢NÔ­×ӵ縺ÐÔÓÉ´óµ½Ð¡µÄ˳ÐòÊÇ__________       ¡£Si60·Ö×ÓÖÐÿ¸ö¹èÔ­×ÓÖ»¸úÏàÁÚµÄ3¸ö¹èÔ­×ÓÐγɹ²¼Û¼ü£¬ÇÒÿ¸ö¹èÔ­×Ó×îÍâ²ã¶¼Âú×ã8µç×ÓÎȶ¨½á¹¹£¬ÔòSi60·Ö×ÓÖЦмüµÄÊýĿΪ______¡£

 

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø