ÌâÄ¿ÄÚÈÝ

ÏÂÁÐÀë×Ó·½³ÌʽÕýÈ·µÄÊÇ(¡¡¡¡)
A£®ÀûÓô×ËáÈܽ⺬̼Ëá¸ÆµÄË®¹¸£ºCaCO3£«2H£«=Ca2£«£«H2O£«CO2¡ü
B£®ÓÃͭΪµç¼«µç½â±¥ºÍʳÑÎË®£º2Cl£­£«2H2OCl2¡ü£«H2¡ü£«2OH£­
C£®ÔÚÃ÷·¯ÈÜÒºÖеμӹýÁ¿°±Ë®£ºAl3£«£«4NH3¡¤H2O=AlO2¡ª£«4NH4+£«2H2O
D£®ÔÚСËÕ´òÈÜÒºÖмÓÉÙÁ¿Ba(OH)2ÈÜÒº£º2HCO3¡ª£«Ba2£«£«2OH£­=BaCO3¡ý£«2H2O£«CO32¡ª
D
¡¡AÏîÖд×ËáӦдΪ»¯Ñ§Ê½£»BÏîÖÐͭΪµç¼«µç½âʱͭ²ÎÓë·´Ó¦£»CÏîÖÐAl(OH)3²»ÄÜÈܽâÔÚ°±Ë®ÖС£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
ʳÑÎÖк¬ÓÐÒ»¶¨Á¿µÄþ¡¢ÌúµÈÔÓÖÊ£¬¼ÓµâÑÎÖеâµÄËðʧÖ÷ÒªÊÇÓÉÓÚÔÓÖÊ¡¢Ë®·Ö¡¢¿ÕÆøÖеÄÑõÆøÒÔ¼°¹âÕÕ¡¢ÊÜÈȶøÒýÆðµÄ¡£ÒÑÖª£º
Ñõ»¯ÐÔ£ºIO3-£¾Fe3£«£¾I2£»»¹Ô­ÐÔ£ºS2O32-£¾I£­
3I2£«6OH£­=5I£­£«IO3-£«3H2O
KI£«I2KI3
(1)ijѧϰС×é¶Ô¼ÓµâÑνøÐÐÁËÈçÏÂʵÑ飺ȡһ¶¨Á¿Ä³¼ÓµâÑÎ(¿ÉÄܺ¬ÓÐKIO3¡¢KI¡¢Mg2£«¡¢Fe3£«)£¬ÓÃÊÊÁ¿ÕôÁóË®Èܽ⣬²¢¼ÓÏ¡ÑÎËáËữ£¬½«ËùµÃÊÔÒº·ÖΪ3·Ý¡£µÚÒ»·ÝÊÔÒºÖеμÓKSCNÈÜÒººóÏÔºìÉ«£»µÚ¶þ·ÝÊÔÒºÖмÓ×ãÁ¿KI¹ÌÌ壬ÈÜÒºÏÔµ­»ÆÉ«£¬ÓÃCCl4ÝÍÈ¡£¬Ï²ãÈÜÒºÏÔ×ϺìÉ«£»µÚÈý·ÝÊÔÒºÖмÓÈëÊÊÁ¿KIO3¹ÌÌåºó£¬µÎ¼Óµí·ÛÊÔ¼Á£¬ÈÜÒº²»±äÉ«¡£
¢Ù¼ÓKSCNÈÜÒºÏÔºìÉ«£¬¸ÃºìÉ«ÎïÖÊÊÇ       (Óû¯Ñ§Ê½±íʾ)£»CCl4ÖÐÏÔ×ϺìÉ«µÄÎïÖÊÊÇ      (Óõç×Óʽ±íʾ)¡£
¢ÚµÚ¶þ·ÝÊÔÒºÖмÓÈë×ãÁ¿KI¹ÌÌåºó£¬·´Ó¦µÄÀë×Ó·½³ÌʽΪ                               ¡¢                         ¡£
(2)KI×÷Ϊ¼Óµâ¼ÁµÄʳÑÎÔÚ±£´æ¹ý³ÌÖУ¬ÓÉÓÚ¿ÕÆøÖÐÑõÆøµÄ×÷Óã¬ÈÝÒ×ÒýÆðµâµÄËðʧ¡£Ð´³ö³±Êª»·¾³ÖÐKIÓëÑõÆø·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º                                          ¡£
½«I2ÈÜÓÚKIÈÜÒº£¬ÔÚµÍÎÂÌõ¼þÏ£¬¿ÉÖƵÃKI3¡¤H2O¡£¸ÃÎïÖÊ×÷ΪʳÑμӵâ¼ÁÊÇ·ñºÏÊÊ£¿       (Ìî¡°ÊÇ¡±»ò¡°·ñ¡±)£¬²¢ËµÃ÷ÀíÓÉ£º               ¡£
(3)ΪÁËÌá¸ß¼ÓµâÑÎ(Ìí¼ÓKI)µÄÎȶ¨ÐÔ£¬¿É¼ÓÎȶ¨¼Á¼õÉÙµâµÄËðʧ¡£ÏÂÁÐÎïÖÊÖÐÓпÉÄÜ×÷ΪÎȶ¨¼ÁµÄÊÇ       ¡£
A£®Na2S2O3B£®AlCl3
C£®Na2CO3D£®NaNO2
(4)¶Ôº¬Fe2£«½Ï¶àµÄʳÑÎ(¼ÙÉè²»º¬Fe3£«)£¬¿ÉÑ¡ÓÃKI×÷Ϊ¼Óµâ¼Á¡£ÇëÉè¼ÆʵÑé·½°¸£¬¼ìÑé¸Ã¼ÓµâÑÎÖеÄFe2£«£º                                                   
¢ñ.Í­Ìú¼°Æ仯ºÏÎïÔÚÈÕ³£Éú»îÖÐÓ¦Óù㷺£¬Ä³Ñо¿ÐÔѧϰС×éÓôÖÍ­£¨º¬ÔÓÖÊFe£©Óë¹ýÁ¿ÂÈÆø·´Ó¦µÃ¹ÌÌåA£¬ÓÃÏ¡ÑÎËáÈܽâA£¬È»ºó¼ÓÊÔ¼Áµ÷½ÚÈÜÒºµÄpHºóµÃÈÜÒºB£¬ÈÜÒºB¾­ÏµÁвÙ×÷¿ÉµÃÂÈ»¯Í­¾§Ì壬Çë»Ø´ð£º
£¨1£©¹ÌÌåAÓÃÏ¡ÑÎËáÈܽâµÄÔ­ÒòÊÇ           __¡£
£¨2£©¼ìÑéÈÜÒºBÖÐÊÇ·ñ´æÔÚFe3£«µÄ·½·¨ÊÇ   __¡£
£¨3£©ÒÑÖªÔªËØÔڸ߼Û̬ʱ³£±íÏÖÑõ»¯ÐÔ£¬ÈôÔÚËáÐÔCuSO4ÈÜÒºÖмÓÈëÒ»¶¨Á¿µÄNa2SO3ºÍNaClÈÜÒº£¬¼ÓÈÈ£¬Éú³ÉCuCl³Áµí£¬ÔòÉú³ÉCuClµÄÀë×Ó·½³ÌʽÊÇ           ¡£
¢ò.³£ÎÂÏ£¬Ä³Í¬Ñ§½«Ï¡ÑÎËáºÍ°±Ë®µÈÌå»ý»ìºÏ£¬Á½ÖÖÈÜÒºµÄŨ¶ÈºÍ»ìºÏºóËùµÃÈÜÒºµÄpHÈçÏÂ±í£º
ʵÑé±àºÅ
°±Ë®ÎïÖʵÄÁ¿Å¨¶È/£¨mol¡¤L£­1£©
ÑÎËáÎïÖʵÄÁ¿Å¨¶È/£¨mol¡¤L£­1£©
»ìºÏÈÜÒºpH
¢Ù
0.1
0.1
pH£½5
¢Ú
c
0.2
pH£½7
¢Û
0.2
0.1
pH>7
 
Çë»Ø´ð£º
£¨4£©´ÓµÚ¢Ù×éÇé¿ö·ÖÎö£¬¸Ã×éËùµÃ»ìºÏÈÜÒºÖÐÓÉË®µçÀë³öµÄc£¨H£«£©£½   __mol¡¤L£­1£»´ÓµÚ¢Ú×éÇé¿ö±íÃ÷£¬c   __£¨Ìî¡°>¡±¡°<¡±»ò¡°£½¡±£©0.2 mol¡¤L£­1£»´ÓµÚ¢Û×éÇé¿ö·ÖÎö¿ÉÖª£¬»ìºÏÈÜÒºÖÐc£¨NH4+£©   __£¨Ìî¡°>¡±¡°<¡±»ò¡°£½¡±£©c£¨NH3¡¤H2O£©¡£
£¨5£©Ð´³öÒÔÏÂËÄ×éÈÜÒºNH4+Ũ¶ÈÓÉ´óµ½Ð¡µÄ˳Ðò   __>   __>   __>   __£¨ÌîÑ¡Ïî±àºÅ£©¡£
A£®0.1 mol¡¤L£­1 NH4Cl
B£®0.1 mol¡¤L£­1 NH4ClºÍ0.1 mol¡¤L£­1 NH3¡¤H2O
C£®0.1 mol¡¤L£­1 NH3¡¤H2O
D£®0.1 mol¡¤L£­1 NH4ClºÍ0.1 mol¡¤L£­1 HCl

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø