ÌâÄ¿ÄÚÈÝ

£¨15·Ö£©Ä³ÐËȤС×éÓû´Ó¹¤ÒµÊ³ÑÎÖо«Á¶¾«ÑΣ¬²¢ÅäÖÆNaClÈÜÒº£¬Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©´ÖÑÎË®¼ÓÈë³Áµí¼ÁA¡¢B³ýÔÓÖÊ£¨³Áµí¼ÁAÀ´Ô´ÓÚʯ»ÒÒ¤³§£©£¬Ð´³öA¡¢BµÄ»¯Ñ§Ê½¡£
A                           B                  
£¨2£©ÊµÑéÊÒÌá´¿´ÖÑεÄʵÑé²Ù×÷ÒÀ´ÎΪ£º
È¡Ñù¡¢       ¡¢³Áµí¡¢       ¡¢       ¡¢ÀäÈ´½á¾§¡¢ºæ¸É¡£
£¨3£©ÊµÑéÊÒÅäÖÆ500 mL 0.1mol/LµÄNaClÈÜÒº£¬¾ßÌå²Ù×÷²½ÖèΪ£º¢ÙÔÚÌìƽÉϳÆÈ¡Ò»¶¨ÖÊÁ¿µÄNaCl£¬°ÑËü·ÅÔÚÉÕ±­ÖУ¬ÓÃÊÊÁ¿µÄÕôÁóˮʹÆäÍêÈ«Èܽ⣻¢Ú°ÑÖƵõÄÈÜҺСÐĵÄ×¢Èë500 mLµÄÈÝÁ¿Æ¿ÖУ»¢Û¼ÌÐøÏòÈÝÁ¿Æ¿ÖеμÓÕôÁóË®ÖÁÒºÃæ¾à¿Ì¶ÈÏß1¡«2 cm´¦Ê±£¬¸ÄÓýºÍ·µÎ¹ÜСÐĵμӣ¬Ö±µ½ÈÜÒºµÄ°¼ÒºÃæÇ¡ºÃÓë¿Ì¶ÈÏßÏàÇÐΪֹ£»¢ÜÓÃÉÙÁ¿ÕôÁóˮϴµÓÉÕ±­ºÍ²£Á§°ô2¡«3´Î£¬Ã¿´ÎµÄÏ´µÓÒº¶¼×ªÈëÈÝÁ¿Æ¿ÖУ¬²¢ÇáÇáÒ¡ÔÈ£»¢Ý½«ÈÝÁ¿Æ¿ÈûºÃ£¬³ä·ÖÒ¡ÔÈ¡£ÊÔÌîдÏÂÁпհס£
¢ÙÓ¦¸Ã³ÆÈ¡µÄNaClµÄÖÊÁ¿Îª________£¬ÉÏÊö²Ù×÷µÄÕýȷ˳ÐòÊÇ____________£»
¢Ú±¾ÊµÑéÓõ½µÄÒÇÆ÷ÓУº²£Á§°ô¡¢_____________________________________________
________________________________________________________________________£¬
¢Û¹Û²ìÈÝÁ¿Æ¿ÖеÄÒºÃæʱ£¬Èô¸©Êӿ̶ÈÏߣ¬»áʹËùÅäµÄÈÜÒºµÄŨ¶È________(Ìî¡°Æ«¸ß¡±¡°Æ«µÍ¡±»ò¡°ÎÞÓ°Ï족£¬ÏÂͬ)£»Ã»ÓнøÐвÙ×÷¢Ü£¬»á________£»

£¨1£©Ca(OH)2»òCaO£»Na2CO3£»£¨Ã¿¿Õ1·Ö£©
£¨2£©Èܽ⣻¹ýÂË£»Õô·¢£»£¨Ã¿¿Õ1·Ö£©     £¨3£©¢Ù2.9 g¡¡ ¢Ù¢Ú¢Ü¢Û¢Ý
¢ÚÍÐÅÌÌìƽ¡¢Ò©³×¡¢ÉÕ±­¡¢500 mLÈÝÁ¿Æ¿¡¢½ºÍ·µÎ¹Ü¡¡¢ÛÆ«¸ß¡¡Æ«µÍ¡¡£¨Ã¿¿Õ1·Ö£©

½âÎö

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
¢ñ£®£¨1£©Ä³»¯Ñ§ÐËȤС×éÓû´ÓÏÂÁÐ×°ÖÃÖÐÑ¡È¡±ØÒªµÄ×°ÖÃÖÆÈ¡£¨NH4£©2SO4ÈÜÒº£¬Á¬½ÓµÄ˳Ðò£¨ÓýӿÚÐòºÅ×Öĸ±íʾ£©ÊÇ£ºa
 
£®
¾«Ó¢¼Ò½ÌÍø
£¨2£©½«×°ÖÃCÖÐÁ½ÖÖÒºÌå·ÖÀ뿪µÄ²Ù×÷Ãû³ÆÊÇ
 
£®×°ÖÃDµÄ×÷ÓÃÊÇ
 
£®
¢ò£®¹ýÑõ»¯¸Æ¿ÉÒÔÓÃÓÚ¸ÄÉƵرíË®ÖÊ¡¢´¦Àíº¬ÖؽðÊôÁ£×Ó·ÏË®ºÍÖÎÀí³à³±£¬Ò²¿ÉÓÃÓÚÓ¦¼±¹©ÑõµÈ£®¹¤ÒµÉÏÉú²ú¹ýÑõ»¯¸ÆµÄÖ÷ÒªÁ÷³ÌÈçÏ£º
¾«Ó¢¼Ò½ÌÍø
ÒÑÖªCaO2?8H2O³Ê°×É«£¬Î¢ÈÜÓÚË®£®I2+2S2O32-=2I-+S4O62-
£¨1£©ÓÃÉÏÊö·½·¨ÖÆÈ¡CaO2?8H2OµÄ»¯Ñ§·½³ÌʽÊÇ
 
£»
£¨2£©¼ìÑ顰ˮϴ¡±ÊÇ·ñºÏ¸ñµÄ·½·¨ÊÇ
 
£»
£¨3£©²â¶¨²úÆ·ÖÐCaO2µÄº¬Á¿µÄʵÑé²½ÖèÊÇ£º
µÚÒ»²½£º×¼È·³ÆÈ¡a g²úÆ·ÓÚ׶ÐÎÆ¿ÖУ¬¼ÓÈëÊÊÁ¿ÕôÁóË®ºÍ¹ýÁ¿µÄb g KI¾§Ì壬ÔÙµÎÈëÉÙÁ¿2mol/LµÄH2SO4ÈÜÒº£¬³ä·Ö·´Ó¦£®
µÚ¶þ²½£ºÏòÉÏÊö׶ÐÎÆ¿ÖмÓÈ뼸µÎµí·ÛÈÜÒº£®
µÚÈý²½£ºÖðµÎ¼ÓÈëŨ¶ÈΪc mol?L-1µÄNa2S2O3ÈÜÒºÖÁ·´Ó¦ÍêÈ«£¬ÏûºÄNa2S2O3ÈÜÒºV mL£®
¢ÙÅжϴ˵ζ¨ÊµÑé´ïµ½ÖÕµãµÄ·½·¨ÊÇ£º
 
£®
¢ÚCaO2µÄÖÊÁ¿·ÖÊýΪ
 
 £¨ÓÃ×Öĸ±íʾ£©£»
¢ÛijͬѧµÚÒ»²½ºÍµÚ¶þ²½µÄ²Ù×÷¶¼ºÜ¹æ·¶£¬µÚÈý²½µÎËÙÌ«Âý£¬ÕâÑù²âµÃµÄCaO2µÄÖÊÁ¿·ÖÊý¿ÉÄÜ
 
£¨Ìî¡°²»ÊÜÓ°Ï족¡¢¡°Æ«µÍ¡±»ò¡°Æ«¸ß¡±£©£®

£¨18·Ö£©Ä³ÐËȤС×éÓû´Ó¹¤ÒµÊ³ÑÎÖо«Á¶¾«ÑΣ¬²¢ÅäÖÆNaClÈÜÒº£¬Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©´ÖÑÎË®¼ÓÈë³Áµí¼ÁA¡¢B³ýÔÓÖÊ£¨³Áµí¼ÁAÀ´Ô´ÓÚʯ»ÒÒ¤³§£©£¬Ð´³öA¡¢BµÄ»¯Ñ§Ê½¡£
A                           B                  
£¨2£©ÊµÑéÊÒÌá´¿´ÖÑεÄʵÑé²Ù×÷ÒÀ´ÎΪ£º
È¡Ñù¡¢       ¡¢³Áµí¡¢¹ýÂË¡¢       ¡¢ÀäÈ´½á¾§¡¢ºæ¸É¡£
£¨3£©ÊµÑéÊÒÅäÖÆ500 mL 0.1mol/LµÄNaClÈÜÒº£¬¾ßÌå²Ù×÷²½ÖèΪ£º¢ÙÔÚÌìƽÉϳÆÈ¡Ò»¶¨ÖÊÁ¿µÄNaCl£¬°ÑËü·ÅÔÚÉÕ±­ÖУ¬ÓÃÊÊÁ¿µÄÕôÁóˮʹÆäÍêÈ«Èܽ⣻¢Ú°ÑÖƵõÄÈÜҺСÐĵÄ×¢Èë500 mLµÄÈÝÁ¿Æ¿ÖУ»¢Û¼ÌÐøÏòÈÝÁ¿Æ¿ÖеμÓÕôÁóË®ÖÁÒºÃæ¾à¿Ì¶ÈÏß1¡«2 cm´¦Ê±£¬¸ÄÓýºÍ·µÎ¹ÜСÐĵμӣ¬Ö±µ½ÈÜÒºµÄ°¼ÒºÃæÇ¡ºÃÓë¿Ì¶ÈÏßÏàÇÐΪֹ£»¢ÜÓÃÉÙÁ¿ÕôÁóˮϴµÓÉÕ±­ºÍ²£Á§°ô2¡«3´Î£¬Ã¿´ÎµÄÏ´µÓÒº¶¼×ªÈëÈÝÁ¿Æ¿ÖУ¬²¢ÇáÇáÒ¡ÔÈ£»¢Ý½«ÈÝÁ¿Æ¿ÈûºÃ£¬³ä·ÖÒ¡ÔÈ¡£ÊÔÌîдÏÂÁпհס£
¢ÙÓ¦¸Ã³ÆÈ¡µÄNaClµÄÖÊÁ¿Îª________£¬ÉÏÊö²Ù×÷µÄÕýȷ˳ÐòÊÇ____________£»
¢Ú±¾ÊµÑéÓõ½µÄÒÇÆ÷³ý²£Á§°ô¡¢ÍÐÅÌÌìƽ¡¢Ò©³×¡¢ÉÕ±­Í⻹ÐèÒªµÄÓÐ___________________¡¢______________________£¬
¢Û¹Û²ìÈÝÁ¿Æ¿ÖеÄÒºÃæʱ£¬Èô¸©Êӿ̶ÈÏߣ¬»áʹËùÅäµÄÈÜÒºµÄŨ¶È________(Ìî¡°Æ«¸ß¡±¡°Æ«µÍ¡±»ò¡°ÎÞÓ°Ï족£¬ÏÂͬ)¡£Ã»ÓнøÐвÙ×÷¢Ü£¬»á________£» 

£¨18·Ö£©Ä³ÐËȤС×éÓû´Ó¹¤ÒµÊ³ÑÎÖо«Á¶¾«ÑΣ¬²¢ÅäÖÆNaClÈÜÒº£¬Çë»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©´ÖÑÎË®¼ÓÈë³Áµí¼ÁA¡¢B³ýÔÓÖÊ£¨³Áµí¼ÁAÀ´Ô´ÓÚʯ»ÒÒ¤³§£©£¬Ð´³öA¡¢BµÄ»¯Ñ§Ê½¡£

A                           B                  

£¨2£©ÊµÑéÊÒÌá´¿´ÖÑεÄʵÑé²Ù×÷ÒÀ´ÎΪ£º

È¡Ñù¡¢        ¡¢³Áµí¡¢¹ýÂË¡¢        ¡¢ÀäÈ´½á¾§¡¢ºæ¸É¡£

£¨3£©ÊµÑéÊÒÅäÖÆ500 mL 0.1mol/LµÄNaClÈÜÒº£¬¾ßÌå²Ù×÷²½ÖèΪ£º¢ÙÔÚÌìƽÉϳÆÈ¡Ò»¶¨ÖÊÁ¿µÄNaCl£¬°ÑËü·ÅÔÚÉÕ±­ÖУ¬ÓÃÊÊÁ¿µÄÕôÁóˮʹÆäÍêÈ«Èܽ⣻¢Ú°ÑÖƵõÄÈÜҺСÐĵÄ×¢Èë500 mLµÄÈÝÁ¿Æ¿ÖУ»¢Û¼ÌÐøÏòÈÝÁ¿Æ¿ÖеμÓÕôÁóË®ÖÁÒºÃæ¾à¿Ì¶ÈÏß1¡«2 cm´¦Ê±£¬¸ÄÓýºÍ·µÎ¹ÜСÐĵμӣ¬Ö±µ½ÈÜÒºµÄ°¼ÒºÃæÇ¡ºÃÓë¿Ì¶ÈÏßÏàÇÐΪֹ£»¢ÜÓÃÉÙÁ¿ÕôÁóˮϴµÓÉÕ±­ºÍ²£Á§°ô2¡«3´Î£¬Ã¿´ÎµÄÏ´µÓÒº¶¼×ªÈëÈÝÁ¿Æ¿ÖУ¬²¢ÇáÇáÒ¡ÔÈ£»¢Ý½«ÈÝÁ¿Æ¿ÈûºÃ£¬³ä·ÖÒ¡ÔÈ¡£ÊÔÌîдÏÂÁпհס£

¢ÙÓ¦¸Ã³ÆÈ¡µÄNaClµÄÖÊÁ¿Îª________£¬ÉÏÊö²Ù×÷µÄÕýȷ˳ÐòÊÇ____________£»

¢Ú±¾ÊµÑéÓõ½µÄÒÇÆ÷³ý²£Á§°ô¡¢ÍÐÅÌÌìƽ¡¢Ò©³×¡¢ÉÕ±­Í⻹ÐèÒªµÄÓÐ___________________¡¢______________________£¬

¢Û ¹Û²ìÈÝÁ¿Æ¿ÖеÄÒºÃæʱ£¬Èô¸©Êӿ̶ÈÏߣ¬»áʹËùÅäµÄÈÜÒºµÄŨ¶È________(Ìî¡°Æ«¸ß¡±¡°Æ«µÍ¡±»ò¡°ÎÞÓ°Ï족£¬ÏÂͬ)¡£Ã»ÓнøÐвÙ×÷¢Ü£¬»á________£» 

 

£¨15·Ö£©Ä³ÐËȤС×éÓû´Ó¹¤ÒµÊ³ÑÎÖо«Á¶¾«ÑΣ¬²¢ÅäÖÆNaClÈÜÒº£¬Çë»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©´ÖÑÎË®¼ÓÈë³Áµí¼ÁA¡¢B³ýÔÓÖÊ£¨³Áµí¼ÁAÀ´Ô´ÓÚʯ»ÒÒ¤³§£©£¬Ð´³öA¡¢BµÄ»¯Ñ§Ê½¡£

A                           B                  

£¨2£©ÊµÑéÊÒÌá´¿´ÖÑεÄʵÑé²Ù×÷ÒÀ´ÎΪ£º

È¡Ñù¡¢        ¡¢³Áµí¡¢        ¡¢        ¡¢ÀäÈ´½á¾§¡¢ºæ¸É¡£

£¨3£©ÊµÑéÊÒÅäÖÆ500 mL 0.1mol/LµÄNaClÈÜÒº£¬¾ßÌå²Ù×÷²½ÖèΪ£º¢ÙÔÚÌìƽÉϳÆÈ¡Ò»¶¨ÖÊÁ¿µÄNaCl£¬°ÑËü·ÅÔÚÉÕ±­ÖУ¬ÓÃÊÊÁ¿µÄÕôÁóˮʹÆäÍêÈ«Èܽ⣻¢Ú°ÑÖƵõÄÈÜҺСÐĵÄ×¢Èë500 mLµÄÈÝÁ¿Æ¿ÖУ»¢Û¼ÌÐøÏòÈÝÁ¿Æ¿ÖеμÓÕôÁóË®ÖÁÒºÃæ¾à¿Ì¶ÈÏß1¡«2 cm´¦Ê±£¬¸ÄÓýºÍ·µÎ¹ÜСÐĵμӣ¬Ö±µ½ÈÜÒºµÄ°¼ÒºÃæÇ¡ºÃÓë¿Ì¶ÈÏßÏàÇÐΪֹ£»¢ÜÓÃÉÙÁ¿ÕôÁóˮϴµÓÉÕ±­ºÍ²£Á§°ô2¡«3´Î£¬Ã¿´ÎµÄÏ´µÓÒº¶¼×ªÈëÈÝÁ¿Æ¿ÖУ¬²¢ÇáÇáÒ¡ÔÈ£»¢Ý½«ÈÝÁ¿Æ¿ÈûºÃ£¬³ä·ÖÒ¡ÔÈ¡£ÊÔÌîдÏÂÁпհס£

¢ÙÓ¦¸Ã³ÆÈ¡µÄNaClµÄÖÊÁ¿Îª________£¬ÉÏÊö²Ù×÷µÄÕýȷ˳ÐòÊÇ____________£»

¢Ú±¾ÊµÑéÓõ½µÄÒÇÆ÷ÓУº²£Á§°ô¡¢_____________________________________________

________________________________________________________________________£¬

¢Û ¹Û²ìÈÝÁ¿Æ¿ÖеÄÒºÃæʱ£¬Èô¸©Êӿ̶ÈÏߣ¬»áʹËùÅäµÄÈÜÒºµÄŨ¶È________(Ìî¡°Æ«¸ß¡±¡°Æ«µÍ¡±»ò¡°ÎÞÓ°Ï족£¬ÏÂͬ)£»Ã»ÓнøÐвÙ×÷¢Ü£¬»á________£»

 

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø