ÌâÄ¿ÄÚÈÝ

ÒÑÖª2H2(g)+O2(g)¡ú2H2O(g)+483£®6kJ¡£ÏÂÁÐ˵·¨»ò±í´ïÕýÈ·µÄÊÇ

A£®ÔÚÏàͬµÄÌõ¼þÏ£¬2mol ÇâÆøÓë 1 mol ÑõÆøµÄ×ÜÄÜÁ¿Ð¡ÓÚ2mol Ë®ÕôÆøµÄ×ÜÄÜÁ¿
B£®H2(g)+1/2 O2(g)¡úH2O(1)+Q1£»Q1£¾241£®8kJ
C£®H2(g)+ 1/2O2(g)¡úH2O(1)+Q2£»Q2£¼241£®8kJ
D£®ÈκÎÌõ¼þÏ£¬2LË®ÕôÆø·Ö½â³É2LÇâÆøÓë1LÑõÆøÐèÎüÊÕ483£®6kJÈÈÁ¿

B

½âÎöÊÔÌâ·ÖÎö£ºA¡¢¸Ã·´Ó¦Îª·ÅÈÈ·´Ó¦£¬ÔÚÏàͬµÄÌõ¼þÏ£¬2mol ÇâÆøÓë 1 mol ÑõÆøµÄ×ÜÄÜÁ¿´óÓÚ2mol Ë®ÕôÆøµÄ×ÜÄÜÁ¿£¬´íÎó£»Æø̬ˮ±äΪҺ̬ˮ·Å³öÈÈÁ¿£¬¹ÊBÏîÕýÈ·£¬CÏî´íÎó£»D¡¢Ñ¹Ç¿ºÍζȸı䣬»¯Ñ§·´Ó¦µÄÈÈЧӦ¿ÉÄܸı䣬DÏî´íÎó¡£
¿¼µã£º±¾Ì⿼²é»¯Ñ§·´Ó¦µÄÈÈЧӦ¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø