ÌâÄ¿ÄÚÈÝ

(11·Ö)ǦÐîµç³ØÊǵäÐ͵ĿɳäÐ͵ç³Ø£¬ËüµÄÕý¸º¼«¸ô°åÊǶèÐÔ²ÄÁÏ£¬µç³Ø×Ü·´Ó¦Ê½Îª£º
Pb+PbO2+4H++22PbSO4+2H2O
ÇëÍê³ÉÏÂÁÐÎÊÌ⣨²»¿¼ÂÇÇâ¡¢ÑõµÄÑõ»¯»¹Ô­£©:
(1)·Åµçʱ£ºÕý¼«µÄµç¼«·´Ó¦Ê½ÊÇ__________________;µç½âÒºÖÐH2SO4µÄŨ¶È½«±ä__________________;µ±Íâµç·ͨ¹ý1 molµç×Óʱ£¬ÀíÂÛÉϸº¼«°åµÄÖÊÁ¿Ôö¼Ó_________________g¡£
(2)ÔÚÍêÈ«·ÅµçºÄ¾¡PbO2ºÍPbʱ£¬Èô°´ÏÂͼÁ¬½Ó£¬µç½âÒ»¶Îʱ¼äºó£¬ÔòÔÚAµç¼«ÉÏÉú³É_________________¡¢Bµç¼«ÉÏÉú³É_________________,´ËʱǦÐîµç³ØµÄÕý¸º¼«µÄ¼«ÐÔ½«_________________¡£
£¨1£©PbO2+2e-+4H++2====PbSO4+2H2O Ð¡  48
£¨2£©Pb   PbO2 ¶Ô»»
±¾Ì⿼²éÔ­µç³ØºÍµç½â³ØµÄÔ­Àí£¬Ð´³öµç¼«·´Ó¦Ê½£¬¸ù¾ÝתÒƵĵçÁ¿Çó³öÔö¼ÓµÄÖÊÁ¿¡£¸ù¾Ý·ÅµçºÍ³äµçÊÇ¿ÉÄæµÄ¹ý³Ì¿ÉÅжϣ¨2£©ÖеÄÕý¸º¼«¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø