ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿Çë²Î¿¼ÌâÖÐͼ±í£¬ÒÑÖªE1£½134 kJ¡¤mol£1¡¢E2£½368 kJ¡¤mol£1£¬¸ù¾ÝÒªÇó»Ø´ðÏÂÁÐÎÊÌ⣺
(1)ͼ¢ñÊÇ1 mol NO2(g)ºÍ1 mol CO(g)·´Ó¦Éú³ÉCO2ºÍNO¹ý³ÌÖеÄÄÜÁ¿±ä»¯Ê¾Òâͼ£¬ÈôÔÚ·´Ó¦ÌåϵÖмÓÈë´ß»¯¼Á£¬·´Ó¦ËÙÂÊÔö´ó£¬E1µÄ±ä»¯ÊÇ________(Ìî¡°Ôö´ó¡±¡°¼õС¡±»ò¡°²»±ä¡±£¬ÏÂͬ)£¬¦¤HµÄ±ä»¯ÊÇ__________________________¡£
Çëд³öNO2ºÍCO·´Ó¦µÄÈÈ»¯Ñ§·½³Ìʽ£º______________________________¡£
(2)¼×´¼ÖÊ×Ó½»»»Ä¤È¼Áϵç³ØÖн«¼×´¼ÕôÆûת»¯ÎªÇâÆøµÄÁ½ÖÖ·´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽÈçÏ£º
¢ÙCH3OH(g)£«H2O(g)===CO2(g)£«3H2(g)
¦¤H£½£«49.0 kJ¡¤mol£1
¢ÚCH3OH(g)£«O2(g)===CO2(g)£«2H2(g)
¦¤H£½£192.9 kJ¡¤mol£1
ÓÖÖª¢ÛH2O(g)===H2O(l) ¦¤H£½£44 kJ¡¤mol£1£¬Ôò¼×´¼ÕôÆûȼÉÕΪҺ̬ˮµÄÈÈ»¯Ñ§·½³ÌʽΪ______________________________¡£
(3)ϱíËùʾÊDz¿·Ö»¯Ñ§¼üµÄ¼üÄܲÎÊý£º
»¯Ñ§¼ü | P¡ªP | P¡ªO | O===O | P===O |
¼üÄÜ/(kJ¡¤mol£1) | a | b | c | x |
ÒÑÖª°×Á×µÄȼÉÕÈÈΪd kJ¡¤mol£1£¬°×Á×¼°ÆäÍêȫȼÉյIJúÎïµÄ½á¹¹Èçͼ¢òËùʾ£¬Ôò±íÖÐx£½________kJ¡¤mol£1(Óú¬a¡¢b¡¢c¡¢dµÄ´úÊýʽ±íʾ)¡£
¡¾´ð°¸¡¿(1)¼õС ²»±ä NO2(g)£«CO(g)===CO2(g)£«NO(g) ¦¤H£½£234 kJ¡¤mol£1
(2)CH3OH(g)£«O2(g)===CO2(g)£«2H2O(l) ¦¤H£½£764.7 kJ¡¤mol£1
(3) (d£«6a£«5c£12b)
¡¾½âÎö¡¿(1)¹Û²ìͼÏñ£¬E1ӦΪ·´Ó¦µÄ»î»¯ÄÜ£¬¼ÓÈë´ß»¯¼Á·´Ó¦µÄ»î»¯ÄܽµµÍ£¬µ«ÊǦ¤H²»±ä£»1 mol NO2(g)ºÍ1 mol CO(g)·´Ó¦Éú³ÉCO2ºÍNOµÄ·´Ó¦ÈÈÊýÖµ¼´·´Ó¦ÎïºÍÉú³ÉÎïµÄÄÜÁ¿²î£¬Òò´Ë¸Ã·´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽΪNO2(g)£«CO(g)===CO2(g)£«NO(g)
¦¤H£½£234 kJ¡¤mol£1¡£
(2)¹Û²ì·½³Ìʽ£¬ÀûÓøÇ˹¶¨ÂÉ£¬½«Ëù¸øÈÈ»¯Ñ§·½³Ìʽ×öÈçÏÂÔËË㣺¢Ú¡Á3£¢Ù¡Á2£«¢Û¡Á2£¬¼´¿ÉÇó³ö¼×´¼ÕôÆûȼÉÕµÄÈÈ»¯Ñ§·½³Ìʽ¡£
(3)°×Á×ȼÉյĻ¯Ñ§·½³ÌʽΪP4£«5O2P4O10£¬½áºÏͼ¢òÖа×Á×¼°ÆäÍêȫȼÉÕ²úÎïµÄ½á¹¹£¬¸ù¾Ý¡°·´Ó¦ÈÈ£½·´Ó¦Îï¼üÄÜ×ܺͣÉú³ÉÎï¼üÄÜ×ܺ͡±ÓëȼÉÕÈȸÅÄî¿ÉµÃµÈʽ£º6a£«5c£(4x£«12b)£½£d£¬¾Ý´Ë¿ÉµÃx£½ (d£«6a£«5c£12b)¡£