ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿Ð¿ÊÇÈËÌå±ØÐèµÄ΢Á¿ÔªËØ£¬[Zn(NH3)4]CO3ÔÚÉúÎï»îÐԵȷ½Ãæ·¢»ÓÖØÒªµÄ×÷Óá£
£¨1£©Zn2+»ù̬ºËÍâµç×ÓÅŲ¼Ê½Îª__¡£
£¨2£©CO32-µÄ¿Õ¼ä¹¹ÐÍΪ__(ÓÃÎÄ×ÖÃèÊö)£»[Zn(NH3)4]CO3ÖÐC¡¢H¡¢O¡¢NËÄÖÖÔªËصĵ縺ÐÔÓÉСµ½´óµÄ˳ÐòΪ__¡£
£¨3£©Ä³º¬Ð¿ÅäºÏÎï¿ÉÓÃÓÚÄ£Äâ̼ËáôûøµÄ´ß»¯»îÐÔ£¬¸ÃÅäºÏÎïÖк¬ÓÐDMF·Ö×Ó¡£DMF·Ö×ӵĽṹÈçͼ1Ëùʾ¡£DMF·Ö×ÓÖÐ̼Ô×Ó¹ìµÀµÄÔÓ»¯ÀàÐÍÊÇ__£¬1molDMF·Ö×ÓÖк¬ÓЦҼüµÄÊýĿΪ__¡£
£¨4£©ÉÁп¿ó¿É¿´×÷ÓÉZn2+ºÍS2-¸÷×ÔÐγɵÄÃæÐÄÁ¢·½½á¹¹Ï໥´©²å¶ø³É¡£Æ侧°û½á¹¹Ê¾ÒâͼÈçͼ2Ëùʾ£¬ÓëZn2+¾àÀëÏàµÈÇÒ×î½üµÄZn2+ÓÐ__¸ö¡£
¡¾´ð°¸¡¿[Ar]3d10»ò1s22s22p63s23p63d10 ƽÃæÕýÈý½ÇÐÎ H<C<N<O sp2¡¢sp3 11mol»ò11¡Á6.02¡Á1023 12
¡¾½âÎö¡¿
£¨1£©ZnÊǵÚ30ºÅÔ×Ó£¬Zn2+µÄ»ù̬ºËÍâµç×ÓÅŲ¼Ê½Îª[Ar]3d10»ò1s22s22p63s23p63d10£»
£¨2£©CO32-µÄ¼Û²ãµç×Ó¶ÔÊýΪ£¬ËùÒԿռ乹ÐÍÊÇƽÃæÈý½ÇÐΣ»Í¬ÖÜÆÚÔªËØ´Ó×óµ½ÓÒÔªËصĵ縺ÐÔÖð½¥Ôö´ó£¬ÔòÓе縺ÐÔC<N<O£¬HµÄµç¸ºÐÔ×îС£¬µç¸ºÐÔ˳ÐòΪ£ºH<C<N<O£»
£¨3£©DMFÖУ¬£¬1ºÅλÖõÄCÓÐË«¼ü£¬ÊÇsp2ÔÓ»¯£¬2¡¢3ºÅλÖõÄC¶¼Êǵ¥¼ü£¬ÊÇsp3ÔÓ»¯£»µ¥¼ü¶¼ÊǦҼü£¬Ë«¼üÀïÒ»Ìõ¦Ò¼üÒ»Ìõ¦Ð¼ü£¬ËùÒÔDMF¹²ÓÐ11NAµÄ¦Ò¼ü£»
£¨4£©ÓÉZnSµÄ¾§°û½á¹¹¿ÉÒÔ¿´³ö£¬ZnSÊÇÃæÐÄÁ¢·½×îÃܶѻý£¬ËùÒÔÓëZn2+¾àÀëÏàµÈÇÒ×î½üµÄZn2+ÓÐ12¸ö£»