ÌâÄ¿ÄÚÈÝ
¶ÔÓÚÈõËᣬÔÚÒ»¶¨Î¶ÈÏ´ﵽµçÀëƽºâʱ£¬¸÷΢Á£µÄŨ¶È´æÔÚÒ»ÖÖ¶¨Á¿µÄ¹Øϵ¡£Èô25¡æʱÓÐHAH++A¨D£¬ÔòK==ʽÖУºKΪµçÀëƽºâ³£Êý£¬Ö»ÓëζÈÓйأ¬cΪ¸÷΢Á£µÄƽºâŨ¶È¡£Ï±íÊǼ¸ÖÖ³£¼ûÈõËáµÄµçÀëƽºâ³£Êý£¨25¡æ£©¡£
Ëá | µçÀë·½³Ìʽ | µçÀëƽºâ³£ÊýK |
CH3COOH | CH3COOHCH3COO¨D+H+ | 1£®76¡Á10¨D5 |
H2CO3 | H2CO3H++HCO3¨D HCO3¨DH++CO32¨D | K1==4£®31¡Á10¨D7 K2==5£®61¡Á10¨D11 |
H2S | H2SH++HS¨D HS¨DH++S2¨D | K1==9£®1¡Á10¨D8
K2==1£®1¡Á10¨D12 |
H3PO4 | H3PO4H++H2PO4¨D H2PO4¨DH++HPO42¨D HPO42¨DH++PO43¨D |
K1==7£®52¡Á10¨D3 K2==6£®23¡Á10¨D8 K3==2£®20¡Á10¨D13 |
»Ø´ðÏÂÁи÷Ì⣺
£¨1£©KÖ»ÓëζÈÓйأ¬µ±Î¶ÈÉý¸ßʱ£¬KÖµ__________£¨Ìî¡°Ôö´ó¡±¡¢¡°¼õС¡±¡¢¡°²»±ä¡±£©¡£
£¨2£©ÔÚζÈÏàͬʱ£¬¸÷ÈõËáµÄKÖµ²»Í¬£¬ÄÇôKÖµµÄ´óСÓëËáÐÔµÄÏà¶ÔÇ¿ÈõÓкιØϵ?___
__________________________¡£
£¨3£©Èô°ÑCH3COOH¡¢H2CO3¡¢HCO3-¡¢H2S¡¢HS-¡¢H3PO4¡¢H2PO4-¡¢HPO42-¶¼¿´×÷ÊÇËᣬÆäÖÐËáÐÔ×îÇ¿µÄÊÇ__________£¬×îÈõµÄÊÇ_____________¡£
£¨4£©¶àÔªÈõËáÊÇ·Ö²½µçÀëµÄ£¬Ã¿Ò»²½¶¼ÓÐÏàÓ¦µÄµçÀëƽºâ³£Êý£¬¶ÔÓÚͬһÖÖ¶àÔªÈõËáµÄK1¡¢K2¡¢K3Ö®¼ä´æÔÚ×ÅÊýÁ¿ÉϵĹæÂÉ£¬´Ë¹æÂÉÊÇ________________£¬²úÉú´Ë¹æÂɵÄÔÒòÊÇ_______
____________________________¡£
£¨1£©Ôö´ó
£¨2£©KÖµÔ½´ó£¬µçÀë³öµÄÇâÀë×ÓŨ¶ÈÔ½´ó£¬ËùÒÔËáÐÔԽǿ
£¨3£©H3PO4 HPO42¨D
£¨4£©K1£ºK2£ºK3¡Ö1£º10¨D5£º10¨D10 £¨»ò´ð K1£¾£¾K2£¾£¾K3£¬»òÕß´ðK1Ô¶´óÓÚK2Ô¶´óÓÚ K3£©ÉÏÒ»¼¶µçÀë²úÉúµÄH+¶ÔÏÂÒ»¼¶µçÀëÓÐÒÖÖÆ×÷ÓÃ
¶ÔÓÚÈõËᣬÔÚÒ»¶¨Î¶ÈÏ´ﵽµçÀëƽºâʱ£¬¸÷΢Á£µÄŨ¶È´æÔÚÒ»ÖÖ¶¨Á¿µÄ¹Øϵ£®Ï±íÊÇ25¡æʱ¼¸ÖÖ³£¼ûÈõËáµÄµçÀëƽºâ³£Êý
Ëá | µçÀë·½³Ìʽ | µçÀëƽºâ³£ÊýK |
¶ÔÓÚÈõËᣬÔÚÒ»¶¨Î¶ÈÏ´ﵽµçÀëƽºâʱ£¬¸÷΢Á£µÄŨ¶È´æÔÚÒ»ÖÖ¶¨Á¿µÄ¹Øϵ£®Ï±íÊÇ25¡æʱ¼¸ÖÖ³£¼ûÈõËáµÄµçÀëƽºâ³£Êý
Ëá | µçÀë·½³Ìʽ | µçÀëƽºâ³£ÊýK |
»Ø´ðÏÂÁи÷ÎÊ£º
£¨1£©KÖ»ÓëζÈÓйأ¬µ±Î¶ÈÉý¸ßʱ£¬KÖµ________£¨Ìî¡°Ôö´ó¡±¡¢¡°¼õС¡±¡¢¡°²»±ä¡±£©£®
£¨2£©ÔÚζÈÏàͬʱ£¬¸÷ÈõËáµÄKÖµ²»Í¬£¬ÄÇôKÖµµÄ´óСÓëËáÐÔµÄÏà¶ÔÇ¿ÈõÓкιØϵ?__________________£®
£¨3£©Èô°ÑCH3COOH¡¢H2CO3¡¢HCO3-¡¢H2S¡¢HS-¡¢H3PO4¡¢H2PO4-¡¢HPO42-¶¼¿´×÷ÊÇËᣬÆäÖÐËáÐÔ×îÇ¿µÄÊÇ_________£¬×îÈõµÄÊÇ________£®
£¨4£©¶àÔªÈõËáÊÇ·Ö²½µçÀëµÄ£¬Ã¿Ò»²½¶¼ÓÐÏàÓ¦µÄµçÀëƽºâ³£Êý£®¶ÔÓÚͬһÖÖ¶àÔªÈõËáµÄK1¡¢K2¡¢K3Ö®¼ä´æÔÚ×ÅÊýÁ¿ÉϵĹæÂÉ£¬¶ÔÓÚH3PO4´Ë¹æÂÉÊÇ________________£¬²úÉú´Ë¹æÂɵÄÔÒòÊÇ_________________________£®
£¨5£©µçÀëƽºâ³£ÊýÊÇÓÃʵÑéµÄ·½·¨²â¶¨³öÀ´µÄ£®ÏÖÒѾ²âµÃijζÈÏ NH3∙H2OÈÜÒºÖдæÔÚÈçÏ·´Ó¦£ºNH3∙H2O NH4++OH- ÒÑÖª0.10 mol¡¤L-1NH3∙H2OÈÜÒºÖУ¬´ïµ½Æ½ºâʱ£¬Cƽºâ£¨OH-£©=4.2 ¡Á 10-3mol¡¤L-1£¬Cƽºâ£¨NH3∙H2O£©¡ÖCÆðʼ£¨NH3∙H2O£©£¬Ë®µÄµçÀë¿ÉºöÂÔ²»¼Æ;
¢ÙÓÃpHÊÔÖ½²âÁ¿ÈÜÒºµÄpHÖµ£¬¼´¿ÉÇóµÃCƽºâ£¨OH-£©£¬²â¶¨ÈÜÒºpHÖµµÄ²Ù×÷ÊÇ______________¡£
¢Ú²âÁ¿Cƽºâ£¨NH3∙H2O£©µÄ·½·¨×îºÃÓÃ_____________·¨£¨Ìî·½·¨Ãû³Æ£©
¢ÛÇó´ËζÈϸ÷´Ó¦µÄƽºâ³£ÊýK.(д³ö¼ÆËã¹ý³Ì£¬¼ÆËã½á¹û±£Áô2λÓÐЧÊý×Ö)
¶ÔÓÚÈõËᣬÔÚÒ»¶¨Î¶ÈÏ´ﵽµçÀëƽºâʱ£¬¸÷΢Á£µÄŨ¶È´æÔÚÒ»ÖÖ¶¨Á¿µÄ¹Øϵ£®Ï±íÊÇ25¡æʱ¼¸ÖÖ³£¼ûÈõËáµÄµçÀëƽºâ³£Êý
Ëá |
µçÀë·½³Ìʽ |
µçÀëƽºâ³£ÊýK |
»Ø´ðÏÂÁи÷ÎÊ£º
£¨1£©KÖ»ÓëζÈÓйأ¬µ±Î¶ÈÉý¸ßʱ£¬KÖµ________£¨Ìî¡°Ôö´ó¡±¡¢¡°¼õС¡±¡¢¡°²»±ä¡±£©£®
£¨2£©ÔÚζÈÏàͬʱ£¬¸÷ÈõËáµÄKÖµ²»Í¬£¬ÄÇôKÖµµÄ´óСÓëËáÐÔµÄÏà¶ÔÇ¿ÈõÓкιØϵ?__________________£®
£¨3£©Èô°ÑCH3COOH¡¢H2CO3¡¢HCO3-¡¢H2S¡¢HS-¡¢H3PO4¡¢H2PO4-¡¢HPO42-¶¼¿´×÷ÊÇËᣬÆäÖÐËáÐÔ×îÇ¿µÄÊÇ_________£¬×îÈõµÄÊÇ________£®
£¨4£©¶àÔªÈõËáÊÇ·Ö²½µçÀëµÄ£¬Ã¿Ò»²½¶¼ÓÐÏàÓ¦µÄµçÀëƽºâ³£Êý£®¶ÔÓÚͬһÖÖ¶àÔªÈõËáµÄK1¡¢K2¡¢K3Ö®¼ä´æÔÚ×ÅÊýÁ¿ÉϵĹæÂÉ£¬¶ÔÓÚH3PO4´Ë¹æÂÉÊÇ________________£¬²úÉú´Ë¹æÂɵÄÔÒòÊÇ_________________________£®
£¨5£©µçÀëƽºâ³£ÊýÊÇÓÃʵÑéµÄ·½·¨²â¶¨³öÀ´µÄ£®ÏÖÒѾ²âµÃijζÈÏ NH3∙H2OÈÜÒºÖдæÔÚÈçÏ·´Ó¦£ºNH3∙H2O NH4++OH- ÒÑÖª0.10 mol¡¤L-1 NH3∙H2OÈÜÒºÖУ¬´ïµ½Æ½ºâʱ£¬Cƽºâ£¨OH-£©=4.2 ¡Á 10-3mol¡¤L-1£¬Cƽºâ£¨NH3∙H2O£©¡ÖCÆðʼ£¨NH3∙H2O£©£¬Ë®µÄµçÀë¿ÉºöÂÔ²»¼Æ;
¢ÙÓÃpHÊÔÖ½²âÁ¿ÈÜÒºµÄpHÖµ£¬¼´¿ÉÇóµÃCƽºâ£¨OH-£©£¬²â¶¨ÈÜÒºpHÖµµÄ²Ù×÷ÊÇ______________¡£
¢Ú²âÁ¿Cƽºâ£¨NH3∙H2O£©µÄ·½·¨×îºÃÓÃ_____________·¨£¨Ìî·½·¨Ãû³Æ£©
¢ÛÇó´ËζÈϸ÷´Ó¦µÄƽºâ³£ÊýK.(д³ö¼ÆËã¹ý³Ì£¬¼ÆËã½á¹û±£Áô2λÓÐЧÊý×Ö)