ÌâÄ¿ÄÚÈÝ
£¨14·Ö£©¶ÌÖÜÆÚÔªËØQ¡¢R¡¢T¡¢WÔÚÔªËØÖÜÆÚ±íÖеÄλÖÃÈçͼËùʾ£¬ÆäÖÐTËù
´¦µÄÖÜÆÚÐòÊýÓëÖ÷×åÐòÊýÏàµÈ£¬Çë»Ø´ðÏÂÁÐÎÊÌ⣺
(1)TÔªËصÄÀë×ӽṹʾÒâͼΪ__________¡£
(2)ÔªËصķǽðÊôÐÔ(Ô×ӵõç×ÓµÄÄÜÁ¦)£ºQ ________W(Ìî¡°Ç¿ÓÚ¡±»ò¡°ÈõÓÚ¡±)¡£
(3)WµÄµ¥ÖÊÓëÆä×î¸ß¼ÛÑõ»¯ÎïµÄË®»¯ÎïŨÈÜÒº¹²ÈÈÄÜ·¢Éú·´Ó¦£¬Éú³ÉÁ½ÖÖÎïÖÊ£¬ÆäÖÐÒ»ÖÖÊÇÆøÌ壬¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ_________________________________________
(4)Ô×ÓÐòÊý±ÈR¶à1µÄÔªËصÄÒ»ÖÖÇ⻯ÎïÄÜ·Ö½âΪËüµÄÁíÒ»ÖÖÇ⻯Î´Ë·Ö½â·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ_________________________________________________________Æä·´Ó¦ÎïµÄµç×ÓʽΪ ¡£Àë×Ӱ뾶T3+__________R3-£¨Ìî¡°£¾¡±¡¢¡°£¼¡±¡¢¡°£½¡±£©
(5)RÓжàÖÖÑõ»¯ÎÆäÖм׵ÄÏà¶Ô·Ö×ÓÖÊÁ¿×îС¡£ÔÚÒ»¶¨Ìõ¼þÏ£¬2 LµÄ¼×ÆøÌåÓë0.5 LµÄÑõÆøÏà»ìºÏ£¬Èô¸Ã»ìºÏÆøÌå±»×ãÁ¿µÄNaOHÈÜÒºÍêÈ«ÎüÊÕºóûÓÐÆøÌå²ÐÁô£¬ËùÉú³ÉµÄRµÄº¬ÑõËáÑÎÖ»ÓÐÒ»ÖÖ£¬Ôò¸Ãº¬ÑõËáÑεĻ¯Ñ§Ê½ÊÇ____________¡£
´¦µÄÖÜÆÚÐòÊýÓëÖ÷×åÐòÊýÏàµÈ£¬Çë»Ø´ðÏÂÁÐÎÊÌ⣺
(1)TÔªËصÄÀë×ӽṹʾÒâͼΪ__________¡£
(2)ÔªËصķǽðÊôÐÔ(Ô×ӵõç×ÓµÄÄÜÁ¦)£ºQ ________W(Ìî¡°Ç¿ÓÚ¡±»ò¡°ÈõÓÚ¡±)¡£
(3)WµÄµ¥ÖÊÓëÆä×î¸ß¼ÛÑõ»¯ÎïµÄË®»¯ÎïŨÈÜÒº¹²ÈÈÄÜ·¢Éú·´Ó¦£¬Éú³ÉÁ½ÖÖÎïÖÊ£¬ÆäÖÐÒ»ÖÖÊÇÆøÌ壬¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ_________________________________________
(4)Ô×ÓÐòÊý±ÈR¶à1µÄÔªËصÄÒ»ÖÖÇ⻯ÎïÄÜ·Ö½âΪËüµÄÁíÒ»ÖÖÇ⻯Î´Ë·Ö½â·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ_________________________________________________________Æä·´Ó¦ÎïµÄµç×ÓʽΪ ¡£Àë×Ӱ뾶T3+__________R3-£¨Ìî¡°£¾¡±¡¢¡°£¼¡±¡¢¡°£½¡±£©
(5)RÓжàÖÖÑõ»¯ÎÆäÖм׵ÄÏà¶Ô·Ö×ÓÖÊÁ¿×îС¡£ÔÚÒ»¶¨Ìõ¼þÏ£¬2 LµÄ¼×ÆøÌåÓë0.5 LµÄÑõÆøÏà»ìºÏ£¬Èô¸Ã»ìºÏÆøÌå±»×ãÁ¿µÄNaOHÈÜÒºÍêÈ«ÎüÊÕºóûÓÐÆøÌå²ÐÁô£¬ËùÉú³ÉµÄRµÄº¬ÑõËáÑÎÖ»ÓÐÒ»ÖÖ£¬Ôò¸Ãº¬ÑõËáÑεĻ¯Ñ§Ê½ÊÇ____________¡£
£¨1£© £¨2£©ÈõÓÚ £¨3£©S+2H2SO4(Ũ)3SO2¡ü+2H2O
£¨4£©2H2O22H2O+O2¡ü £¼ £¨5£©NaNO2
£¨4£©2H2O22H2O+O2¡ü £¼ £¨5£©NaNO2
¸ù¾ÝÔªËØÔÚÖÜÆÚ±íÖеÄλÖÿÉÖª£¬TÊǵÚÈýÖÜÆÚ£¬ËùÒÔTÊÇAl¡£ÔòQÊÇC£¬RÊÇN£¬WÊÇS¡£
£¨1£©ÂÁÀë×ÓÖ»Óë2¸öµç×Ӳ㣬Àë×ӽṹʾÒâͼΪ¡£
£¨2£©ÁòËáµÄËáÐÔÇ¿ÓÚ̼ËáµÄ£¬ËùÒÔ̼µÄ·Ç½ðÊôÐÔÈõÓÚÁòµÄ·Ç½ðÊôÐÔ¡£
£¨3£©Å¨ÁòËá¾ßÓÐÑõ»¯ÐÔ£¬ÔÚ¼ÓÈȵÄÌõ¼þÏÂÄܺ͵¥ÖÊÁò·´Ó¦Éú³ÉSO2ºÍË®£¬·½³ÌʽΪS+2H2SO4(Ũ)3SO2¡ü+2H2O¡£
£¨4£©Ô×ÓÐòÊý±ÈR¶à1µÄÔªËØÊÇÑõÔªËØ£¬¶ÔÓ¦µÄÇ⻯ÎïÊÇË«ÑõË®ºÍË®¡£Ë«ÑõË®²»Îȶ¨£¬·Ö½âÉú³ÉÑõÆøºÍË®£¬·½³ÌʽΪ2H2O22H2O+O2¡ü ¡£Ë«ÑõË®ÊǺ¬Óм«ÐÔ¼üºÍ·Ç¼«ÐÔ¼üµÄ¹²¼Û»¯ºÏÎµç×ÓʽΪ¡£ºËÍâµç×ÓÅŲ¼ÏàͬµÄ΢Á££¬Æä΢Á£°ë¾¶ËæÔ×ÓÐòÊýµÄÔö´ó¶ø¼õС£¬ËùÒÔÀë×Ӱ뾶T3+£¼R3-¡£
£¨5£©µªÔªËصÄÑõ»¯ÎïÖÐÏà¶Ô·Ö×ÓÖÊÁ¿×îСµÄÊÇNO£¬ÔÚ·´Ó¦ÖÐÌå»ýÖ®±ÈÊÇÆøÌåµÄÎïÖʵÄÁ¿Ö®±È£¬ËùÒÔ¸ù¾Ýµç×ÓµÃʧÊغã¿ÉÖª£¬NOÖеªÔ×Óʧȥ£¬ËùÒÔÆäÑõ»¯²úÎïµÄ¼Û̬ÊÇ£«£¨2£«1£©£½£«3¼Û£¬¼´º¬ÑõËáÑÎÊÇÑÇÏõËáÄÆ¡£
£¨1£©ÂÁÀë×ÓÖ»Óë2¸öµç×Ӳ㣬Àë×ӽṹʾÒâͼΪ¡£
£¨2£©ÁòËáµÄËáÐÔÇ¿ÓÚ̼ËáµÄ£¬ËùÒÔ̼µÄ·Ç½ðÊôÐÔÈõÓÚÁòµÄ·Ç½ðÊôÐÔ¡£
£¨3£©Å¨ÁòËá¾ßÓÐÑõ»¯ÐÔ£¬ÔÚ¼ÓÈȵÄÌõ¼þÏÂÄܺ͵¥ÖÊÁò·´Ó¦Éú³ÉSO2ºÍË®£¬·½³ÌʽΪS+2H2SO4(Ũ)3SO2¡ü+2H2O¡£
£¨4£©Ô×ÓÐòÊý±ÈR¶à1µÄÔªËØÊÇÑõÔªËØ£¬¶ÔÓ¦µÄÇ⻯ÎïÊÇË«ÑõË®ºÍË®¡£Ë«ÑõË®²»Îȶ¨£¬·Ö½âÉú³ÉÑõÆøºÍË®£¬·½³ÌʽΪ2H2O22H2O+O2¡ü ¡£Ë«ÑõË®ÊǺ¬Óм«ÐÔ¼üºÍ·Ç¼«ÐÔ¼üµÄ¹²¼Û»¯ºÏÎµç×ÓʽΪ¡£ºËÍâµç×ÓÅŲ¼ÏàͬµÄ΢Á££¬Æä΢Á£°ë¾¶ËæÔ×ÓÐòÊýµÄÔö´ó¶ø¼õС£¬ËùÒÔÀë×Ӱ뾶T3+£¼R3-¡£
£¨5£©µªÔªËصÄÑõ»¯ÎïÖÐÏà¶Ô·Ö×ÓÖÊÁ¿×îСµÄÊÇNO£¬ÔÚ·´Ó¦ÖÐÌå»ýÖ®±ÈÊÇÆøÌåµÄÎïÖʵÄÁ¿Ö®±È£¬ËùÒÔ¸ù¾Ýµç×ÓµÃʧÊغã¿ÉÖª£¬NOÖеªÔ×Óʧȥ£¬ËùÒÔÆäÑõ»¯²úÎïµÄ¼Û̬ÊÇ£«£¨2£«1£©£½£«3¼Û£¬¼´º¬ÑõËáÑÎÊÇÑÇÏõËáÄÆ¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿