ÌâÄ¿ÄÚÈÝ

ʳÑÎÖк¬ÓÐÒ»¶¨Á¿µÄþ¡¢ÌúµÈÔÓÖÊ£¬¼ÓµâÑÎÖеâµÄËðʧÖ÷ÒªÊÇÓÉÓÚÔÓÖÊ¡¢Ë®·Ö¡¢¿ÕÆøÖеÄÑõÆøÒÔ¼°¹âÕÕ¡¢ÊÜÈȶøÒýÆðµÄ¡£
ÒÑÖª£º¢ÙÑõ»¯ÐÔ£º £¾Fe3£«£¾I2£»»¹Ô­ÐÔ£º£¾I£­£»¢ÚKI£«I2KI3
£¨1£©Ä³Ñ§Ï°Ð¡×é¶Ô¼ÓµâÑνøÐÐÈçÏÂʵÑ飺ȡһ¶¨Á¿Ä³¼ÓµâÑÎ(¿ÉÄܺ¬ÓÐKIO3¡¢KI¡¢Mg2£«¡¢Fe2£«¡¢Fe3£«)£¬ÓÃÊÊÁ¿ÕôÁóË®Èܽ⣬²¢¼ÓÏ¡ÑÎËáËữ£¬½«ËùµÃÈÜÒº·ÖΪ4·Ý¡£µÚÒ»·ÝÊÔÒºÖеμÓKSCNÈÜÒººóÏÔºìÉ«£»µÚ¶þ·ÝÊÔÒºÖмÓ×ãÁ¿KI¹ÌÌ壬ÈÜÒºÏÔµ­»ÆÉ«£¬ÓÃCCl4ÝÍÈ¡£¬Ï²ãÈÜÒºÏÔ×ϺìÉ«£»µÚÈý·ÝÊÔÒºÖмÓÈëÊÊÁ¿KIO3¹ÌÌåºó£¬µÎ¼Óµí·ÛÊÔ¼Á£¬ÈÜÒº²»±äÉ«¡£
¢ÙÏòµÚËÄ·ÝÊÔÒºÖмÓK3Fe(CN)6ÈÜÒº£¬¸ù¾ÝÊÇ·ñµÃµ½¾ßÓÐÌØÕ÷À¶É«µÄ³Áµí£¬¿É¼ìÑéÊÇ·ñº¬ÓР  £¨ÓÃÀë×Ó·ûºÅ±íʾ£©£¬À¶É«µÄ³ÁµíÊÇ_______£¨Óû¯Ñ§Ê½±íʾ£©¡£
¢ÚµÚ¶þ·ÝÊÔÒºÖмÓÈë×ãÁ¿KI¹ÌÌåºó£¬·´Ó¦µÄÀë×Ó·½³ÌʽΪ£º______¡¢______
£¨2£©KI×÷Ϊ¼Óµâ¼ÁµÄʳÑÎÔÚ±£´æ¹ý³ÌÖУ¬ÓÉÓÚ¿ÕÆøÖÐÑõÆøµÄ×÷Óã¬ÈÝÒ×ÒýÆðµâµÄËðʧд³ö³±Êª»·¾³ÏÂKIÓëÑõÆø·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º_________________¡£
½«I2ÈÜÓÚKIÈÜÒº£¬ÔÚµÍÎÂÌõ¼þÏ£¬¿ÉÖƵÃKI3¡¤H2O¡£¸ÃÎïÖʲ»ÊʺÏ×÷ΪʳÑμӵâ¼Á£¬ÆäÀíÓÉÊÇ_________________________________¡£
£¨3£©Ä³Í¬Ñ§ÎªÌ½¾¿Î¶Ⱥͷ´Ó¦ÎïŨ¶È¶Ô·´Ó¦2IO3£­£«5SO32£­£«2H£«=I2£«5SO42£­£«H2OµÄËÙÂʵÄÓ°Ï죬Éè¼ÆʵÑéÈçϱíËùʾ£º

 
0.01mol¡¤L£­1KIO3
ËáÐÔÈÜÒº(º¬µí·Û)
µÄÌå»ý/mL
0.01mol¡¤L£­Na2SO3
ÈÜÒºµÄÌå»ý/mL
H2OµÄ
Ìå»ý/mL
ʵÑé
ζÈ
/¡æ
ÈÜÒº³öÏÖ
À¶É«Ê±Ëù
Ðèʱ¼ä/s
ʵÑé1
5
V1
35
25
t1
ʵÑé2
5
5
40
25
t2
ʵÑé3
5
5
V2
0
t3
 
±íÖÐÊý¾Ý£ºt1     t2£¨Ìî¡°>¡±¡¢¡°<¡±»ò¡°=¡±£©£»±íÖÐV2=___________mL

£¨¹²14·Ö£©
£¨1£©¢Ù Fe2£« £¬  Fe 3[Fe(CN)6]2     £¨¸÷1·Ö£©
¢ÚIO3£­£«5I£­£«6H£«=3I2£«3H2O   2Fe3£«£«2I£­=2Fe2£«£«I£¨¸÷2·Ö£©
£¨2£©O2£«4KI£«2H2O=2I2£«4KOH £¨2·Ö£©
KI3ÔÚÊÜÈÈ£¨»ò³±Êª£©Ìõ¼þϲúÉúI2ºÍKI£¬KI±»ÑõÆøÑõ»¯£¬I2Ò×Éý»ª¡££¨2·Ö£©
£¨3£©< £» 40 £¨¸÷2·Ö£©

½âÎöÊÔÌâ·ÖÎö£º
£¨1£©¢ÙFe2£«ÓëÌúÇ軯¼ØÈÜÒºÓÐÌØÕ÷·´Ó¦ÏÖÏó¡£
¢ÚÓ¦ÓÃÐÅÏ¢£º¡°Ñõ»¯ÐÔ£ºIO3£­£¾Fe3£«£¾I2¡±£¬ËµÃ÷IO3£­ºÍFe3£«¾ùÄÜÑõ»¯I£­Éú³ÉI2¡£
£¨2£©KI±»³±Êª¿ÕÆøÑõ»¯¶øÒýÆðËðʧ£¬ËùÒÔ¿¼ÂÇI£­±»ÑõÆøÑõ»¯ÐγÉI2Éý»ª´Ó¶øÔì³ÉËðʧ¡£
¸ù¾ÝÒÑÖªÐÅÏ¢£º¡°KI£«I2 KI3¡±½âÎöÆäÐÔÖʲ»Îȶ¨ÐÔ£¬Ò×·¢Éú·Ö½â¹ý³Ì¡£
£¨3£©Óɱí¸ñÐÅÏ¢¿ÉÖª£¬Èý×éʵÑéΪƽÐжÔÕÕʵÑ飬Ҫ×ñÑ­¡°µ¥Ò»±äÁ¿¡±µÄ¹æÔò£¬Òò´ËÕâÈý×éʵÑéÈÜÒºµÄ×ÜÌå»ý¶¼µÈÓÚ50 ml£¬Òò´ËV2="40" ml¡£ÊµÑé1ºÍʵÑé2±È½Ï£¬ÊµÑé2ÖÐË®µÄÌå»ý¶à£¬ËµÃ÷ÈÜÖÊŨ¶È±ÈʵÑé1ÖеÄҪС£¬·´Ó¦ËÙÂÊÂý£¬ËùÓÃʱ¼ä³¤£¬ËùÒÔt1£¼t2
¿¼µã¶¨Î»£º¿¼²éÁËÀë×ӵļìÑ飬Ñõ»¯»¹Ô­·´Ó¦µÄÊéд£¬ÊµÑéÉè¼ÆÊý¾Ý·ÖÎöµÈÏà¹Ø֪ʶ£¬ÅàÑøѧÉúÌâ¸ÉÐÅÏ¢µÄ¶ÁÈ¡ºÍ·ÖÎöµÄÄÜÁ¦¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

ij¿ÎÍâС×éѧÉú¶ÔCl2ÓëFeBr2ÈÜÒº·´Ó¦½øÐÐʵÑé̽¾¿¡£

²Ù ×÷
ÏÖ Ïó
È¡0£®1 mol/LµÄFeBr2ÈÜÒº10 mL£¬²âÈÜÒºµÄpH
pHÊÔÖ½±äºì£¨Ô¼Îª4£©

¢¡£®¿ªÊ¼Í¨Èë100 mL£¨Õۺϱê×¼×´¿ö£©£¬ÈÜÒºÓÉdzÂÌÉ«Öð½¥±ä»Æ£»
¢¢£®ÉԺ󣬼ÌÐøͨÈëCl2£¬ÈÜÒº»ÆÉ«¼ÓÉ±äΪ×Ø»ÆÉ«£»
iii£®ÉÔºó£¬ÈÜÒºÓÉ×Ø»ÆÉ«±ädz£¬×îÖÕ±äΪ»ÆÉ«
 
£¨1£©ÓÃŨÑÎËáºÍMnO2·´Ó¦ÖÆÈ¡Cl2µÄ»¯Ñ§·½³ÌʽÊÇ                                  ¡£
£¨2£©pH¡Ö4µÄÔ­ÒòÊÇ                                 £¨Óû¯Ñ§ÓÃÓï±íʾ£©¡£
£¨3£©ÏÖÏóiÖÐÈÜÒºÓÉdzÂÌÉ«Öð½¥±ä»Æ¡£Ä³Ñ§Éú²Â²â¿ÉÄÜÔ­Òò£º¢ÙCl2½«Fe2+Ñõ»¯ÎªFe3+£¬Ê¹ÈÜÒº³Ê»ÆÉ«£»¢ÚCl2½«Br£­Ñõ»¯ÎªBr2£¬Ê¹ÈÜÒº³Ê»ÆÉ«¡£Ö¤Ã÷Ô­Òò¢ÙµÄʵÑé·½°¸ÊÇ       £»Ö¤Ã÷Ô­Òò¢ÚµÄʵÑé·½°¸ÊÇ                               ¡£
£¨4£©ÏÖÏó¢¢ÖУ¬ÈÜÒº±äΪ×Ø»ÆÉ«¡£²¿·ÖѧÉú²Â²â¢Ù£º¿ÉÄÜÊÇCl2ÏȽ«Fe2+Ñõ»¯Éú³ÉFe3+£¬Cl2ÓÖ¼ÌÐøÑõ»¯Br£­Éú³ÉBr2¡£²¿·ÖѧÉú²Â²â¢Ú£º¿ÉÄÜÊÇCl2ÏȽ«Fe2+Ñõ»¯Éú³ÉFe3+£¬Fe3+½«Br£­Ñõ»¯Éú³ÉBr2¡£Ä³Ñ§ÉúÉè¼ÆʵÑé½øÐÐÑéÖ¤£¬ÇëÍê³ÉÏÂÁбí¸ñ£º
ÓÉ´ËʵÑéµÃ³öµÄ½áÂÛÊÇ                                ¡£
ÊÔ¹Ü
²Ù×÷
ÏÖÏó
½áÂÛ
a
È¡2 mL FeCl2ÈÜÒº£¬µÎ¼ÓÉÙÁ¿ÂÈË®¡¢2µÎKSCNÈÜÒº£¬Õñµ´
 
 
Cl2µÄÑõ»¯ÐÔÇ¿ÓÚFe3+
b
È¡2 mL FeCl3ÈÜÒº£¬µÎ¼ÓÉÙÁ¿ä廯ÄÆÈÜÒººÍÉÙÁ¿CCl4£¬Õñµ´
CCl4²ãûÓÐÃ÷ÏԱ仯
 
 
c
                                
CCl4²ãÓÉÎÞÉ«±äΪ³È»ÆÉ«
Cl2µÄÑõ»¯ÐÔÇ¿ÓÚBr2
 

KMnO4ÈÜÒº³£ÓÃ×÷Ñõ»¯»¹Ô­·´Ó¦µÎ¶¨µÄ±ê×¼Òº£¬ÓÉÓÚKMnO4µÄÇ¿Ñõ»¯ÐÔ£¬ËüµÄÈÜÒººÜÈÝÒ×±»¿ÕÆøÖлòË®ÖеÄijЩÉÙÁ¿»¹Ô­ÐÔÎïÖÊ»¹Ô­£¬Éú³ÉÄÑÈÜÐÔÎïÖÊMnO(OH)2£¬Òò´ËÅäÖÆKMnO4±ê×¼ÈÜÒºµÄ²Ù×÷ÈçÏÂËùʾ£º¢Ù³ÆÈ¡ÉÔ¶àÓÚËùÐèÁ¿µÄKMnO4¹ÌÌåÈÜÓÚË®ÖУ¬½«ÈÜÒº¼ÓÈȲ¢±£³Ö΢·Ð1 h£»¢ÚÓÃ΢¿×²£Á§Â©¶·¹ýÂ˳ýÈ¥ÄÑÈܵÄMnO(OH)2£»¢Û¹ýÂ˵õ½µÄKMnO4ÈÜÒºÖü´æÓÚ×ØÉ«ÊÔ¼ÁÆ¿²¢·ÅÔÚ°µ´¦£»¢ÜÀûÓÃÑõ»¯»¹Ô­µÎ¶¨·½·¨£¬Óûù×¼ÊÔ¼Á(´¿¶È¸ß¡¢Ïà¶Ô·Ö×ÓÖÊÁ¿½Ï´ó¡¢Îȶ¨ÐԽϺõÄÎïÖÊ)ÈÜÒº±ê¶¨ÆäŨ¶È£¬KMnO4Ôڵζ¨Öб»»¹Ô­³ÉMn2+¡£Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£© ׼ȷÁ¿È¡Ò»¶¨Ìå»ýµÄKMnO4ÈÜÒºÐèҪʹÓõÄÒÇÆ÷ÊÇ____________¡£
£¨2£© ÔÚÏÂÁÐÎïÖÊÖУ¬ÓÃÓڱ궨KMnO4ÈÜÒºµÄ»ù×¼ÊÔ¼Á×îºÃÑ¡ÓÃ________(ÌîÐòºÅ)¡£

A£®ÖÊÁ¿·ÖÊýΪ30%µÄË«ÑõË®B£®FeSO4C£®Ä¦¶ûÑÎD£®Na2SO3
£¨3£© ±¾ÊµÑéÒ²¿É²ÉÓÃH2C2O4¡¤2H2O×ö»ù×¼ÊÔ¼Á£¬×¼È·³ÆÈ¡W g H2C2O4¡¤2H2OÈÜÓÚË®Åä³É500 mLÈÜÒº£¬È¡25.00 mLÖÃÓÚ׶ÐÎÆ¿ÖУ¬ÓÃKMnO4ÈÜÒºµÎ¶¨ÖÁÖÕµãµÄʵÑéÏÖÏóΪ         £¬ÈôÏûºÄKMnO4ÈÜÒºV mL¡£KMnO4ÈÜÒºµÄÎïÖʵÄÁ¿Å¨¶ÈΪ________mol¡¤L£­1¡£
£¨4£© ²ÉÓÃH2C2O4¡¤2H2O×ö»ù×¼ÊÔ¼ÁµÄÑõ»¯»¹Ô­µÎ¶¨ÔÚÊÒÎÂʱ·´Ó¦ºÜÂý£¬ËùÒÔ·´Ó¦ÐèÒªÔÚ70¡«80 ¡æÌõ¼þϽøÐУ¬µ«Î¶ȸü¸ß»áµ¼Ö²ÝËá·Ö½â²úÉúÆøÌ壬д³ö²ÝËá·Ö½âµÄ»¯Ñ§·´Ó¦·½³Ìʽ                    £¬ÈôÈç´ËËù²âµÃµÄ¸ßÃÌËá¼Ø±ê׼ҺŨ¶È»á     (Ìî¡°Æ«¸ß¡±¡¢¡°Æ«µÍ¡±»ò¡°ÎÞÓ°Ï족)¡£¼´Ê¹¿ØÖÆ70¡«80 ¡æÌõ¼þ£¬Ò»¿ªÊ¼µÎ¶¨Ê±·´Ó¦ÈÔÈ»½ÏÂý£¬ÈôµÎ¼ÓKMnO4ÈÜÒº¹ý¿ìµÄ»°£¬»áÔì³ÉKMnO4ÈÜҺŨ¶È¾Ö²¿¹ý¸ß¶ø·Ö½â£¬Òò´ËÔÚ¿ªÊ¼¼¸µÎ²Ù×÷ʱӦ                                            £¬ÔÚµÎÈ뼸µÎKMnO4ÈÜÒºÖ®ºó£¬·´Ó¦ËÙÂÊ»áѸËټӿ죬¸ÃµÎ¶¨²Ù×÷Ò²¿ÉÏàÓ¦¼Ó¿ì£¬·´Ó¦ËÙÂʼӿìµÄÔ­ÒòÊÇ                                          ¡£
£¨5£©ÈôÓ÷ÅÖÃÁ½ÖܺóµÄKMnO4±ê×¼ÈÜҺȥ²â¶¨Ë®ÑùÖÐFe2£«µÄº¬Á¿£¬²âµÃµÄFe2£«Å¨¶ÈÖµ½«________(Ìî¡°Æ«¸ß¡±¡¢¡°Æ«µÍ¡±»ò¡°ÎÞÓ°Ï족)¡£

ΪÑéÖ¤Ñõ»¯ÐÔ£ºCl2£¾Fe3+£¾SO2£¬Ä³Ð¡×éÓÃÏÂͼËùʾװÖýøÐÐʵÑ飨¼Ð³ÖÒÇÆ÷ºÍAÖеļÓÈÈ×°ÖÃÒÑÂÔ£¬ÆøÃÜÐÔÒѾ­¼ìÑéÍê±Ï£©

ʵÑé¹ý³Ì£º
¢ñ£®´ò¿ªµ¯»É¼ÐK1-K4£¬Í¨ÈëÒ»¶Îʱ¼äN2£¬ÔÙ½«TÐ͵¼¹Ü²åÈëBÖУ¬¼ÌÐøͨÈëN2£¬µ¥ºó¹Ø±ÕK1¡¢K2¡¢K3 .
¢ò£®´ò¿ª»îÈûa£¬µÎ¼ÓÒ»¶¨Á¿µÄŨÑÎËᣬ¸øA¼ÓÈÈ.
¢ó£®µ±BÖеÄÈÜÒº±ä»Æʱ£¬Í£Ö¹¼ÓÈÈ£¬¼Ð½ôµ¯»É¼ÐK2.
¢ô£®´ò¿ª»îÈûb£¬Ê¹Ô¼2mlµÄÈÜÒºÁ÷ÈëDÊÔ¹ÜÖУ¬¼ìÑéÆäÖеÄÀë×Ó.
¢õ£®´ò¿ªµ¯»É¼ÐK3¡¢»îÈûc£¬¼ÓÈë70%µÄÁòËᣬһ¶Îʱ¼äºó¼Ð½ôµ¯»É¼ÐK3.
¢ö.¸üÐÂÊÔ¹ÜD£¬Öظ´¹ý³Ì¢ö£¬¼ìÑéBÈÜÒºÖеÄÀë×Ó.
£¨1£©¹ý³Ì¢ñµÄÄ¿µÄÊÇ___________________________
£¨2£©ÃÞ»¨ÖнþÈóµÄÈÜҺΪ_______________________
£¨3£©AÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ_____________________________________________
£¨4£©ÓÃ70%µÄÁòËá֧ȡSO2£¬·´Ó¦ËÙÂʱÈÓÃ98%µÄÁòËá¿é£¬Ô­ÒòÊÇ___________________
£¨5£©¹ý³Ì¢ôÖмìÑéBÈÜÒºÖÐÊÇ·ñº¬ÓÐÁòËá¸ùµÄ²Ù×÷ÊÇ______________________________
£¨6£©¼×¡¢ÒÒ¡¢±ûÈýλͬѧ·Ö±ðÍê³ÉÁËÉÏÊöʵÑ飬ËûÃǵļì²â½á¹ûÒ»¶¨Äܹ»Ö¤Ã÷Ñõ»¯Cl2£¾Fe3+£¾SO2µÄÊÇ      

 
 ¹ý³Ì¢ô BÈÜÒºÖк¬ÓеÄÀë×Ó
¹ý³Ì¢ö BÈÜÒºÖк¬ÓеÄÀë×Ó
¼×
    ÓÐFe3+ÎÞFe2+
ÓÐSO42-
ÒÒ
  ¼ÈÓÐFe3+ÓÖÓÐFe2+
ÓÐSO42-
±û
    ÓÐFe3+ÎÞFe2+
           ÓÐFe2+
 
£¨7£©½øÐÐʵÑé¹ý³Ì¢õʱ£¬BÖеÄÈÜÒºÑÕÉ«ÓÉ»ÆÉ«±äΪºì×ØÉ«£¬Í£Ö¹Í¨Æø£¬·ÅÖÃÒ»¶Îʱ¼äºóÈÜÒºÑÕÉ«±äΪdzÂÌÉ«¡£
²éÔÄ×ÊÁÏ£ºFe2+(aq)+SO32-(aq)  FeSO3£¨s£©
Ìá³ö¼ÙÉ裺FeCl3ºÍSO2µÄ·´Ó¦¾­ÀúÁËÖмä²úÎïFeSO3£¬ÈÜÒºµÄºì×ØÉ«ÊÇFeSO3£¨Ä«ÂÌÉ«£©ÓëFeCl3£¨»ÆÉ«£©µÄ»ìºÏÑÕÉ«¡£
ijͬѧÉè¼ÆÈçÏÂʵÑ飬Õýʽ¸Ã¼ÙÉèµÄ³ÉÁ¢£º

ÈÜÒºEºÍF·Ö±ðÊÇ___________¡¢_______________
ÇëÓû¯Ñ§Æ½ºâÔ­Àí½âÊͲ½Öè3ºì×ØÉ«ÈÜÒº±äΪdzÂÌÉ«µÄÔ­Òò___________________________

£¨14·Ö£©¢ñ£®Ä³Í¬Ñ§×ö¡°ÂÁÈÈ·´Ó¦¡±µÄʵÑé¡£²éÔÄ¡¶»¯Ñ§Êֲᡷ֪£¬Al¡¢Al2O3¡¢Fe¡¢Fe2O3È۵㡢·ÐµãÊý¾ÝÈçÏ£º

ÎïÖÊ
Al
Al2O3
Fe
Fe2O3
ÈÛµã/¡æ
660
2054
1535
1462
·Ðµã/¡æ
2467
2980
2750
¡ª¡ª
£¨1£©ÂÁÈÈ·´Ó¦·½³ÌʽΪ                                       ¡£
£¨2£©ÏÂÁÐÄÜÓëAl·¢ÉúÂÁÈÈ·´Ó¦µÄÓР      ¡££¨ÌîÐòºÅ£©
A¡¢MnO2         B¡¢Na2O    C¡¢MgO       D¡¢FeO
£¨3£©¾ÝÉϱíÊý¾Ý¸ÃͬѧÍƲ⣬ÂÁÈÈ·´Ó¦ËùµÃµ½µÄÈÛÈÚÎïÓ¦ÊÇÌúÂÁºÏ½ð¡£ÈôÖ¤Ã÷ÉÏÊöËùµÃµÄ¿é×´ÈÛÈÚÎïÖк¬ÓнðÊôÂÁ£¬ËùÓÃÊÔ¼ÁÊÇ           ¡£
¢ò£®Ä³Í¬Ñ§ÎªÁËÑéÖ¤º£´øÖк¬Óе⣬Äâ½øÐÐÈçÏÂʵÑ飬Çë»Ø´ðÏà¹ØÎÊÌâ¡£
£¨1£©µÚ1²½£º×ÆÉÕ¡£²Ù×÷Êǽ«×ãÁ¿º£´ø×ÆÉճɻҽý¡£¸Ã¹ý³ÌÖн«Ê¹Óõ½µÄʵÑéÒÇÆ÷ÓÐ________µÈ¡££¨Ìî´úºÅ£¬ÏÂͬ£©
A ÊԹܠ     B ÛáÛö      C ÉÕ±­      D Èý½Ç¼Ü
E¡¢ÄàÈý½Ç    F¡¢È÷¾«µÆ    G¡¢Ìú¼Ų̈    H¡¢Á¿Í²
µÚ2²½£ºI¡¥ÈÜÒºµÄ»ñÈ¡¡£²Ù×÷Êǽ«»Ò½ýתÒƵ½ÉÕ±­ÖУ¬¼ÓÊÊÁ¿ÕôÁóË®Èܽ⣬¸Ã¹ý³ÌΪ¼Ó¿ìÈܽâ¿ÉÒÔ²ÉÈ¡ÄÄЩ´ëÊ©                  ¡£´Ë²Ù×÷ºóµÄ·ÖÀë·½·¨________¡££¨Ìî·ÖÀë·½·¨£©
£¨3£©µÚ3²½£ºÑõ»¯¡£È¡(2)ÖÐÈÜÒºÉÙÁ¿ÒÀ´Î¼ÓÈëºÏÊʵÄÊÔ¼Á¡£ÏÂÁÐÑõ»¯¼Á×îºÃÑ¡_________¡£
A¡¢Å¨ÁòËá     B¡¢ÐÂÖÆÂÈË®      C¡¢KMnO4ÈÜÒº       D¡¢H2O2
£¨4£©µÚ4²½£ºµâµ¥ÖʵļìÑé¡£²Ù×÷ÊÇÈ¡ÉÙÁ¿µÚ3²½µÄÈÜÒº£¬µÎ¼Ó_______ÈÜÒº£¬Ö¤Ã÷º£´øÖк¬µâ¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø