ÌâÄ¿ÄÚÈÝ

³£ÎÂÏ£¬ÏÂÁи÷×éÀë×ÓÔÚÖ¸¶¨ÈÜÒºÖпÉÄÜ´óÁ¿¹²´æµÄÊÇ:

A£®µÎÈë¼×»ù³ÈÏÔºìÉ«µÄÈÜÒºÖУº Na£«¡¢NO3¡¥¡¢ Fe2+¡¢SO32¡¥
B£®Ë®µçÀë³öµÄ c ( H+) = 10¡¥12 mol/L µÄÈÜÒºÖÐ:K+¡¢ AlO2¡¥¡¢ CH3COO¡¥¡¢ Cl¡¥
C£®=10¡¥12µÄÈÜÒºÖУº K+¡¢ClO¡¥¡¢S2¡¥¡¢ Cl¡¥
D£®c ( Fe 3+ ) =" 0" .1 mol/L µÄÈÜÒºÖУº K+¡¢Cl¡¥ ¡¢SO42¡¥¡¢ SCN¡¥

B

½âÎöÊÔÌâ·ÖÎö£ºA£®µÎÈë¼×»ù³ÈÏÔºìÉ«£¬ÈÜҺΪËáÐÔ£º NO3¡¥ÓëFe2+¡¢SO32¡¥²»´óÁ¿¹²´æ£»B£®Ë®µçÀë³öµÄc(H+)=10¡¥12 mol/LµÄÈÜÒº¿ÉÒÔΪËáÐÔ£¬AlO2¡¥ºÍCH3COO¡¥²»ÄÜ´óÁ¿¹²´æ£¬¿ÉÒÔΪ¼îÐÔ£¬¿ÉÒÔ´óÁ¿¹²´æ£»C£®=10¡¥12ÈÜÒºµÄc(H+)=10-1mol/L£¬¼´ËáÐÔÈÜÒº£ºClO¡¥ÓëS2¡¥·¢ÉúÑõ»¯»¹Ô­·´Ó¦£»D£®c(Fe3+)="0.1" mol/L µÄÈÜÒºÖв»´æÔÚSCN¡¥£¬Fe3+ÓëÆä·¢ÉúÅäºÏ·´Ó¦¡£
¿¼µã£ºÏÞÖÆÌõ¼þµÄÀë×Ó×é¹²´æÇé¿öÅжϡ£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø