ÌâÄ¿ÄÚÈÝ

ÏÂÁÐ˵·¨²»ÕýÈ·µÄÊÇ£¨    )
A£®5.85gNaCl¾§ÌåÈÜÓÚ100gË®£¬ËùµÃÈÜÒºÎïÖʵÄÁ¿Å¨¶È²»µÈÓÚ1mol/L
B£®20gŨ¶ÈΪc mol¡¤L-1µÄ°±Ë®ÖмÓÈëÒ»¶¨Á¿µÄˮϡÊͳÉ0.5cmol¡¤L-1£¬Ôò¼ÓÈëË®µÄÌå»ýСÓÚ20ml
C£®Ä³ÂÈ»¯Ã¾ÈÜÒºµÄÃܶÈΪ1.18 g¡¤cm£­3£¬ÆäÖÐþÀë×ÓµÄÖÊÁ¿·ÖÊýΪ5.1%,300 mL¸ÃÈÜÒºÖÐCl£­µÄÎïÖʵÄÁ¿Ô¼µÈÓÚ1.50 mol
D£®V L Fe2(SO4)3ÈÜÒºÖк¬Fe3£«m g£¬ÔòÈÜÒºÖÐSO42-µÄÎïÖʵÄÁ¿Å¨¶ÈΪmol¡¤L£­1
B

ÊÔÌâ·ÖÎö£ºBÏ²»¿¼ÂÇÈÜÒºÌå»ýµÄ±ä»¯£¬Ôò¼ÓË®Ìå»ý£½Ô­ÈÜÒºÌå»ý£½20/¦Ñ mLµ«ÊÇÈÜÒº»ìºÏ¡¢Ï¡ÊÍÒª¿¼ÂÇÌå»ýµÄ΢С±ä»¯£¬Òò´Ë±È20/¦Ñ mLÂÔ´óÓÉÓÚ£¬°±Ë®ÃܶÈСÓÚË®£¬¼´Ð¡ÓÚ1£¬ËùÒÔ20/¦Ñ mL > 20 mL¡£BÏî´íÎó¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
ÈçͼΪʵÑéÊÒijŨÁòËáÊÔ¼ÁÆ¿ÉϵıêÇ©£¬ÊÔ¸ù¾ÝÓйØÊý¾Ý»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©¸ÃŨÁòËáµÄÎïÖʵÄÁ¿Å¨¶ÈΪ__________mol/L¡£
£¨2£©È¡ÓÃÈÎÒâÌå»ýµÄ¸ÃÁòËáÈÜҺʱ£¬ÏÂÁÐÎïÀíÁ¿Öв»ËæËùÈ¡Ìå    »ýµÄ¶àÉÙ¶ø±ä»¯µÄÊÇ__________¡£
A£®ÈÜÒºÖÐH2SO4µÄÎïÖʵÄÁ¿       B£®ÈÜÒºµÄŨ¶È
C£®ÈÜÒºÖÐSO42£­µÄÊýÄ¿            D£®ÈÜÒºµÄÃܶÈ
£¨3£©Ä³Ñ§ÉúÓûÓÃÉÏÊöŨÁòËáºÍÕôÁóË®ÅäÖÆ480 mLÎïÖʵÄÁ¿Å¨¶ÈΪ0.2 mol/LÏ¡ÁòËá¡£
¢Ù¸ÃѧÉúÐèÒªÁ¿È¡________mLÉÏÊöŨÁòËá½øÐÐÅäÖÆ¡£
¢ÚÅäÖÆʱ£¬ÆäÕýÈ·µÄ²Ù×÷˳ÐòÊÇ£¨×Öĸ±íʾ£¬Ã¿¸ö×ÖĸֻÄÜÓÃÒ»´Î£©________________£»
A£®ÓÃ30mLˮϴµÓÉÕ±­2¡«3´Î£¬Ï´µÓÒº¾ù×¢ÈëÈÝÁ¿Æ¿£¬Õñµ´
B£®ÓÃÁ¿Í²×¼È·Á¿È¡ËùÐèŨÁòËáµÄÌå»ý£¬ÂýÂýÑر­±Ú×¢ÈëÊ¢ÓÐÉÙÁ¿Ë®£¨Ô¼30mL£©µÄÉÕ±­ÖУ¬Óò£Á§°ôÂýÂý½Á¶¯£¬Ê¹Æä»ìºÏ¾ùÔÈ
C£®½«ÒÑÀäÈ´µÄÁòËáÑز£Á§°ô×¢ÈëÒ»¶¨Ìå»ýµÄÈÝÁ¿Æ¿ÖÐ
D£®½«ÈÝÁ¿Æ¿¸Ç½ô£¬µßµ¹Ò¡ÔÈ
E£®¸ÄÓýºÍ·µÎ¹Ü¼ÓË®£¬Ê¹ÈÜÒº°¼ÃæÇ¡ºÃÓë¿Ì¶ÈÏßÏàÇÐ
F£®¼ÌÐøÍùÈÝÁ¿Æ¿ÄÚСÐļÓË®£¬Ö±µ½ÒºÃæ½Ó½ü¿Ì¶ÈÏß1¡«2cm´¦
¢ÛÔÚÅäÖƹý³ÌÖУ¬ÏÂÁÐʵÑé²Ù×÷ʹËùÅäÖƵÄÏ¡ÁòËáµÄÎïÖʵÄÁ¿Å¨¶ÈÆ«¸ßµÄÊÇ_________
A£®ÓÃÁ¿Í²Á¿È¡Å¨ÁòËáʱÑöÊӹ۲찼ҺÃæ
B£®Ï¡ÊÍÓõÄÉÕ±­ºÍ²£Á§°ôδϴµÓ
C£®Ï´¾»µÄÈÝÁ¿Æ¿Î´¾­¸ÉÔï¾ÍÓÃÓÚÅäÖÆÈÜÒº
D£®ÈÜҺעÈëÈÝÁ¿Æ¿Ç°Ã»Óлָ´µ½ÊÒξͽøÐж¨ÈÝ
E£®¶¨ÈÝʱ¸©Êӹ۲찼ҺÃæ
F£®¼ÓË®³¬¹ý¿Ì¶ÈÏߺó£¬ÓýºÍ·µÎ¹ÜÎü³ö¶àÓàµÄÒºÌå
¢ÜÏÖ½«100mL¸ÃÁòËáÓë300mL 0.4mol/LCuSO4ÈÜÒº»ìºÏ£¬Ìå»ý±ä»¯ºöÂÔ²»¼Æ£¬ËùµÃÈÜÒºÖÐSO42£­µÄÎïÖʵÄÁ¿Å¨¶ÈÊÇ_________mol/L¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø