ÌâÄ¿ÄÚÈÝ
£¨9·Ö£©ÓÐA¡¢B¡¢C¡¢D¡¢E¡¢F¡¢G¡¢H¡¢IµÈ¾ÅÖÖ³£¼ûÎïÖÊ£¬ËüÃǵÄת»¯¹Øϵ£¨·´Ó¦Ìõ¼þδעÃ÷£©ÈçÏÂͼËùʾ¡£ÒÑÖª£ºB¡¢C¡¢FΪµ¥ÖÊ£¬³£Î³£Ñ¹Ï£¬BΪ¹Ì̬£¬C¡¢FΪÆø̬£»»¯ºÏÎïÖнöA¡¢EΪÆø̬£»³£ÎÂÏ£¬DΪµ»ÆÉ«·ÛÄ©£¬HµÄÑæÉ«·´Ó¦Îª»ÆÉ«¡£GΪÎÞÉ«ÒºÌå¡£
£¨1£©Ð´³öGÓëD·´Ó¦µÄÀë×Ó·½³Ìʽ___________________________¡£
£¨2£©Ð´³öBÓëG·´Ó¦µÄ»¯Ñ§·½³Ìʽ_____________________________¡£
£¨3£©ÔÚ¢Ù¡¢¢Ú¡¢¢Û¡¢¢Ü¡¢¢ÝÎå¸ö·´Ó¦ÖУ¬¡÷H£¾0µÄ·´Ó¦ÊÇ___£¨Ìî´úºÅ£©¡£
£¨4£©EÊÇÒ»ÖÖ¿ÉȼÐÔÆøÌ壬ÒÑÖª4.0gEÔÚÑõÆøÖÐÍêȫȼÉշųö71kJÈÈÁ¿£¬Ð´³ö¸Ã·´Ó¦µÄȼÉÕÈȵÄÈÈ»¯Ñ§·½³Ìʽ£º __________________________
£¨5£©Çëд³ö»¯ºÏÎïAµÄµç×Óʽ____________________
£¨1£©Ð´³öGÓëD·´Ó¦µÄÀë×Ó·½³Ìʽ___________________________¡£
£¨2£©Ð´³öBÓëG·´Ó¦µÄ»¯Ñ§·½³Ìʽ_____________________________¡£
£¨3£©ÔÚ¢Ù¡¢¢Ú¡¢¢Û¡¢¢Ü¡¢¢ÝÎå¸ö·´Ó¦ÖУ¬¡÷H£¾0µÄ·´Ó¦ÊÇ___£¨Ìî´úºÅ£©¡£
£¨4£©EÊÇÒ»ÖÖ¿ÉȼÐÔÆøÌ壬ÒÑÖª4.0gEÔÚÑõÆøÖÐÍêȫȼÉշųö71kJÈÈÁ¿£¬Ð´³ö¸Ã·´Ó¦µÄȼÉÕÈȵÄÈÈ»¯Ñ§·½³Ìʽ£º __________________________
£¨5£©Çëд³ö»¯ºÏÎïAµÄµç×Óʽ____________________
£¨1£© 2Na2O2£«2H2O£½4Na£«£«4OH££«O2¡ü (2·Ö£©
£¨2£©C£«H2OCO£«H2 (2·Ö£©£¨3£©¢Ú¡¢¢Ý (2·Ö£©
(4) CO(g)£«1£¯2O2(g)£½CO2(g) ;¡÷H=-497kJ/mol (2·Ö£© £¨5£©
£¨2£©C£«H2OCO£«H2 (2·Ö£©£¨3£©¢Ú¡¢¢Ý (2·Ö£©
(4) CO(g)£«1£¯2O2(g)£½CO2(g) ;¡÷H=-497kJ/mol (2·Ö£© £¨5£©
±¾ÌâÊÇÎÞ»ú¿òͼÌ⣬¹Ø¼üÊÇÕÒ׼ͻÆƵ㡣DΪµ»ÆÉ«·ÛÄ©£¬HµÄÑæÉ«·´Ó¦Îª»ÆÉ«£¬GΪÎÞÉ«ÒºÌ壬ËùÒÔDÊǹýÑõ»¯ÄÆ£¬GÊÇË®¡£FÊÇÆø̬ÇâÑõ»¯ÄƵ¥ÖÊ£¬EÊÇÆø̬»¯ºÏÎËùÒÔBÊÇ̼£¬FÊÇÇâÆø£¬EÊÇCO¡£ÔòAÊÇCO2£¬CÊÇÑõÆø£¬HÊÇ̼Ëá±µ£¬IÊÇÇâÑõ»¯ÄÆ¡£
£¨3£©¿¼²é³£¼ûµÄ·ÅÈÈ·´Ó¦ºÍÎüÈÈ·´Ó¦¡£Ò»°ã½ðÊôºÍË®»òËá·´Ó¦£¬Ëá¼îÖкͷ´Ó¦£¬Ò»ÇÐȼÉÕ£¬´ó¶àÊý»¯ºÏ·´Ó¦ºÍÖû»·´Ó¦£¬»ºÂýÑõ»¯·´Ó¦ÈçÉúÐâµÈÊÇ·ÅÈÈ·´Ó¦¡£´ó¶àÊý·Ö½â·´Ó¦£¬ï§ÑκͼӦ£¬Ì¼¡¢ÇâÆø»òCO×÷»¹Ô¼ÁµÄ·´Ó¦µÈÊÇÎüÈÈ·´Ó¦¡£ËùÒÔ¢Ú¢ÝÊÇÎüÈÈ·´Ó¦¡£
£¨4£©È¼ÉÕÈÈÊÇÖ¸ÔÚÒ»¶¨Ìõ¼þÏ£¬1mol¿ÉȼÎïβÆøȼÉÕÉú³ÉÎȶ¨µÄÑõ»¯Îïʱ·¢³öµÄÈÈÁ¿£¬ËùÒÔCOµÄȼÉÕÈȵÄÈÈ»¯Ñ§·½³ÌʽΪCO(g)£«1£¯2O2(g)£½CO2(g) ;¡÷H=-497kJ/mol¡£
£¨5£©CO2ÊÇÓɼ«ÐÔ¼üÐγɵĹ²¼Û»¯ºÏÎµç×ÓʽΪ¡£
£¨3£©¿¼²é³£¼ûµÄ·ÅÈÈ·´Ó¦ºÍÎüÈÈ·´Ó¦¡£Ò»°ã½ðÊôºÍË®»òËá·´Ó¦£¬Ëá¼îÖкͷ´Ó¦£¬Ò»ÇÐȼÉÕ£¬´ó¶àÊý»¯ºÏ·´Ó¦ºÍÖû»·´Ó¦£¬»ºÂýÑõ»¯·´Ó¦ÈçÉúÐâµÈÊÇ·ÅÈÈ·´Ó¦¡£´ó¶àÊý·Ö½â·´Ó¦£¬ï§ÑκͼӦ£¬Ì¼¡¢ÇâÆø»òCO×÷»¹Ô¼ÁµÄ·´Ó¦µÈÊÇÎüÈÈ·´Ó¦¡£ËùÒÔ¢Ú¢ÝÊÇÎüÈÈ·´Ó¦¡£
£¨4£©È¼ÉÕÈÈÊÇÖ¸ÔÚÒ»¶¨Ìõ¼þÏ£¬1mol¿ÉȼÎïβÆøȼÉÕÉú³ÉÎȶ¨µÄÑõ»¯Îïʱ·¢³öµÄÈÈÁ¿£¬ËùÒÔCOµÄȼÉÕÈȵÄÈÈ»¯Ñ§·½³ÌʽΪCO(g)£«1£¯2O2(g)£½CO2(g) ;¡÷H=-497kJ/mol¡£
£¨5£©CO2ÊÇÓɼ«ÐÔ¼üÐγɵĹ²¼Û»¯ºÏÎµç×ÓʽΪ¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿