ÌâÄ¿ÄÚÈÝ

¡¾ÌâÄ¿¡¿Ä³»¯Ñ§ÐËȤС×é³ÆÈ¡´¿¾»µÄNa2SO3 ¡¤7H20 a¿Ë£¬¸ô¾ø¿ÕÆø¼ÓÇ¿ÈÈÖÁºãÖØ£¬¾­¹ý·ÖÎöÓë¼ÆË㣬µÃµ½µÄ¹ÌÌåÖÊÁ¿ÓëÈ«²¿×ª»¯ÎªÑÇÁòËáÄƹÌÌåµÄ¼ÆËãÖµÒ»Ö£¬µ«¹ÌÌåÔÚË®ÖÐÈܽâºó²âµÄpHÖµ±ÈÀíÂÛ¼ÆËãÖµ£¨ÏàͬŨ¶ÈNa2SO3ÈÜÒºµÄpH£©´óºÜ¶à¡£ÏÂÁÐ˵·¨²»ÕýÈ·µÄÊÇ

A. Á¬ÐøÁ½´Î³ÆÁ¿Ç¿ÈÈÇ°ºó¹ÌÌåµÄÖÊÁ¿£¬ÈçÖÊÁ¿²îСÓÚ0.1g£¬¼´¿ÉÅжϹÌÌåÒѾ­ºãÖØ

B. ²úÉúÉÏÊöì¶ÜµÄ¿ÉÄܽâÊÍ£º4Na2SO3 3Na2SO4 £« Na2S

C. ¹ÌÌå²úÎïÖмÓÈëÏ¡ÑÎËá¿ÉÄÜÓе­»ÆÉ«³Áµí²úÉú

D. ¼ÓÈëBaCl2ÈÜÒº£¬³öÏÖ°×É«³Áµí£¬ÔòÄÜÈ·¶¨²úÎïÖÐÓÐNa2SO4

¡¾´ð°¸¡¿D

¡¾½âÎö¡¿A¡¢Á¬ÐøÁ½´Î³ÆÁ¿Ç¿ÈÈÇ°ºó¹ÌÌåµÄÖÊÁ¿£¬ÈçÖÊÁ¿²îСÓÚ0.1g£¬¼´¿ÉÅжϹÌÌåÒѾ­ºãÖØ£¬¹ÊAÕýÈ·£»B¡¢ÓÉÓÚNa2SO3¼È¾ßÓÐÑõ»¯ÐÔÓÖ¾ßÓл¹Ô­ÐÔ£¬Na2SO3¼ÓÈȺó·¢ÉúÁËÆ绯·´Ó¦£¬ÁòÔªËØ»¯ºÏ¼Û´Ó+4¼Û±ä»¯Îª-2¼ÛºÍ+6¼Û£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º4Na2SO3=Na2S+3Na2SO4£¬¹ÊBÕýÈ·£»C¡¢¹ÌÌåÖпÉÄÜ»¹ÓÐNa2SO3£¬Na2SO3ÓëNa2SÔÚËáÐÔÌõ¼þÏ¿ÉÒÔ¹éÖз´Ó¦Éú³ÉÁòµ¥ÖÊ£¬ËùÒÔ¹ÌÌå²úÎïÖмÓÈëÏ¡ÑÎËá¿ÉÄÜÓе­»ÆÉ«³Áµí²úÉú£¬¹ÊCÕýÈ·£»D¡¢¹ÌÌåÖпÉÄÜ»¹ÓÐNa2SO3£¬¼ÓÈëBaCl2ÈÜÒº£¬³öÏÖ°×É«³Áµí£¬Ôò²»ÄÜÈ·¶¨²úÎïÖÐÓÐNa2SO4£¬¹ÊD´íÎó£»¹ÊÑ¡D¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø