ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿£¨1£©4.9 g H2SO4º¬________________¸öH2SO4·Ö×Ó£¬ÄܺÍ__________mol NaOHÍêÈ«·´Ó¦¡£
£¨2£©º¬ÓÐÏà̼ͬÔ×ÓÊýµÄCOºÍCO2£¬ÆäÖÊÁ¿±ÈΪ________________¡£
£¨3£©ÔÚͬÎÂͬѹÏ£¬µÈÖÊÁ¿µÄCOºÍNO£¬ÆäÌå»ýÖ®±ÈΪ___________¡£
£¨4£©±ê×¼×´¿öÏÂÓТÙ44.8 L CH4£¬¢Ú9.03¡Á1023¸öNH3·Ö×Ó£¬¢Û85 g H2SÈýÖÖÆøÌ壬¶ÔÕâÈýÖÖÆøÌåµÄÎïÖʵÄÁ¿´Ó´óµ½Ð¡µÄ˳ÐòÊÇ________________ (ÌîÐòºÅ)¡£
£¨5£©ÔÚÒ»¶¨µÄζȺÍѹǿÏ£¬1Ìå»ýÆøÌåX2¸ú3Ìå»ýÆøÌåY2»¯ºÏÉú³É2Ìå»ý»¯ºÏÎïC£¬Ôò¸Ã»¯ºÏÎïµÄ»¯Ñ§Ê½ÊÇ____________¡£
¡¾´ð°¸¡¿3.01¡Á1022 (»ò0.05NA) 0.1 7¡Ã11 15¡Ã14 ¢Û¡¢¢Ù¡¢¢Ú XY3 (»òY3X)
¡¾½âÎö¡¿
£¨1£©4.9 g H2SO4µÄÎïÖʵÄÁ¿Îª4.9g¡Â98g/mol=0.05mol£¬Ôòº¬ÓÐÁòËá·Ö×Ó¸öÊýΪ0.05 NA£¬ÓÉ·´Ó¦2NaOH+H2SO4=Na2SO4+2H2O£¬¿ÉÖªÏûºÄNaOHµÄÎïÖʵÄÁ¿Îª0.05mol¡Á2=0.1mol£¬¹Ê´ð°¸Îª£º3.01¡Á1022 (»ò0.05NA)¡¢0.1£»
£¨2£©º¬ÓÐÏà̼ͬÔ×ÓÊýµÄCOºÍCO2£¬ÆäÎïÖʵÄÁ¿ÏàµÈ£¬ÔòÆäÖÊÁ¿±ÈΪ28£º44=7:11£¬¹Ê´ð°¸Îª7:11£»
£¨3£©ÔÚͬÎÂͬѹÏ£¬µÈÖÊÁ¿µÄCOºÍNO£¬ÆäÎïÖʵÄÁ¿Ö®±ÈΪ=15:14£¬ÆäÌå»ýÖ®±ÈµÈÓÚÆäÎïÖʵÄÁ¿Ö®±È£¬¹Ê´ð°¸Îª15:14£»
£¨4£©±ê×¼×´¿öÏ¢Ù44.8 L CH4£¬¢Ú9.03¡Á1023¸öNH3·Ö×Ó£¬¢Û85 g H2SÈýÖÖÆøÌ壬ÕâÈýÖÖÆøÌåµÄÎïÖʵÄÁ¿·Ö±ðΪ=2mol¡¢
=1.5mol¡¢
=2.5mol£¬¹Ê´ð°¸Îª£º¢Û¡¢¢Ù¡¢¢Ú£»
£¨5£©¸ù¾Ý°¢·ü¼ÓµÂÂÞ¶¨ÂÉ£¬ÆøÌåµÄÌå»ýÖ®±ÈµÈÓÚÎïÖʵÄÁ¿Ö®±È£¬µÈÓÚ»¯Ñ§·½³ÌʽµÄ¼ÆÁ¿ÊýÖ®±È£¬¿ÉµÃ£ºX2+3Y2=2C£¬¸ù¾Ý»¯Ñ§·´Ó¦Ç°ºóÔ×ÓÖÖÀàºÍÊýÄ¿ÏàµÈ£¬¿ÉµÃÉú³ÉÎï·Ö×Óº¬1¸öXÔ×Ó£¬3¸öYÔ×Ó£¬»¯Ñ§Ê½ÎªXY3£¬¹Ê´ð°¸Îª£ºXY3 (»òY3X)¡£

¡¾ÌâÄ¿¡¿ÂÈ»¯ÑÇí¿£¨SOCl2£©ÊÇÒ»ÖÖҺ̬»¯ºÏÎ·ÐµãΪ77¡æ£¬ÔÚÅ©Ò©¡¢ÖÆÒ©ÐÐÒµÖÐÓÃ;¹ã·º£®SOCl2ÓöË®¾çÁÒ·´Ó¦£¬ÒºÃæÉϲúÉú°×Îí£¬²¢´øÓд̼¤ÐÔÆøζµÄÆøÌå²úÉú£®ÊµÑéÊҺϳÉÔÀí£ºSO2+Cl2+SCl2¨T2SOCl2£¬²¿·Ö×°ÖÃÈçͼËùʾ£¬»Ø´ðÒÔÏÂÎÊÌ⣺
£¨1£©ÒÇÆ÷cµÄÃû³ÆÊÇ________
£¨2£©ÊµÑéÊÒÖÆCl2µÄ»¯Ñ§·½³ÌʽΪ________________________
£¨3£©ÏÂÁÐËÄÖÖÖƱ¸ SO2µÄ·½°¸ÖÐ×î¼ÑÑ¡ÔñÊÇ_______
·½°¸ | ¼× | ÒÒ | ±û | ¶¡ |
·¢Éú×°Öà | ||||
ËùÑ¡ÊÔ¼Á |
|
£¨4£©dµÄÐéÏß¿òÄÚÒþº¬Á½¸ö×°Ö㬰´ÆøÁ÷·½Ïò˳ÐòÕâÁ½¸ö×°ÖõÄ×÷Ó÷ֱðÊÇ_______________¡£
£¨5£©ÊµÑé½áÊøºó,½«Èý¾±ÉÕÆ¿ÖлìºÏÎï·ÖÀ뿪µÄ·½·¨ÊÇ _________(ÒÑÖªSCl2µÄ·ÐµãΪ50¡æ)
£¨6£©ÊÔÉè¼ÆÒ»¸ö¼òµ¥ÊµÑé·½°¸ÑéÖ¤H2SO3ËáÐÔÇ¿ÓÚH2CO3£¨¼òҪ˵Ã÷ʵÑé²½Öè¡¢ÏÖÏóºÍ½áÂÛ£©____________________________________________¡£ÒÇÆ÷×ÔÑ¡¡£
ÏÞÑ¡µÄÊÔ¼Á£ºSO2¡¢NaHCO3¡¢ËáÐÔKMnO4¡¢NaHSO3¡¢ÕôÁóË®¡¢±¥ºÍʯ»ÒË®¡¢Æ·ºìÈÜÒº¡¢pHÊÔÖ½¡£
£¨7£©Îª²â¶¨Ä³¹¤³§µÄ¿ÕÆøÖжþÑõ»¯Áòº¬Á¿£¬Ì½¾¿Ð¡×é½øÐÐÈçÏÂʵÑ飺ÔÚÊÔ¹ÜÖмÓÈëÒ»¶¨Á¿µÄº¬µâ£¨I2£©0.635mgµÄµâÈÜÒº£¬ÔÙ¼ÓÈë2~3µÎµí·ÛÈÜÒº£¬ÏòÊÔ¹ÜÖÐͨÈë¿ÕÆø£¬µ±ÈÜÒºÓÉÀ¶É«±äΪÎÞɫʱǡºÃÍêÈ«·´Ó¦£¬¹²ÓÃÈ¥¿ÕÆøÌå»ýΪ500L¡£Çëͨ¹ý¼ÆËãÅжϳö´Ë¿ÕÆøÖжþÑõ»¯ÁòµÄŨ¶È_____mg/m3¡££¨»¯Ñ§·½³ÌʽΪ£ºSO2+I2+2H2O=H2SO4+2HI£©