ÌâÄ¿ÄÚÈÝ
£¨2010?¾²°²Çøһģ£©Èçͼ1ËùʾµÄµç·ÖУ¬µçÔ´µçѹΪ18·üÇÒ±£³Ö²»±ä£¬µç×èR1µÄ×èֵΪ25Å·£¬»¬¶¯±ä×èÆ÷R2ÉϱêÓС°50¦¸ 2A¡±×ÖÑù£®±ÕºÏµç¼üSºó£¬µçѹ±íʾÊýΪ6·ü£®
£¨1£©Ç󣺵ç×èR1Á½¶ËµÄµçѹU1ÒÔ¼°Í¨¹ýR1µÄµçÁ÷I1£®
£¨2£©Ç󣺱ä×èÆ÷R2Á¬Èëµç·µÄ×èÖµ£®
£¨3£©²»¸Ä±äµç±íµÄÁ¿³Ì£¬Òƶ¯»¬¶¯±ä×èÆ÷µÄ»¬Æ¬P£¬
¢ÙÈôÁ½µç±íµÄÖ¸ÕëÆ«ÀëÁã¿Ì¶ÈÏߵĽǶÈÇ¡ºÃÏàµÈ£¬Èçͼ2Ëùʾ£¬Ç󣺱ä×èÆ÷R2Á¬Èëµç·µÄ×èÖµ£®
¢ÚÈôÆäÖÐijһµç±íµÄÖ¸ÕëÇ¡ºÃÂúÆ«£¬Çó£ºÁíÒ»¸öµç±íµÄʾÊý£®
£¨1£©Ç󣺵ç×èR1Á½¶ËµÄµçѹU1ÒÔ¼°Í¨¹ýR1µÄµçÁ÷I1£®
£¨2£©Ç󣺱ä×èÆ÷R2Á¬Èëµç·µÄ×èÖµ£®
£¨3£©²»¸Ä±äµç±íµÄÁ¿³Ì£¬Òƶ¯»¬¶¯±ä×èÆ÷µÄ»¬Æ¬P£¬
¢ÙÈôÁ½µç±íµÄÖ¸ÕëÆ«ÀëÁã¿Ì¶ÈÏߵĽǶÈÇ¡ºÃÏàµÈ£¬Èçͼ2Ëùʾ£¬Ç󣺱ä×èÆ÷R2Á¬Èëµç·µÄ×èÖµ£®
¢ÚÈôÆäÖÐijһµç±íµÄÖ¸ÕëÇ¡ºÃÂúÆ«£¬Çó£ºÁíÒ»¸öµç±íµÄʾÊý£®
·ÖÎö£º£¨1£©ÒÑÖªÁ½µç×è´®Áª£¬µçѹ±í²âÁ¿»¬¶¯±ä×èÆ÷Á½¶ËµÄµçѹ£¬´Ó¶ø¿ÉÒÔÇó³öµç×èR1Á½¶ËµÄµçѹ£»¸ù¾ÝÅ·Ä·¶¨ÂÉÇó³öͨ¹ýR1µÄµçÁ÷£»
£¨2£©ÒÑ֪ͨ¹ýµÄµçÁ÷ºÍÁ½¶ËµÄµçѹ£¬¸ù¾ÝÅ·Ä·¶¨ÂÉ¿ÉÇóµç×èµÄ´óС£»
£¨3£©ÒÑÖªµçѹ±íºÍµçÁ÷±íµÄ·Ö¶ÈÖµ£¬¸ù¾ÝÅ·Ä·¶¨ÂÉ¿ÉÇóµç×èµÄ´óС£»¸ù¾ÝµçÁ÷±íºÍµçѹ±íµÄʾÊý¿ÉÖª½á¹û£®
£¨2£©ÒÑ֪ͨ¹ýµÄµçÁ÷ºÍÁ½¶ËµÄµçѹ£¬¸ù¾ÝÅ·Ä·¶¨ÂÉ¿ÉÇóµç×èµÄ´óС£»
£¨3£©ÒÑÖªµçѹ±íºÍµçÁ÷±íµÄ·Ö¶ÈÖµ£¬¸ù¾ÝÅ·Ä·¶¨ÂÉ¿ÉÇóµç×èµÄ´óС£»¸ù¾ÝµçÁ÷±íºÍµçѹ±íµÄʾÊý¿ÉÖª½á¹û£®
½â´ð£º½â£º£¨1£©µç×èR1Á½¶ËµÄµçѹU1=U-U2=18V-6V=12V£»
I1=
=
=0.48A£»
´ð£ºµç×èR1Á½¶ËµÄµçѹΪ12V£»Í¨¹ýR1µÄµçÁ÷I1Ϊ0.48A£»
£¨2£©±ä×èÆ÷R2Á¬Èëµç·µÄ×èÖµR2=
=
=12.5¦¸£»
´ð£º±ä×èÆ÷R2Á¬Èëµç·µÄ×èֵΪ12.5¦¸£»
£¨3£©¢Ù±ä×èÆ÷R2Á¬Èëµç·µÄ×èÖµR2=
=
=25¦¸£»
¢Úµ±µçÁ÷±íʾÊýI'=0.6°²Ê±£¬µçѹ±íʾÊýΪ3·ü£®
I1=
U1 |
R1 |
12V |
25¦¸ |
´ð£ºµç×èR1Á½¶ËµÄµçѹΪ12V£»Í¨¹ýR1µÄµçÁ÷I1Ϊ0.48A£»
£¨2£©±ä×èÆ÷R2Á¬Èëµç·µÄ×èÖµR2=
U2 |
I2 |
6V |
0.48A |
´ð£º±ä×èÆ÷R2Á¬Èëµç·µÄ×èֵΪ12.5¦¸£»
£¨3£©¢Ù±ä×èÆ÷R2Á¬Èëµç·µÄ×èÖµR2=
U2¡ä |
I2¡ä |
0.5V |
0.02A |
¢Úµ±µçÁ÷±íʾÊýI'=0.6°²Ê±£¬µçѹ±íʾÊýΪ3·ü£®
µãÆÀ£º±¾Ì⿼²éµçѹ¡¢µçÁ÷¡¢µç×èµÄ¼ÆË㣬¹Ø¼üÊǹ«Ê½¼°Æä±äÐεÄÁé»îÔËÓã¬ÄѵãÊÇÖªµÀµçÁ÷±íºÍµçѹ±íµÄ·Ö¶ÈÖµÒÔ¼°Á¿³Ì£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿