题目内容
(1)计算:2-1+(-1)2013+(2013-π)0-sin30°
(2)化简:(1+
)÷
.
(2)化简:(1+
x2-1 |
x2-2x+1 |
1 |
x-1 |
(1)原式=
-1+1-
=0;
(2)原式=
•(x-1)
=
•(x-1)
=2x.
1 |
2 |
1 |
2 |
(2)原式=
2x2-2x |
(x-1)2 |
=
2x(x-1) |
(x-1)2 |
=2x.
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