题目内容
3 |
1+a |
6 |
1-a |
12 |
a2-1 |
原式=
+
-
=
=
=
.
3(a-1) |
(a+1)(a-1) |
6(a+1) |
(a+1)(a-1) |
12 |
(a+1)(a-1) |
=
3(a-1)+6(a+1)-12 |
(a+1)(a-1) |
=
9(a-1) |
(a+1)(a-1) |
=
9 |
a+1 |
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