题目内容
如图,已知∠ACB=90°,∠DAB=70°,AC平分∠DAB,∠1=35°.
①求∠B的度数;
②求证:AB∥CD.

①求∠B的度数;
②求证:AB∥CD.

①∵∠DAB=70°,AC平分∠DAB,
∴∠2=
∠DAB=
×70°=35°,
∵∠ACB=90°,
∴∠B=90°-∠2=90°-35°=55°;
②证明:∵∠1=35°,∠2=35°,
∴∠1=∠2,
∴AB∥CD.

∴∠2=
1 |
2 |
1 |
2 |
∵∠ACB=90°,
∴∠B=90°-∠2=90°-35°=55°;
②证明:∵∠1=35°,∠2=35°,
∴∠1=∠2,
∴AB∥CD.


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